Which phrases can be used to represent the inequality 12 minus 3 x greater-than-or-equal-to 9? Select two options.

Answers

Answer 1
Answer:

Answer:

Twelve less three times a number is at least nine.

Twelve minus the product of three and a number is no smaller than nine.

Step-by-step explanation:

complete question is:

Twelve less than three times a number is greater than or equal to nine.

Twelve less than three times a number is at least nine.

Twelve less three times a number is at least nine.

Twelve minus the product of three and a number is no more than nine.

Twelve minus the product of three and a number is no smaller than nine.

ANSWER:

Twelve less three times a number is at least nine.

The phrase "twelve less three..." means that the "three times a number" is being subtracted from twelve. So, it has to be at least nine.

Twelve minus the product of three and a number is no smaller than nine.

Even the least number you suppose is 1 we'll get 9

e.g: 12-3(1)=9. Therefore, this statement also represent the inequality

Answer 2
Answer:

Check attachment for the remaining part of the questions.

Answer:

The correct options are:

C. Twelve less three times a number is at least nine.

F. Twelve minus the product of three and a number is no smaller that nine.

Step-by-step explanation:

Given 12 - 3x ≥ 9,

we want to check which phrase from the options can be used to represent the inequality.

12 - 3x: This means the product of 3 and a number is subtracted from 12.

≥: This is the "Greater or equal to" symbol. It is used to show that the quantity on the left hand side of the symbol is at least, the exact quantity on the right. It means the quantity on the right hand side can be equal, or greater, but can never be smaller the quantity on the left hand side.

So, the statement means

When 3 is multiplied my a number, and then the result is subtracted from 12, what we have is at least 9.

The only statements that corresponds to this from the options are:

1. Twelve less three times a number is at least nine.

2. Twelve minus the product of three and a number is no smaller that nine.


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Which equation is a function?O A. X = -2
O B. Y= 2x – 9
O C. y² = x - 2
O D. x² + y² = 9

Answers

the answer is B -- no matter the x factor y should be single

Lori ran 4.63 miles last weekend and 5.876 miles this weekend. How many miles did she run in all?

Answers

Answer:

10.506

Step-by-step explanation:

its just adding and math lol- if u dont trust it look it at a calculator- hope this helped!!<3

he ran 6,339 in total

WHO WANTS BRANLIEST?!?!?!?!?!?!?!?

Answers

Answer:

I Do

Step-by-step explanation:

There are twelve signs of the zodiac. How many people must be present for there to be at least a 50% chance that two or more of them were born under the same sign

Answers

Answer:

5

Step-by-step explanation:

Given that each zodiac sign occupies 1/12 of a year.

Then the minimum number of persons for Y[all different signs] < 0.5,

The probability of at least two having the same sign is 1 minus the probability of all having different signs.

This can be represented as A [at least 2 person share the same sign] = 1 - Y[all different signs] must be > 0.5

Therefore we have 1 - 12/12 *11/12 * 10/12 *9/12 *8/12 = 0.38

This implies that the lowest number will be found to be 5

Hence, the correct answer is 5.

Final answer:

To have at least a 50% chance that two or more people share the same Zodiac sign, there must be 13 people. This is based on the Pigeonhole Principle in probability theory.

Explanation:

This question is related to the field of probability theory. It can be solved using the principle of the Pigeonhole Principle, which states that if there are more items than containers, at least one container must hold more than one item.

Let's visualize each Zodiac sign as a container. If we have 12 people (items), each one can occupy a different Zodiac sign (container), without any sign repeating. Therefore, the probability of two people sharing a zodiac sign would be less than 50% at this point.

However, once we introduce the 13th person, regardless of their Zodiac sign, they would have to 'share' a container (be born under a sign that at least one other person was born under) since there are only 12 Zodiac signs. Therefore, for there to be a 50% chance that two or more people share a Zodiac sign, there would need to be 13 people.

Learn more about Pigeonhole Principle here:

brainly.com/question/34617354

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Can someone plz help me solved this problem I need help ASAP plz help me! Will mark you as brainiest!

Answers

Answer:

-1, 1

13, 15

Step-by-step explanation:

x and x+2 are the integers

  • x*(x+2)= 7(x+x+2) -1
  • x²+2x= 14x+14-1
  • x² - 12x -13= 0

Roots of the quadratic equation are: -1 and 13.

So the integers pairs are: -1, 1 and 13, 15

A small regional carrier accepted 19 reservations for a particular flight with 17 seats. 14 reservations went to regular customers who will arrive for the flight. Each of the remaining passengers will arrive for the flight with a 52% chance, independently of each other. (Report answers accurate to 4 decimal places.)1. Find the probability that overbooking occurs.
2. Find the probability that the flight has empty seats.

Answers

Answer:

(a) The probability of overbooking is 0.2135.

(b) The probability that the flight has empty seats is 0.4625.

Step-by-step explanation:

Let the random variable X represent the number of passengers showing up for the flight.

It is provided that a small regional carrier accepted 19 reservations for a particular flight with 17 seats.

Of the 17 seats, 14 reservations went to regular customers who will arrive for the flight.

Number of reservations = 19

Regular customers = 14

Seats available = 17 - 14 = 3

Remaining reservations, n = 19 - 14 = 5

P (A remaining passenger will arrive), p = 0.52

The random variable X thus follows a Binomial distribution with parameters n = 5 and p = 0.52.

(1)

Compute the probability of overbooking  as follows:

P (Overbooking occurs) = P(More than 3 shows up for the flight)

                                        =P(X>3)\n\n={5\choose 4}(0.52)^(4)(1-0.52)^(5-4)+{5\choose 5}(0.52)^(5)(1-0.52)^(5-5)\n\n=0.175478784+0.0380204032\n\n=0.2134991872\n\n\approx 0.2135

Thus, the probability of overbooking is 0.2135.

(2)

Compute the probability that the flight has empty seats as follows:

P (The flight has empty seats) = P (Less than 3 shows up for the flight)

=P(X<3)\n\n1-P(X\geq 3)\n\n=1-[{5\choose 3}(0.52)^(3)(1-0.52)^(5-3)+{5\choose 4}(0.52)^(4)(1-0.52)^(5-4)+{5\choose 5}(0.52)^(5)(1-0.52)^(5-5)]\n\n=1-[0.323960832+0.175478784+0.0380204032]\n\n=0.4625399808\n\n\approx 0.4625

Thus, the probability that the flight has empty seats is 0.4625.