The probability that all 7 solar cells will be active is 0.08243, or approximately 8.24%.
In this question, we are given that each solar cell on the satellite has a failure probability of 0.3. Since there are 7 cells, we need all of them to be active in order to have adequate power output for the mission. To find the probability of this happening, we need to calculate the probability of all 7 cells being active.
Since each cell operates independently, the probability of a cell failing is 0.3 and the probability of it being active is 1 - 0.3 = 0.7. Therefore, the probability that all 7 cells will be active is (0.7)^7 = 0.08243.
Thus, the probability of there being adequate power output for the mission is 0.08243, or approximately 8.24%.
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Answer:
x=7
Step-by-step explanation:
m1= 84
m2= 96
m3= 84
m4= 96
m5= 96
m6= 84
m7= 96
m8= 84
Answer: The size of the sample is 840.
The probability that the first three letters of the four-letter code are vowels is
Step-by-step explanation:
Th total number of letters given to form code of 4 letters = 7
Since, the order of the letters in the code matters, which means there is no repetition.
The total number of ways to form the code size =
Therefore, The size of the sample is 840.
Since, there are 3 vowels and rest of 4 letters are consonant.
The number of ways to form code such that the first three letters of the four-letter code are vowels =
The probability that the first three letters of the four-letter code are vowels is
=
The probability that the first three letters of the four-letter code are vowels is 1/35 and the size of the sample is 840.
Step 1 - Determine the sample size.
It is to be noted that the total number of letters given to form code of 4 letters = 7
Given that the order of the letters in the code matters, which means there is no repetition; hence,
The total number of ways to form the code size = 7 x 6 x 5 x 4 = 840
Thus, the size of the sample is 840.
Step 2 - Solve for the Probability
Given that there are 3 vowels and rest of 4 letters are consonant.
The number of ways to form code such that the first three letters of the four-letter code are vowels
= 3 x 2 x 1 x 4
= 24
Hence, the probability that the first three letters of the four-letter code are vowels is
= 24/840
= 1/35
Learn more about probability at;
brainly.com/question/24756209
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A is equal to B complement.
A∪B={}
A is not a subset of B.
If A∩B = Ø and A and B are not the empty set, all of the following are true except Option 3
That set which doesn't contain any value is called empty set. This is also called as null set or void set. This is denoted by Ø or { }
We have given A∩B = Ø
Case1:
If A∩B = Ø and A and B are not the empty set, A and B are non empty set which means A and B are disjoint.
Hence, Option 1 is correct.
Case2:
If there intersection is empty means there is nothing common. Hence, Option 2 is correct.
Case3:
A and B are non-empty sets means their union can not be empty.
Hence, option 3 is incorrect.
Case4:
A can't be subset of B because Subset is the same elements in B of A which is not possible because their intersection is empty.
Hence, Option 4 is correct.
Therefore, If A∩B = Ø and A and B are not the empty set, all of the following are true except Option 3.
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Answer:
Option 3
Step-by-step explanation:
We have give
Case1:
A and B are non empty set which means A and B are disjoint
Hence, Option 1 is correct.
Case2:
When there intersection is empty means there is nothing common
Hence, A is not of B or A is equal to complement of B
Hence, Option 2 is correct.
Case3:
A and B are non-empty sets means their union can not be empty
Hence, option 3 is incorrect.
Case4:
A can not be subset of B because Subset is the same elements in B of A which is not possible because their intersection is empty
Hence, Option 4 is correct.
We have to choose false statement
Therefore, Option 3