Answer:
52
Step-by-step explanation:
Let x represent the smallest of the three numbers. Then the other two are (x+2) and (x+4). Their sum is ...
x + (x+2) +(x+4) = 162
3x = 156 . . . . . . . . . . . .subtract 6
x = 156/3 = 52
The smallest of the three numbers is 52.
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I like to work problems like this by considering the average number. Here, the average of the three numbers is 162/3 = 54, the middle number of the three. Then the smallest of the three consecutive even numbers is 2 less, or 52.
Answer: Mode
For instance, the mode of the set {1,2,3,5,4,4,6,4,8,4,4,7,4} is 4 because it shows up the most compared to the other values. Making a frequency table can be helpful to determine the mode.
In statistics, the most recurring number in a data set is identified as the mode. It is calculated by identifying the frequency of each number in the data set. A data set may have one mode, no mode, or more than one mode.
The number that appears most often in a given set of data is called the mode. The mode is an important concept of statistics and helps in identifying the most frequent value in a data set. There can be more than one mode for a data set if they have the same frequency, which is the number of times a value appears in the data set. For example, in a data set of [2, 3, 3, 5, 5], both 3 and 5 are modes because they appeared twice each, which is more frequently than any other number in the data.
In some cases, the data set might have no mode when no number repeats or two modes, which will then be referred to as bimodal.
Learn more about Mode here:
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Answer:
10 for $4.25 has a better value than 2 bunches of 5 for $2.25 each.
Step-by-step explanation:
3 oranges = $1.35
y × 3 = 1 × 1.35
3y = 1.35
3y ÷ 3 = 1.35 ÷ 3
y = $0.45
4 oranges = $1.80
y × 4 = 1 × 1.8
4y = 1.8
4y ÷ 4 = 1.8 ÷ 4
y = $0.45
5 oranges = $2.25
y × 5 = 1 × 2.25
5y = 2.25
5y ÷ 5 = 2.25 ÷ 5
y = $0.45
y × 1 = 0.45 × 10
y = $4.50
y × 10 = 1 × 4.25
10y = 4.25
10y ÷ 10 = 4.25 ÷ 10
y = 0.425
$0.425 ≈ $0.43
Answer:
× B + A
Step-by-step explanation:
Given equations are x + y = 12 ---------(A)
and equation y - x = 6 -------------(B)
To eliminate the variable x we will multiply equation A by
and add it to equation B.
In other words, the expression that we will adopt to eliminate the variable x will be × B + A