Answer:
The maximum height that the ball reaches is sf = 31 feet from the ground
Step-by-step explanation:
Solution:-
- A ball is thrown vertically upwards from an initial elevation of si = 6 feet from the ground.
- The velocity with which the ball was thrown up, vi = 40 ft/s
- We can determine the maximum height of the ball when it is thrown vertically up by using the 3rd kinematic equation of motion.
vf^2 - vi^2 = 2*g*( sf - si )
Where,
vf : The final velocity of the ball, for maximum height it is = 0
sf : The final height of the ball from the ground
g : Gravitational constant = -32 ft/s^2
0 - 40^2 = -2*32*( sf - 6 )
sf - 6 = 25
sf = 31 feet
- The maximum height that the ball reaches is sf = 31 feet from the ground.
C. P = 5x + 4y
D. P = 4x + 5y
Answer:
Option C is correct that is P=5x+4y
Step-by-step explanation:
We have given She has 15 eggs and 16 cups of flour in her pantry. Her pumpkin bread recipe uses 2 eggs and 3 cups of flour. Her coffee cake recipe uses 3 eggs and 4 cups of flour
Let x represents number of loaves of pumpkin bread
And y represents the number of loaves of coffee cake Susan bakes
Since, She plans to sell pumpkin bread loaves for $5 each and coffee cake loaves for $4 each.
Hence, P=5x+4y
Therefore, option C is correct.
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StartFraction 9 over 2 EndFraction
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I NEED HELP QUICK!
We have been given an equation . We are asked to find constant of proportionality from our given equation.
We know that two directly proportional equations are in form ,where y is directly proportional to x and k is constant of proportionality.
Let us rewrite our given equation by cross multiplying as:
Now we will divide both sides of equation by 2.
We can see that our equation is in form and constant of proportionality is .
Answer:
9
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Picture:
Answer:
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