Lamar Gant, U.S. powerlifting star, became the first man to deadlift five times his own body weight in 1985. Deadlifting involves raising a loaded barbell from the floor to a position above the head with outstretched arms. Determine the work done by Lamar in deadlifting 300 kg to a height of 0.90 m above the ground (W=Fd).a. 270 J
b. 2646 J
c. 333 J
d. 3.00X10-3 J
Answers
The work done by Lamar in deadlifting 300 kg to a height of 0.90 m above the ground is 2646 Joules
Work is the amount of energy exerted in other to perform an activity. Work is the product of force and displacement. It is given by:
Work = force * displacement
Given that the mass = 300 kg, height = 0.9 m, acceleration due to gravity (g) = 9.81 m/s². Hence:
Work = mass * acceleration due to gravity * height
Work = 300 * 9.81 * 0.9 = 2646 Joules
The work done by Lamar in deadlifting 300 kg to a height of 0.90 m above the ground is 2646 Joules
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Answer:
(b) 2646 J
Explanation:
Earth's gravitational field exerts gravitational force that has direction towards the center of earth, we know that where there is force there is work.
Work by definition is given by.
here in this case
is force because of gravity which has the magnitude of
.
We are making an assumption that we are not too high to change the value of
And .
Putting or substituting these values in the equation of work that i introduced above gives.
and it is Option (b).
Note! units will always be joules for work, joule by definition is Nm.
and .
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Answers
The centripetal acceleration of the ball would be 88.44 m/.
Centripetal acceleration
The centripetal acceleration (ac) of an object moving in a circle at a constant speed is given by the formula:
ac = (v^2) / r
where v is the speed of the object and r is the radius of the circle.
In this case, the ball is revolving uniformly in a circle of radius 0.75 meters, and it makes 2.0 revolutions per second. To find the speed of the ball (v), we need to convert the number of revolutions per second to the angular velocity (ω) in radians per second:
ω = 2π x (number of revolutions per second)
ω = 2π x 2.0 = 4π radians per second
The speed of the ball (v) is then given by:
- v = ω x r
- v = (4π rad/s) x 0.75 m = 3π m/s
Now we can calculate the centripetal acceleration (ac) of the ball:
- ac = (v^2) / r
- ac = [(3π m/s)^2] / 0.75 m
- ac = 9π^2 m/s^2 ≈ 88.44 m/s^2
Therefore, the centripetal acceleration of the ball is approximately 88.44 m/s^2.
More on centripetal acceleration can be found here: brainly.com/question/1052267
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Answer:
insulator
Explanation:
a standard unit of mass used for _____ particies
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Atomic particle.
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It is used to calculate mass at atom level .
1 amu is the mass of 1 atom of C12 carbon
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Answer:
5×10^4 kg
Explanation:
pressure= force/Area
area= 5m^2
pressure = 1×10^5 Pa
1×10^5=mg/5 (weight will be the force)
5×10^5=m×10 (gravitational field strength of the earth)
5×10^5×10^-1 =m
mass=5×10^4 kg!
hope this helps!