If Linh removes bulb 3,the bulbs which will remain lit are 1, 2 and 4.
The electric circuit provided with battery creating potential difference across resistance or capacitor or inductors.
When Linh removes the middle branch, the bulbs 1, 2 and 4 will be acting as resistor which are in series connection. The current flow will be same in all the resistors except 3.
Thus, If Linh removes bulb 3, the bulbs which will remain lit are 1, 2 and 4.
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Answer:
1, 2, 4
Explanation:
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Answer:
A freely falling object have fallen from a position of rest when its instantaneous speed is 10 m/s, it will travel 5.102 meter.
Explanation:
We have equation of motion, , where u is the initial velocity, u is the final velocity, s is the displacement and a is the acceleration.
In this case we have final velocity = 10 m/s, initial velocity = 0 m/s, and acceleration = 9.8 .
Substituting
A freely falling object have fallen from a position of rest when its instantaneous speed is 10 m/s, it will travel 5.102 meter.
When an object, starting from rest, achieves an instantaneous speed of 10 m/s while freely falling under gravity, it will have fallen approximately 5.10 meters.
Using the physics concept of motion under gravity, where the first equation of motion can apply (v = u + gt), your question involves finding the displacement of a freely falling object starting from rest until it reaches a speed of 10 m/s.
In this case, initial velocity (u) is zero because the object was at rest, the final velocity (v) is 10 m/s, and g is the acceleration due to gravity which is approximately 9.81 m/s².
We could rearrange the equation to find time: t = v/g = 10 / 9.81 ≈ 1.02 s. Then, we employ the second equation of motion to find the distance fallen, s = ut + 0.5gt². Since u=0, the formula simplifies to s = 0.5gt². Substituting g = 9.81 m/s² and t = 1.02 s into the equation yields s = 0.5 * 9.81 * (1.02)² ≈ 5.10 m.
Therefore, a freely falling object will have fallen approximately 5.10 meters when its instantaneous speed is 10 m/s.
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To accelerate a shopping cart with a mass of 65kg at a rate of 0.3 m/sec2, you would need to exert a force of 19.5 Newtons, according to Newton's second law of motion.
The subject of this problem is physics, specifically the concept of force, mass, and acceleration within the domain of Newton's second law of motion. The law states that the force needed to accelerate an object is equal to the mass of the object multiplied by the desired acceleration.
Given the mass of the cart is 65 kilograms and the acceleration is 0.3 m/sec2, you can calculate the required force using the formula:
Force = mass * acceleration.
So, Force = 65 kg * 0.3 m/sec2 = 19.5 Newtons. Therefore, you would have to exert a force of 19.5 Newtons to accelerate the shopping cart at the specified rate.
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Answer: The diameter of the circular path is 2.96m
Explanation: centripetal acceleration = tangential speed^2 / radius of the circular path.
Centripetal acceleration = 2.7m/s^2
Tangential speed = 2.0m/s
Radius = 2.0^2 / 2.7 = 4/2.7
= 1.48m
Diameter = radius*2
= 1.48*2 = 2.96m.
2.beta
3.gamma
4.positron
The kinetic energy of the object which is moving with velocity of 9 m/s and has a mass of 20 kg will be 810 joules.
The energy possessed by the body by virtue of its motion is called kinetic energy. Mathematically -
E[K] = 1/2mv²
Given is an object that has a velocity of 9 m/s and a mass of 20 kg.
We can calculate the kinetic energy of the object by using the formula discussed above.
Mass [m] = 20 Kg
Velocity [v] = 9 m/s
Substituting the values, we get -
E[K] = 1/2 x 20 x 9 x 9
E[K] = 10 x 9 x 9
E[K] = 81 x 10
E[K] = 810 joules
Therefore, the kinetic energy of the object which is moving with velocity of 9 m/s and has a mass of 20 kg will be 810 joules.
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Explanation:
k.e =1/2m(v)²
or
k.e=m/2(v)²
so......k.e=20kg/2(9m/s)²
k.e=10kg(81m²/s²)
k.e=10kg(81m²/s²)
k.e=810kgm²/s²
HOPE ITS CORRECT
ANSWER
k.e=810kgm²/s²