Answer:
2/6 or 1/3
(Please vote me Brainliest if this helped!)
Step-by-step explanation:
Call monkeys A, B and C and hats 1, 2 and 3
You have :
Now, a little more advanced way to solve this is to count in your head. Each outcome gives you a permutation of {1, 2, 3} so there are 3! = 6 Outcomes. Now, if they all wear the wrong hat, you have two choices for the hat of A and then only one choices for B and C. For instance you can choose A2 or A3. If you choose A2 then you must choose B3 and C1.
O B. (f- g)(x) = -4x2 + 10x
O c. (f- g)(x) = 4x2 - 10x
O D. (f- g)(x) = -4x2 - 2x
The (f-g)(x) is- 4x²+ 10x
A function in mathematics from a set X to a set Y allocates exactly one element of Y to each element ofX. The sets X and Y are collectively referred to as the function's domain and codomain, respectively. Initially, functions represented the idealized relationship between two changing quantities.
Given
f(x) = - x² + 6x -1
g(x)=3x² - 4x - 1
(f-g)(x) = - x² + 6x -1 -(3x² - 4x - 1)
(f-g)(x) = - x² + 6x -1 - 3x² + 4x + 1
(f-g)(x) = - 4x² + 10x
(f-g)(x) = - 4x²+ 10x
To know more about codomain refer to :
#SPJ2
2x-5y=22
y=4x+22
Answer:
Point Form (graph) : ( − 22/ 3 , − 22/ 3 )
Equation Form: x = − 22/ 3 , y = − 22/ 3
Step-by-step explanation:
Solve for the first variable in one of the equations, then substitute the result into the other equation.
The recursive formula for the given sequence as required in the task content is; f(n) = f (n - 1) - 50.
It follows from the task content that the recursive formula for the given sequence is to be determined.
By observation, the sequence is an arithmetic progression and the common difference, d can be evaluated as;
d = 750 - 800 = 800 - 850 = 850 - 900 = -50
Also, since the recursive formula for an arithmetic sequence takes the form;
f(n) = f (n - 1) + d.
Hence, since the recursive formula as required is;
f(n) = f (n - 1) - 50.
Read more on recursive formula;
#SPJ1
Answer:
f(1)=900
f(n)=f(n-1)-50if n>1
Step-by-step explanation:
this is the correct
marbles drawn will be red?
Answer: 0.036
Work Shown:
6 red, 6+3+7 = 16 total
A = 6/16 = probability of getting red the first time
after you pick 1 red, there's 6-1 = 5 left out of 16-1 = 15 total
B = 5/15 = probability of getting red the second time
then you repeat: 5-1 = 4 red left out of 15-1 = 14 total
C = 4/14 = probability of getting red the third time
B and C are dependent on A, C is dependent on B. This is assuming we do not put any marbles back.
Multiply out the fractions found
A*B*C = (6/16)*(5/15)*(4/14) = 0.0357 which rounds to 0.036 when rounding to the nearest thousandth.
COMPLETE QUESTION:
Chris went on a vacation for a week and asked his brother Paul to feed his old cat Charlie. But Paul is forgetful, and Chris is 70% sure Paul will forget to feed his cat. Without food, Charlie will die with probability 0.5. With food, he will die with probability 0.03. Chris came back from vacation and found Charlie alive. What is the probability that Paul forgot to feed Charlie (round off to third decimal place)?
Answer:
The probability that Paul forgot to feed charlie is 0.546
Step-by-step explanation:
Lets denote F the event 'Paul forgot to feed Charlie', and L the even 'Charlie is alive', we have
P(F) = 0.7
P(L|F) = 1-0.5 = 0.5
P(L|F^c) = 1-P(L^c|F^c) = 1-0.03 = 0.97
We want to calculate P(F|L). We will use Bayesformula at the start and the theoremoftotalprobability to calculate P(L).
Given that Charlie is alive, the probability that Paul forgot to feed charlie is 0.546.
Answer:
P = 0.546
Step-by-step explanation:
Hi,
This is a question of conditional probability, which means to find probability of a situation given that another event has already occured:
In this question, we need to find the probability of Charlie being alive if not fed, with the data given below:
From this data, we can infer the following:
The probability of Charlie staying alive in both cases:
We need to find the probability when not fed:
(Remember this is the variation of the conditional probability formula as per our requirement in this question).
Hence, the probability of Charlie being alive when Paul forgets is 0.546.
30°
249
126
Answer:
30 - Acute
249 - Obtuse
126 - Obtuse
Step-by-step explanation:
Less than 90 - Acute
90 - Right
More than 90 - Obtuse