At 3:30 P.M. the angle between the hands of a
clock is

Answers

Answer 1

Answer: Well, the "hour" hand is 3.5*30=105 degrees from the "12" marking (30 degrees per hour), while the "minute" hand is 30*6=180 degrees from the "12" marking (6 degs per minute). The difference, that is, 75 degrees, is our angle. The other difference would have been over 180, which is not important for us.

Answer 2

Answer:

Answer:

At 3:30 , the minute hand is at number 6. At 3:00 the hour hand was at number 3. Now it has moved 15 degree. Hence the angle between the two is (90 -15) = 75 degree.

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Literal Equations:
C=2πr solve for r

Answers

$\sf C = 2\pi r\n\n Divide~both~sides~by~2\pi\n\n\boxed{\bf{r = (C)/(2\pi)}}$

Hope this helped! If you have any other questions or would like further explanation just let me know!! :)

What are the vertex, focus, and directrix of the parabola with equation y = x^2 – 10x + 33?

Answers

Answer:

Vertex:(5,8)

Focus:(5,8.25)

Directrix: y=7.75

Step-by-step explanation:

For the equation of the parabola in the form:

(x - h)² = 4p(y - k), where p≠ 0

The vertex of this parabola is at (h, k).

The focus is at (h, k + p).

The directrix is the line y = k - p.

Converting the equation y=x²-10x+33 in the above form

y=x²-10x+25+8

y=(x-5)²+8

(x-5)²=(y-8)

On comparing this equation with the above equation, we see that

h=5 k=8 and 4p=1

or p=1/4

Vertex=(5,8)

Focus=(5,8+1/4)

=(5,8.25)

Directrix: y=8-1/4

y= 7.75

opens up so
(x-h)^2=4P(y-k)
complete the square with the x term
take 1/2 of -10 and square it and add that to both sides

y+25=x^2-10x+25+33
factor perfect square
y+25=(x-5)^2+33
minus 33 both sides
y-8=(x-5)^2
force factor out a 4
4(1/4)(y-8)=(x-5)^2
(x-5)^2=4(1/4)(y-8)
vertex is (5,8)

distance from directix is P or 1/4 or 0.25
since opens up, directix is ycoordinate-0.25 aka y=7.75 is directix
focus=(5,8+0.25)=(5,8.25)

vertex=(5,8)
directix: y=7.75
focus: (5,8.25)

Tiffany pays $40 for 160 minutes of talk time on her cell phone. Hpw how many minutes of talk time does she get per dollar?

Answers

the answer is ............................4

The numbers on a football field indicate 10 yard increments. You walk around the perimeter of a football field between the pylons. You walk a distance of 306 and 2/3 yards. Find the area and perimeter of the indicated regions. Write your answers as mixed numbers, if necessary. One end zone

Answers

Answer: 126.67 is the perimeter walked

Step-by-step explanation:

Given data:

Distance walked on the field = 306 2/3 yards.

Increments on the field = 10 yards.

Solution:

We know a pitch has 4 sides let make it A, B,C,D = 306.67yards.

each has an increment of 10

= 10 x 10 + 10 x 10 = 200

Therefore

= 306.67 yards – 200

= 106.67 yards.

For both end zones Perimeter

= 106.67 + 10 + 10

= 126.67 yards

Final answer:

The area of the end zone is 6400 square yards and the perimeter is 326 and 2/3 yards.

Explanation:

To find the area and perimeter of the end zone of a football field, we need to know the dimensions of the end zone. If the end zone has a width of 53 and 1/3 yards, we multiply the width by the length of the field, which is 120 yards, to find the area. So the area of the end zone is (53 and 1/3) x 120 = 6400 square yards. The perimeter is found by adding the dimensions together, so the perimeter of the end zone is (2 x 53 and 1/3) + (2 x 120) = 326 and 2/3 yards.

Learn more about Area and perimeter of a football field end zone here:

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Benito had 10 days of vacation. he spent 1/5 of his vacation fishing. he spent 30% of his vacation at soccer camp. he spent the rest of the time at the beach. what percent of his vacation did benito spend at the beach?