Answer:
The different variable in C is 21213316700.
Explanation:
Given value:
Total value = letters + underscore value
Total value = 52 + 1
Total value =53
choice for first character = 53 letters +10 digits
first character = 63
choice for remaining characters
So,
Variable number With one 1 character = 53
Variable number With 2 character = 53 × 63
Variable number With 3 character = 53 × 63²
Variable number With 4 character = 53 × 63³
.
.
.
Variable number With 7 character =
Total difference variable = 53 + 53 × 63+ 53 × 63²+ 53 × 63³+....+
Total difference variable = 53(1 + 63 + 63²+ 63³+ .... + )
Formula:
Total difference variable
Answer:
The answer is "It Specifies the built-in chip in the module header".
Explanation:
The hardware simulator is also an instrument about which the device physical models could be constructed, in the mainframe, which includes a console, a power supply, or multiple sockets for plugging regular modules.
Answer:
D. Refrigerants
Explanation:
In the United States of America, the agency which was established by US Congress and saddled with the responsibility of overseeing all aspects of pollution, environmental clean up, pesticide use, contamination, and hazardous waste spills is the Environmental Protection Agency (EPA). Also, EPA research solutions, policy development, and enforcement of regulations through the resource Conservation and Recovery Act .
The Clean Air Act Amendments of 1990 prohibit service-related releases of all refrigerants such as R-12 and R-134a. This ban became effective on the 1st of January, 1993.
Refrigerants refers to any chemical substance that undergoes a phase change (liquid and gas) so as to enable the cooling and freezing of materials. They are typically used in air conditioners, refrigerators, water dispensers, etc.
The Clean Air Act Amendments of 1990 prohibit service-related releases of all refrigerants. The correct option is D.
Thus, The Environmental Protection Agency (EPA), which was formed by US Congress, is the organization tasked with regulating all facets of pollution, environmental cleanup, pesticide use, contamination, and hazardous material spills.
All refrigerants, including R-12 and R-134a, are forbidden from being released during service under the Clean Air Act Amendments of 1990. On January 1st, 1993, this ban came into force.
Any chemical compound that transforms into a different phase (liquid or gas) to allow for the cooling or freezing of items is referred to as a refrigerant. They are frequently found in refrigerators, water dispensers, air conditioners, and other appliances.
Thus, The Clean Air Act Amendments of 1990 prohibit service-related releases of all refrigerants. The correct option is D.
Learn more about Clean air act, refer to the link:
#SPJ3
Answer:
A metropolitan area network is one step up from a local area network in geographical range.
Explanation:
A metropolitan area network is one step up from a local area network in geographical range.
A network is a group of devices connected together for communication. Networks can be classified according to the area they cover, A metropolitan area network is smaller than a wide area network but larger than a local area network.
A local area network consist of computers network in a single place. A group of LAN network form a metropolitan network
A metropolitan network is a network across a city or small region. A group of MAN form a wide area network.
Answer:
Here is the C++ program:
#include<iostream> //to use input output functions
#include<iomanip> //to use setprecision
using namespace std; //to identify objects cin cout
int main() { //start of main function
int n1, n2, n3, n4, n5, n6, n7, min, max; // declare variables for 7 numbers, minimum value and maximum value
double sum= 0; //declare variable to hold sum of 7 numbers
double average; //declare variable to hold average of 7 numbers
cout<<"Enter first number: "; //prompts user to enter 1st number
cin>>n1; //reads first number from user
max = n1; //sets the first number to maximum
min=n1; //sets the first number to minimum
cout<<"Enter second number: "; //prompts user to enter 2nd number
cin>>n2; //reads second number from user
if(n2<min){ //if second number is less than min
min=n2; } //sets min to n2
if(n2>max){ //if n2 is greater than max
max = n2; } //sets max to n2
cout<<"Enter third number: "; //prompts user to enter 3rd number
cin>>n3; //reads third number from user
if(n3<min){ //checks if n3 is greater than min
min=n3; } //sets n3 to min
if(n3>max){ //checks if n3 is greater than max
max = n3; } //sets max to n3
cout<<"Enter fourth number: ";//prompts user to enter 4th number
cin>>n4; //reads fourth number from user
if(n4<min){ //if n4 is less than min
min=n4; } //sets min to n4
if(n4>max){ //if n4 is greater than max
max = n4; } //sets max to n4
cout<<"Enter fifth number: "; //prompts user to enter 5th number
cin>>n5; //reads fifth number from user
if(n5<min){ //if n5 is less than min
min=n5; } //sets min to n5
if(n5>max){ //if n5 is greater than max
max = n5; } //sets max to n5
cout<<"Enter sixth number: "; //prompts user to enter 6th number
cin>>n6; //reads sixth number from user
if(n6<min){ // if n6 is less than min
min=n6; } //sets min to n6
if(n6>max){ //if n6 is greater than max
max = n6; } //sets max to n6
cout<<"Enter seventh number: ";//prompts user to enter 7th number
cin>>n7; //reads seventh number from user
if(n7<min){ //if n7 is less than minimum number
min=n7; } //assigns n7 to min
if(n7>max){ //if n7 is greater than the maximum number
max = n7; } //assigns n7 to max
sum = n1+n2+n3+n4+n5+n6+n7; //adds 7 numbers
average = sum/7; //computes average of 7 numbers
cout<<"The average is: "<<fixed<<setprecision(3)<<average<<endl; //displays average value up to show 3 digits below decimal point using setprecision method of iomanip library
cout<<"The maximum number is: "<<max<<endl; //displays maximum number of 7 numbers
cout<<"The minimum number is: "<<min<<endl; //displays miimum number of 7 numbers
return 0; }
Explanation:
The program is well explained in the comments attached to each statement of program. For example if
n1 = 3
n2 = 9
n3 = 7
n4 = 6
n5 = 2
n6 = 5
n7 = 4
When n1 is read using cin then this number is set to max and min as:
min = 9
max = 3
Now when n2 is read, the first if condition checks if n2 is less than min and second if condition checks if n2 is greater than max. As n2 = 9 so it is not less than min so this if condition is false and n2 is greater than max i.e. 3 so this condition is true. So 9 is assigned to max.
min = 9
max = 9
Now when n3 is read the values of min and max become:
min = 7
max = 9
Now when n4 is read the values of min and max become:
min = 6
max = 9
Now when n5 is read the values of min and max become:
min = 2
max = 9
Now when n6 is read the values of min and max become:
min = 2
max = 9
Now when n7 is read the values of min and max become:
min = 2
max = 9
Now the statement sum = n1+n2+n3+n4+n5+n6+n7;
executes which becomes:
sum = 3 + 9 + 7 + 6 + 2 + 5 + 4
sum = 36.0
Next program control moves to statement:
average = sum/7;
this becomes
average = 36/7
5.142857
Since this is to be displayed up to 3 decimal places so average = 5.143
the complete output of the program is attached.
if (str.indexOf("pea") >= 0)
{
System.out.println("pea");
}
else if (str.indexOf("pear") >= 0)
{
System.out.println("pear");
}
else if (str.indexOf("pearl") >= 0)
{
System.out.println("pearl");
}
II.
if (str.indexOf("pearl") >= 0)
{
System.out.println("pearl");
}
else if (str.indexOf("pear") >= 0)
{
System.out.println("pear");
}
else if (str.indexOf("pea") >= 0)
{
System.out.println("pea");
}
Which of the following best describes the output produced by code segment I and code segment II?
Both code segment I and code segment II produce correct output for all values of str.
Neither code segment I nor code segment II produce correct output for all values of str.
Code segment II produces correct output for all values of str, but code segment I produces correct output only for values of str that contain "pear" but not "pearl".
Code segment II produces correct output for all values of str, but code segment I produces correct output only for values of str that contain "pearl".
Code segment II produces correct output for all values of str, but code segment I produces correct output only for values of str that contain "pea" but not "pear".
Answer:
Code segment II produces correct output for all values of str, but code segment I produces correct output only for values of str that contain "pea" but not "pear".
Explanation:
The main issue with the first code segment is the way how the if else if condition are arranged. The "pea" is checked at the earliest time in the first code segment and therefore so long as there is the "pea" exist in the string (regardless there is pear or pearl exist in the string as well), the if condition will become true and display "pea" to terminal. This is the reason why the code segment 1 only work for the values of str that contain "pea".
Answer:
I am writing Python program.
string = input("Enter a string: ")
print(string.count(' '))
Explanation:
The first statement takes input string from the user.
input() is used to read the input from the user.
The next statement uses count() function to count the number of times the specified object which is space ' ' hereoccurs in the string.
The print() function is used to return the number of times the space occurs in the string entered by the user.
Output:
Enter a string: How are you doing today?
4
The screenshot of program and its output is attached.