MATHEMATICS MIDDLE SCHOOL

For the data set: 12, 8, 6, 6, 9, 8, 7, 11, 6, “6” is the value for which measure? Select two answers. A. IQR
B. range
C. mode
D. median
E. mean

Answers

Answer 1
Answer:

Answer:

B, C

Step-by-step explanation:

12 minus 6 = 6 this is range the max minus the minimum

the number that appears the most: 6
Answer 2
Answer:

Answer:

B and C, Range and Mode.

Step-by-step explanation:

6, 6, 6, 7, 8, 8, 9, 11, 12

IQR interquartile range: 10 - 6 = 4

Range: 12 - 6 = 6

Mode: 6

Median: 8

Mean: 6 + 6 + 6 + 7 + 8 + 8 + 9 + 11 + 12 = 73/9 =  8.1

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Is 9/16 less than or greater than 5/8

Answers

To find that, you multiply 5/8 by 2/2 because it makes the denominator 16, which would get you 10/16. Compare the two: 9/16 is less than 10/16.

Data Set 1 has a mean of 120 and a MAD of 4. Data Set 2 has a mean of 132 and a MAD of 3.What can you conclude about the two distributions?

Choose exactly two answers that are correct.

A.
The means-to-MAD ratio is 3.

B.
The means-to-MAD ratio is 4.

C.
The distributions are somewhat similar.

D.
The distributions are different.

Answers

The answer is A and D. I know cause I've done the test before 

Solve

x2 + 6x + 6 = 0

Answers

Answer:

The solution of x^2 + 6x + 6 is x = -1.2679 or -4.7320

Solution:

A two degree polynomial equation is given in the question.

We have been asked to solve it to find the value of ‘x’.

The given equation is:

x^(2)+6 x+6=0

There are two ways to solve this equation.

We can either factorise it or use the quadratic equation formula. For factorising it, it has to satisfy certain conditions.

The condition is b^2 - 4ac should be a perfect square otherwise the equation is not factorable.

a=1,b=6,c=6

On substituting the values of a,b and c, we get:

Which is not a perfect square.

Hence we have to use the quadratic equation is

x=\frac{-b \pm \sqrt{b^(2)-4 a c}}{2 a}

By substituting the values of a,b and in the quadratic equations. We get;

\begin{array}{l}{x=\frac{-6 \pm \sqrt{6^(2)-4 * 1 * 6}}{2 * 1}} \n\n {x=(-6 \pm √(12))/(2 * 1)}\end{array}

The two roots of x are:

\begin{aligned} x &=(-6-√(12))/(2 * 1) \n\n x &=(-6+√(12))/(2 * 1) \end{aligned}

On solving both the equations we will get the roots of the given equation, which are:

x = -1.2679 or -4.7320

Answer:

-1.2679 or -4.7320

Step-by-step explanation:

W -7 7/12 equals 5 + 5/12 what is w show work

Answers

w is 9/45. Ask google for more help

How do you solve this math question?

Answers

For the 6 friends to eat a half meat pie the will eat 3 and they will be 2 more, the 6 friends should cut each one into 3 half's.
Uea shes correct :) have s great day

Which compound inequality could this graph be the solution of?

Answers

Answer:

B. 2x + 3 ≥ 11 or 4x - 7 ≤ 1

Step-by-step explanation:

Given compound inequality,

In option A,

2x + 3 ≥ 11 and 4x - 7 ≤ 1

⇒ 2x ≥ 8 and 4x ≤ 8

⇒ x ≥ 4 and x ≤ 2

\implies [4,\infty)\cap (-\infty, 2]

=\phi

2x + 3 ≥ 11 and 4x - 7 ≤ 1 can not be the correct inequality,

In option B,

2x + 3 ≥ 11 or 4x - 7 ≤ 1

⇒ 2x ≥ 8 or 4x ≤ 8

⇒ x ≥ 4 or x ≤ 2

\implies [4,\infty)\cup (-\infty, 2]

Which is shown in the given graph,

Thus, 2x + 3 ≥ 11 or 4x - 7 ≤ 1 is the correct compound inequality,

In option C,

2x + 3 > 11 or 4x - 7 < 1

⇒ 2x > 8 or 4x < 8

⇒ x > 4 or x < 2

\implies (4,\infty)\cup (-\infty, 2)

So, which is not shown in the graph,

2x + 3 > 11 or 4x - 7 < 1 can not be the correct compound inequality,

In option D,

2x + 3 ≥ 11 or 4x - 7 ≥ 1

⇒ 2x ≥ 8 or 4x  ≥ 8

⇒ x ≥ 4 or x  ≥ 2

\implies [4,\infty)

Which is not shown in the graph,

2x + 3 ≥ 11 or 4x - 7 ≥ 1 is not the correct compound inequality.

B.. 4 is less than or equal to x, 2 is greater or equal to x
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