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The ratio of the heights of two similar cylinders is 1:3. If the volume of the smaller cylinder is 67cm cubed, find the volume of the larger cylinder.

Answers

Answer 1

Answer:

Answer:

volume = 1809 cm³

Step-by-step explanation:

The ratio of the height of two similar cylinder is 1:3 . The volume of the smaller cylinder is 67 cm³. The volume of the larger cylinder can be computed below:

If 2 object are similar and the ratio of the corresponding sides is x ,then the ratio of their volume is x³.

ratio of height = 1/3

ratio of volume = (1/3)³ = 1/27

volume of smaller cylinder/volume of larger cylinder = 1/27 = 67/x

where

x = volume of the larger cylinder

x = 27 × 67

x = 1809 cm³

volume = 1809 cm³

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Write an augmented matrix for the system. Then state the dimensions. x+8y−7z=12 5x+9y+5z=15 6z−3y−8x=1

(2 4/10 + 8 4/5) - 3 1/5

Answers

Answer:

it says use a calculater maybe if u used one it would help u out.

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

You can first simplify each fraction, so the it would be (24/10 + 44/5) - 16/5. And then add what is in the parenthesis, 556/5, and then subtract 16/5 to get 8.

A painter can finish painting a house in 3 hour

Answers

Answer:

cool

Step-by-step explanation:

Which of the below is the quotient for the expression 1/5 divided by 4?A) 1/5
B) 4/5
C) 1/20
D) 20

Answers

Answer:

1/20

Step-by-step explanation:

1/5 divided by 4

1/5÷4

1/5x1/4 = 1/20

answer is C (1/20)

Simplify (x + 4)(x2 − 6x + 3). x3 − 14x2 + 3x + 12 x3 − 6x2 − 17x + 12 x3 − 10x2 − 27x + 12 x3 − 2x2 − 21x + 12

Answers

Answer:

36 x^3 - 32 x^2 + (x + 4) (x^2 - 6 x + 3).x^3 - 62 x + 12

Step-by-step explanation:

Answer:

x^6-2x^5-21x^4+48x^3-32x^2-62x+12

Step-by-step explanation:

Mark me as brainliest!!!!

4> Solve by using Laplace transform: y'+5y'+4y=0; y(0)=3 y'(o)=o

Answers

Answer:

$y=3e^(-4t)$

Step-by-step explanation:

$y''+5y'+4y=0$

Applying the Laplace transform:

$\mathcal{L}[y'']+5\mathcal{L}[y']+4\mathcal{L}[y']=0$

With the formulas:

$\mathcal{L}[y'']=s^2\mathcal{L}[y]-y(0)s-y'(0)$

$\mathcal{L}[y']=s\mathcal{L}[y]-y(0)$

$\mathcal{L}[x]=L$

$s^2L-3s+5sL-3+4L=0$

Solving for $L$

$L(s^2+5s+4)=3s+3$

$L=(3s+3)/(s^2+5s+4)$

$L=(3(s+1))/((s+1)(s+4))$

$L=\frac3{s+4}$

Apply the inverse Laplace transform with this formula:

$\mathcal{L}^(-1)[\frac1{s-a}]=e^(at)$

$y=3\mathcal{L}^(-1)[\frac1{s+4}]=3e^(-4t)$

10 less than three times a number is 23. Find the number

Answers

The value of the unknown number is 11

Inequality is a concept in mathematics that shows the comparison between two non-equal numbers.

From the given information

Let the unknown number be x

∴

3x - 10 = 23

Collect like terms

3x = 23 + 10

3x = 33

Divide both sides by 3

$\mathbf{(3x)/(3)= (33)/(3)}$

x = 11

Learn more about inequality here:

brainly.com/question/11613554

Answer:

x = 11

Step-by-step explanation:

23 = 3x-10

1. Add 10 to both sides of the equation. -10 plus 10 is equal to zero so it cancels out to nothing, and 23 plus 10 is 33.

2. The new equation is now 33 = 3x.

3. Now you want to divide both sides by 3 to make x by itself since that is what you are trying to solve for.

4. 33/3 is equal to 11 so x = 11.

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