Find the least common multiple of 7 3 2

Answers

Answer 1

Answer: The answer should be 42

Related Questions

Miguel made 6 identical necklaces each, having beads and a pendant. The total cost of the beads and the pendant for all 6 necklaces was $29.40. If the beads cost a total of $19.80, how much did each pendant cost?
Three vertices of a rectangle are given. Find the coordinates of the fourth vertex. (2, 5), (6, 1), (4, –1)A.(0, 2)B.(0, 3)C.(1, 3)D.(1, 4)
Solve the following equation for "h": A=bh/2
Pls give an explanation
Find the mode.19, 1, 17, 19, 3, 20, 5, 2A. 10.75B. 11C. 19D. 20

- 5+ (-4) = ?
Can you guys please help me

Answers

-9 because a negative plus a negative is a negative so -5+-4 or -5-4 is -9

Answer:

-9 because a negative plus a negative is a negative so -5+-4 or -5-4 is -9

Step-by-step explanation:

What two numbers add to 4 and when multiplied together equal 5

Answers

Answer:

$\large\text{no real solution}\n\n\text{complex solution}$

$\large\boxed{x=2+i\ and\ y=2-i\ or\ x=2-i\ and\ y=2+i}$

Step-by-step explanation:

$x,\ y-\text{the numbers}\n\nx+y=4\nxy=5\n\nx+y=4\qquad\text{subtract y from both sides}\nx=4-y\n\n\text{substitute it to the second equation}\n\n(4-y)y=5\qquad\text{use distributive property}\n\n4y-y^2=5\n\n-y^2+4y=5\qquad\text{change the signs}\n\ny^2-4y=-5\n\ny^2-2(y)(2)=-5\qquad\text{add}\ 2^2\ \text{to both sides}\n\ny^2-2(y)(2)+2^2=-5+2^2\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2\n\n(y-2)^2=-5+4\n\n(y-2)^2=-1<0\to\boxed{no\ real\ solution}$

$\text{If you need the complex solution, then}\n\n(y-2)^2=-1\to y-2=\pm√(-1)\n\ny-2=-i\ \vee\ y-2=i\qquad\text{add 2 to both sides}\n\n\boxed{y=2-i\ \vee\ y=2+i}\n\n\text{Put the values of y to the first equation:}\n\nx=4-(2-i)\ \vee\ x=4-(2+i)\n\nx=4-2+i\ \vee\ x=4-2-i\n\n\boxed{x=2+i\ \vee\ x=2-i}$

What is the slope of the line through (1, 9) and (–3, 16)?

Answers

For this case we have that by definition, the slope of a line is given by:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}$

Where:

$(x_ {1}, y_ {1})$ and $(x_ {2}, y_ {2})$ are two points through which the line passes.

We have as data that:

$(x_ {1}, y_ {1}) :( 1,9)\n(x_ {2}, y_ {2}): (- 3,16)$

Substituting we have:

$m = \frac {16-9} {- 3-1} = \frac {7} {- 4} = - \frac {7} {4}$

Thus, the slope of the line is $- \frac {7} {4}$

Answer:

$m = - \frac {7} {4}$

Answer:

-7/4.

Step-by-step explanation:

This is the difference in the y coordinates / corresponding difference in the x coordinates.

here it is (16 - 9) / (-3-1)

= 7 / -4

= -7/4.

The perimeter of a rectangular piece of land is 280m. People divide the land into two small pieces: a square, a rectangle. The total perimeter of the two small plots is 390m. Calculate the area of the original piece of land.

Answers

Step-by-step explanation:

Length of the Rectangular piece of the land = 12 + 1/2 m = 25/2 m

Breadth of the Rectangular piece of the land = 5 + 1/5 m = 26/5 m

If 4 small square flower bed of side length 1 m are made at center.

To find: Area of the rectangular land , Perimeter of the rectangle and Area of land left when flower bed are mad.

Perimeter of the rectangle = 2 × ( length + breadth )

= 2 × ( 25/2 + 26/5 )

= 2 × ( 177/10 )

= 177/5 m

= 35.4 m

Area of the rectangular land = Length × Breadth

= 25/2 × 26/5

= 5 × 13

= 65 m²

Area of a flower bed = side × side = 1 × 1 = 1 m²

Area of 4 flower bed= 4 × 1 = 4 m²

Area left in the land = 65 - 4 = 61 m²

Therefore, Perimeter of the land is 35.4 m

Area of land is 65 m²

Area of the land left after flower beds is 61 m²

A coin of questionable fairness is tossed 10 times per set of trials for two sets of trials. The outcomes are THTHTHTHHT and TTTHTTHTTH (T = Tails; H = Heads). Which model can you most likely rule out on the basis of this simulation?A.The probability of heads is 40%.
B. The probability of heads is 30%.
C. The probability of heads is 35%
D. The probability of heads is 70%