An orbiting satellite has seven solar cells, which function independently of each other. During a mission, each cell fails with a probability of 0.3. What is the probability that there will be adequate power output for the mission if 7. All 7 cells must be active?

Answers

Answer 1
Answer: The probability of each cell not failing is 1.0 - 0.3 = 0.7.
The probability of all 7 cells not failing during a mission is given by:
P(7\ cells\ do\ not\ fail)=0.7^(7)=0.082\ or\ 8.2\ percent
Answer 2
Answer:

Final answer:

The probability that all 7 solar cells will be active is 0.08243, or approximately 8.24%.

Explanation:

In this question, we are given that each solar cell on the satellite has a failure probability of 0.3. Since there are 7 cells, we need all of them to be active in order to have adequate power output for the mission. To find the probability of this happening, we need to calculate the probability of all 7 cells being active.

Since each cell operates independently, the probability of a cell failing is 0.3 and the probability of it being active is 1 - 0.3 = 0.7. Therefore, the probability that all 7 cells will be active is (0.7)^7 = 0.08243.

Thus, the probability of there being adequate power output for the mission is 0.08243, or approximately 8.24%.

Learn more about Probability here:

brainly.com/question/22962752

#SPJ2


Related Questions

Shanna attends school for 1 week longer than 3/4 of the year. How many weeks in a year dies Shanna attend school ?
In 2004, it was reported that "the relationship between body mass, M, and standard metabolic rate, B, among living organisms remains controversial. However, in many cases B is approximately proportional to the three-quarters power of M. a.he average mass of an African forest elephant is 4.6 metric tons, and that of a typical mouse is 25 grams. Use part (a) to determine how many times greater the metabolic rate of an elephant is than that of a mouse. Recall that 1 metric ton = 1,000,000 grams.
Which of the following equations describe the line shown below? Check all that apply. (THERE IS MORE THAN ONE ANSWER)
How do you find the volume of an L-Block
Which of the following graphs represents the solution set for 7(4x – 1 ) + 6x > –279? PLEASE HELP

7x-5y=20 in slope intercept form

Answers

slope inercept
solve for y

mnus 7x both sides

-5y=-7x+20
divide both sides by -5
y=7/5x-4

Hello , may someone help me on this plz

Answers

Answer:

x=7

Step-by-step explanation:

m1= 84

m2= 96

m3= 84

m4= 96

m5= 96

m6= 84

m7= 96

m8= 84

A code is formed using four of these letters: A, B, I, K, N, O, and T. (Note that the order of the letters in the code matters; for example, ABIK is a different code from BAIK.)The size of the sample space is . The probability that the first three letters of the four-letter code are vowels is?

Answers

Answer: The size of the sample is 840.

The probability that the first three letters of the four-letter code are vowels is=(1)/(35)

Step-by-step explanation:

Th total number of letters given to form code of 4 letters = 7

Since, the order of the letters in the code matters, which means there is no repetition.

The total number of ways to form the code size =7*6*5*4=840

Therefore, The size of the sample is 840.

Since, there are 3 vowels and rest of 4 letters are consonant.

The number of ways to form code such that the first three letters of the four-letter code are vowels =3*2*1*4=24

The probability that the first three letters of the four-letter code are vowels is

=(24)/(840)=(1)/(35)

The probability that the first three letters of the four-letter code are vowels is 1/35 and the size of the sample is 840.

What is the explanation for the above?

Step 1 - Determine the sample size.

It is to be noted that the total number of letters given to form code of 4 letters = 7

Given that  the order of the letters in the code matters, which means there is no repetition; hence,

The total number of ways to form the code size = 7 x 6 x 5 x 4 = 840

Thus, the size of the sample is 840.

Step 2  - Solve for the Probability

Given that  there are 3 vowels and rest of 4 letters are consonant.

The number of ways to form code such that the first three letters of the four-letter code are vowels

= 3 x 2 x 1 x 4

= 24

Hence, the probability that the first three letters of the four-letter code are vowels is

= 24/840

= 1/35

Learn more about probability at;
brainly.com/question/24756209
#SPJ5

Submit your work legible (ifSwill and answerin a webmail to me. This is a total of 35 points. Itbe a portfolio gradyou will have to webmail me this!Complete the following problems.1. Open Response: Solve each problem below. Solve for the missing side, Show your workGive both an exact answer and Rn answer in your solutions.

Answers

ok so

for a right triangle with legs legnth a and b and hypotonuse c
a^2+b^2=c^2
remember
the hypotonuse is the side oposite the right angle

you have
13 and 17 and x
17=hypotonuse
13 ad x are legs
13^2+x^2=17^2
169+x^2=289
minus 169 boh sides
x^2=120
sqrt both sides
x=2√30
aprox
10.9545 units


second one
legs are 5x and x
hypotonsue is 20
(5x)^2+x^2=20^2
25x^2+x^2=400
26x^2=400
divide both sides by 26
x^2=(400/26)
sqrt both sides
x=20/(√26)
aprox
x=3.92232 units
times 5 to see other leg
19.616 units

A universal set contains only sets A and B. If A∩B = Ø and A and B are not the empty set, then all of the following are true except ______. A and B are disjoint.

A is equal to B complement.

A∪B={}

A is not a subset of B.

Answers

If A∩B = Ø and A and B are not the empty set, all of the following are true except Option 3

What is an empty set?

That set which doesn't contain any value is called empty set. This is also called as null set or void set. This is denoted by Ø  or { }

We have given A∩B = Ø

Case1:

If A∩B = Ø and A and B are not the empty set, A and B are non empty set which means A and B are disjoint.

Hence, Option 1 is correct.

Case2:

If there intersection is empty means there is nothing common. Hence, Option 2 is correct.

Case3:

A and B are non-empty sets means their union can not be empty.

Hence, option 3 is incorrect.

Case4:

A can't be subset of B because Subset is the same elements in B of A which is not possible because their intersection is empty.

Hence, Option 4 is correct.

Therefore,  If A∩B = Ø and A and B are not the empty set, all of the following are true except Option 3.

Learn more about set here:

brainly.com/question/12885796

#SPJ2

Answer:

Option 3

Step-by-step explanation:

We have give A\capB=\phi

Case1:

A and B are non empty set which means A and B are disjoint

Hence, Option 1 is correct.

Case2:

When there intersection is empty means there is nothing common

Hence, A is not of B  or A is equal to complement of B

Hence, Option 2 is correct.

Case3:

A and B are non-empty sets means their union can not be empty

Hence, option 3 is incorrect.

Case4:

A can not be subset of B because Subset is the same elements in B of A which is not possible because their intersection is empty

Hence, Option 4 is correct.

We have to choose false statement

Therefore, Option 3

A frying pan has a radius of 14 centimeters. What is the circumference of the frying pan

Answers

The formula for the circumference of a circle is:

C=2πr

Since we know the radius is 14cm, we can solve for the circumference...
C=2π(14)
C=28πcm
C=87.96cm



The curcumfrence is 87.92 centimeters. I multiplied 14 by 2 because you multiply the diameter by 3.14. Diameter is radius times 2. Then you would multiply 28 by 3.14 because C = d times 3.14. d is diameter and C is circumference. Hope this helps