MATHEMATICS MIDDLE SCHOOL

Please help!!!! I am about to fail !!

Answers

Answer 1

Answer:

Given:

A circle with its center at (0, -3).

To find:

The standard equation for the given circle.

Solution:

The standard form of a circle is $(x-h)^(2)+(y-k)^(2)=r^(2)$ , where (h, k) is the center of the circle and r is the radius of the circle.

The center of the given circle is at (0, -3).

We need to determine the radius of the circle. The center is at (0, -3) and a point with the same y coordinate is (3, -3).

The radius of the circle $= 3-0=3$ units.

So for the given circle, (h, k) is (0, -3) and r is 3 units.

So the equation becomes $(x-0)^(2)+(y-(-3))^(2)=3^(2)$ .

The standard equation for the circle is $x^(2)+(y+3)^(2)=9.$

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6d 1 = 15-d I really don't understand thisssss and my teacher won't help

Answers

You required to find the value of d.
Always remember the concept that if you transpose "+" sign to the other side, it becomes "-" sign, and vice versa. Make sure that you arrange the like terms and constants. Solving the equation,
6d + 1 = 15 - d
6d + d = 15 - 1
7d = 14
d = 14/7 = 2

When transposing a multiplication, you divide it to the other side.

Verifying the solution,
6(2) + 1 = 15 - 2
12 + 1 = 13
13 = 13

What is a common factor of 34

Answers

You need to give 2/more numbers to obtain a common factor.

sorry you need 1 more to find the common factor

3.25, 3.0, 2.75, 2.5, 2.25, ...What is the rule to continue this decimal number pattern?
increase by 0.5
increase by 0.25
decrease by 0.5
decrease by 0.25

Answers

3.25 - 3 = 0.25
3 - 2.75 = 0.25
2.75 - 2.5 = 0.25
2.5 - 2.25 = 0.25

Since we subtracted those numbers, it means we are decreasing.
Therefore, the answer is decrease by 0.25.

you are decreasing by 0.25 . Each time you are subtracting only .25 to each number . +

Which describes the relationship between 20,000 and 200,000?

Answers

200,000 is ten times greater then 20,000

write a fraction with a decimal value between 1/2 ans 3/4. Write both the fraction and the equivalent decimal.

Answers

1/2 can also be written as 4/8
3/4 can be written as 6/8
5/8 is between 4/8 and 6/8
the equivalent decimal of 5/8 is .625

1/2 = 4/8 = 0.5
3/4 = 6/8 = 0.75
therefore, a fraction between 1/2 and 3/4 is 5/8

The sides of a square are 3 cm long. One vertex of thesquare is at (2,0) on a square coordinate grid marked in
centimeter units. Which of the following points could
also be a vertex of the square?
F. (−4, 0)
G. ( 0, 1)
H. ( 1,−1)
J. ( 4, 1)
K. ( 5, 0)

Answers

Answer: The required point that could also be a vertex of the square is K(5, 0).

Step-by-step explanation: Given that the sides of a square are 3 cm long and one vertex of the square is at (2,0) on a square coordinate grid marked in centimeter units.

We are to select the co-ordinates of the point that could also be a vertex of the square.

To be a vertex of the given square, the distance between the point and the vertex at (2, 0) must be 3 cm.

Now, we will be suing the distance formula to calculate the lengths of the segment from the point to the vertex (2, 0).

If the point is F(-4, 0), then the length of the line segment will be

$\ell=√((-4-2)^2+(0-0)^2)=√(6^2+0^2)=√(6^2)=6~\textup{cm}\neq 3~\textup{cm}.$

If the point is G(0, 1), then the length of the line segment will be

$\ell=√((0-2)^2+(1-0)^2)=√(2^2+1^2)=√(4+1)=\sqrt5~\textup{cm}\neq 3~\textup{cm}.$

If the point is H(1, -1), then the length of the line segment will be

$\ell=√((1-2)^2+(-1-0)^2)=√(1^2+1^2)=√(1+1)=\sqrt2~\textup{cm}\neq 3~\textup{cm}.$

If the point is J(4, 1), then the length of the line segment will be

$\ell=√((4-2)^2+(1-0)^2)=√(2^2+1^2)=√(4+1)=\sqrt5~\textup{cm}\neq 3~\textup{cm}.$

If the point is K(5, 0), then the length of the line segment will be

$\ell=√((5-2)^2+(0-0)^2)=√(3^2+0^2)=√(3^2)=3~\textup{cm}.$

Thus, the required point that could also be a vertex of the square is K(5, 0).

K (5.0) It's easy just use 2plus3and that's it.

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Plz help me quick!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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