Momentum = (mass) x (speed)
Momentum = (12,000 kg) x (40 m/s)
Momentum = (12,000 x 40) kg-m/s
Momentum = 480,000 kg-m/s
Answer:
v = 54 m/s
Explanation:
Given,
The maximum height of the flight of golf ball, h = 150 m
The velocity at height h, u = 0
The velocity of the golf ball right before it hits the ground, v = ?
Using the III equations of motion
v² = u² + 2gh
Substituting the given values in the above equation,
v² = 0 + 2 x 9.8 x 150 m
= 2940
v = 54 m/s
Hence, the speed of the golf ball right before it hits the ground, v = 54 m/s
lateral continuity
B.
horizontal continuity
C.
faunal succession
D.
geological succession