MATHEMATICS HIGH SCHOOL

The table shows numbers with the ratio x : y? Find the missing number?x 1 15 225
y 4 ? 900

Answers

Answer 1
Answer:

Answer:

The value of missing number is:

60

Step-by-step explanation:

The ratio x:y is given below

x:y=1:4

x:y=15:?

x:y=225:900

The ratio x:y will remain same for every x and y

Hence, 1:4=15:?

Let a=?

(1)/(4)=(15)/(a)

a=15* 4

a=60

Hence, the value of missing number is:

60
Answer 2
Answer: x| 1 | 15 | 225 |
y| 4 |  ?  | 900 |

(y)/(x)=const.

therefore

[tex]\dfrac{4}{1}=4;\ \dfrac{900}{225}=4;\ \dfrac{?}{15}=4\to?=60[\tex]

Answer: ? = 60

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Rewrite the equation 2x + 4y + 2 = 3y + 5 in general form.

Answers

Answer:  The required general form of the given equation is

2x+y=3.

Step-by-step explanation:  We are given to rewrite the following equation in general form :

2x+4y+2=3y+5~~~~~~~~~~~~~~~~~~~~~~~~~(i)

We know that

the general form of a linear equation in two variables x and y is written as :

ax+by=c,~~\textup{[where a and b cannot be zero at the same time]}

So, from equation (i0, we have

2x+4y+2=3y+5\n\n\Rightarrow 2x+4y-3y=5-2\n\n\Rightarrow 2x+y=3.

Thus, the required general form of the given equation is

2x+y=3.
I believe that the general form would be 2x +4y+ 2 = 3y + 5 
                                                                2x + 4y + 2 - 3y - 5 = 0
                                                                 2x + y - 3 = 0 

This is for today someone help me?!!!!!

Answers

angle m and r both equal 124
angle q and n both equal 56
I think that it’s 17 not a good

Triangle ABC underwent a sequence of transformations to give triangle A′B′C′. Which transformations could not have taken place? A. a reflection across the line y = x followed by a reflection across the line y = -x B. a reflection across the x-axis followed by a reflection across the y-axis C. a rotation 180° clockwise about the origin followed by a reflection across the line y = x D. a reflection across the y-axis followed by a reflection across the x-axis

Answers

Answer:

C. a rotation 180° clockwise about the origin followed by a reflection across the line y = x

Step-by-step explanation:

Let us assume that the coordinate of A in triangle ABC is A(x, y)

A) If there is a reflection across line y = x, the new coordinate is at A'(y, x).

If a reflection across the line y = -x is then followed, the new coordinate is at A"(-x, -y)

B) If there is a reflection across line x axis, the new coordinate is at A'(x, -y).

If a reflection across the line y axis is then done, the new coordinate is at

A"(-x, -y)

C) If there is a rotation 180° clockwise about the origin, the new coordinate is at A'(-x, -y).

If a reflection across the line y = x is then followed, the new coordinate is at A"(-y, -x)

D) B) If there is a reflection across line y axis, the new coordinate is at A'(-x, y).

If a reflection across the line x axis is then done, the new coordinate is at

A"(-x, -y)

Since only option C has a different result from the remaining options, hence option C would not five triangle A'B'C'

Answer:

C. a rotation 180° clockwise about the origin followed by a reflection across the line y = x

Step-by-step explanation:

Let us assume that the coordinate of A in triangle ABC is A(x, y)

A) If there is a reflection across line y = x, the new coordinate is at A'(y, x).

If a reflection across the line y = -x is then followed, the new coordinate is at A"(-x, -y)

B) If there is a reflection across line x axis, the new coordinate is at A'(x, -y).

If a reflection across the line y axis is then done, the new coordinate is at

A"(-x, -y)

C) If there is a rotation 180° clockwise about the origin, the new coordinate is at A'(-x, -y).

If a reflection across the line y = x is then followed, the new coordinate is at A"(-y, -x)

D) B) If there is a reflection across line y axis, the new coordinate is at A'(-x, y).

If a reflection across the line x axis is then done, the new coordinate is at

A"(-x, -y)

Since only option C has a different result from the remaining options, hence option C would not five triangle A'B'C'

Rewrite the multiplication problem using improper fractions.

1 5/6 x 2

Answers

22/6 is the result of the product of the expression.

Multiplication problem using improper fractions.

To rewrite the multiplication problem using improper fractions, we need to convert the mixed number 1 5/6 to an improper fraction.

1 5/6 = 11/6

Now, the multiplication problem can be expressed as:

1 5/6 x 2= 11/6 x 2

1 5/6 x 2 = 22/6

Therefore, the multiplication problem, using improper fractions, is 22/6

Learn more on multiplication of fraction here: brainly.com/question/30391645

#SPJ2
you'll convert 1 5/6 by multiplying the denominator to the whole number (6) then add the numerator 6 + 5 = 11. So the answer is

11/6 x 2 

To solve 5y - 2 - 3y=8, can you start by adding 2 each side? Justify your reasoning.

Answers

Yes, you can start by adding 2 to each side, it doesn't made a difference if you combine 5y and -3y first or not. Either way, you still get y= 5 both ways you do it.
yes , you can add the 2 to both sides. you are combining like terms. it would be easier if you start off by doing 5y - 3y = 2y so the new problem would ne 2y-2=8 then add the 2 so 2y=10 so y = 5.

Tatami mats are used as a floor covering in Japan. one possible layout uses four identical rectangular mats and one square mat. The area of the square mat is half the area of one of the rectangular mats. What is the length and width of one rectangular mat?

Answers

Answer with explanation:

→  Let L be the Length and B be the Breadth of rectangular mat.

     Area of rectangular Mat = Length (L) * Breadth (B)

                                              =L*B square units

→  Let , a be the side of Square.

Area of square =(Side)²

                             =a² square units

→→It is also, given that The area of the square mat is half the area of one of the rectangular mats.

\rightarrow a^2=(LB)/(2)\n\nLB=2a^2\n\n \text{Length of one square mat(L)}=\frac{2a^2}{\text{Breadth(B)}}\n\n\L=\frac{2* {\text{Area of Square}}}{\text{Breadth of rectangle}}\n\nB=\frac{2* {\text{Area of Square}}}{\text{Length of rectangle}}
So by definition, area is equal to the length (x) times the width (y). The area of the square mat is = x × y, or xy
If the area of the rectangular mat is twice that of the square mat, the area of the rectangular mat would have to be = 2 × x × y
This can be written as 2x × y, making the length of the rectangular mat twice that of the square mat's length, and the width the same as the square mat's width.
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