If an alloyed guitar B string (147 Hz resonance) has an average diameter of .6 mm over an effective oscillating length of 65 cm, what is the tension in Newtons if the alloy is 10% aluminum and 90% copper? (assume the specific gravities of the metals are 2.6 and 8.9 grams per cubic centimeter, respectively)

Answers

Answer 1
Answer:

Answer:

73.8 N

Explanation:

The total volume is,

V = (m_Al)/(P_Al) = (m_copper)/(P_copper)

=  (10m)/((100)(2.6)) = (90m)/((100)(8.9))

= 0.1396 m

The average  density is,

p = (m)/(V)

= (m)/(0.1396)

= 7.169 g/cm³

The linear mass density is,

μ = pπr²

= (7.169 x 10⁹) (π (0.3 x 10⁻³)²)

= 2.026 x 10⁻³ Kg/m

The fundamental mode of length is,

L =  λ/2

λ=2L

= 2 x 0.65

= 1.3 m

The speed of the wave is,

v = λf

= 1.3 m x 147 Hz

= 1.91 m/s

The tension is,

v =  √T/ц

T = ц v²

= 2.026 x 10⁻³)(1.91 m/s)²

= 73.769N

73.8N


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Answers

The correct answer should be D). speed up, decrease, stay the same.

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Two objects move toward each other because of gravitational attraction. As the objects get closer and closer, the force between them _____. A. remains constant B. decreases C. increases

Answers

As 2 objects get closer and closer due to the gravitational attraction, the force between them C. increases.

Two objects move toward each other because of gravitational attraction. To understand the gravitational force, we need to consider Newton's law of universal gravitation, which states that every particle attracts every other particle in the universe with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. Mathematically,

F = G (m_1m_2)/(r^(2) )

where,

  • F: gravitational force
  • G: gravitational constant
  • m₁: mass of object 1
  • m₂: mass of object 2
  • r: distance between centers of the masses

As the objects get closer, the distance between them decreases, and consequently the gravitational force increases.

As 2 objects get closer and closer due to the gravitational attraction, the force between them C. increases.

Learn more: brainly.com/question/11033817

Answer:

C. increases

Explanation:

Law of Universal Gravitation

This law establishes that bodies, by simply having mass, experience a force of attraction to other bodies with mass, called gravitational force or gravitational force.

The gravitational force between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance that separates them.

F_(g) =G((M*m)/(r^(2) ) )Formula (1)

where:

G is the universal gravitation constant, G = 6.67 · 10-11 N · m² / kg²

M and m are the masses of the bodies that interact  (kg)

r is the distance that separates them. (m)

Problem development

As objects get closer and closer the distance (r) that separates them decreases and because M, m and G remain constant, in formula (1):

F_(g) =G((M*m)/(r^(2) ) )

, if r decreases then Fg increases.

Hi all! I’m struggling with solving this section in a physics test. Especially the last point.

Answers

Answer:

Explanation:

We should know that the gradient(slope) of a distance-time graph is the speed, and the gradient of a velocity-time graph is the acceleration.

a) Since the gradient from t=80 to 160 is 0, the speed is 0, indicating it is at rest.

b)To find the speed, we find the gradient of the graph at t=40. Since it is a straight line from t=40 to 60, we can do this simply by

Gradient = (200-120)/(60-40)=80/20=4 (This is an estimate since the graph is not clear, instead of t=40 and t=60, you can use any two points along that straight line (from about t=20 to 60))

c)The one on the right is the velocity graph, and the one on the left shows acceleration. We can know this by analysing some points. For example, and t=50, the right graph is about constant at 5, while the left one is 0. This would indicate that the left one shows the gradient of the right (gradient of a constant portion is 0). We can choose another place on the right graph, say t=60 to 80. The curve is decreasing. The left graph for this same time period is negative. This reaffirms our guess, since the gradient of a decreasing curve should be negative.

If you want to do it the other way around, you can analyse the left graph. From about t=15 to t=30 the graph is decreasing. Thus its slope should be negative. However, the right graph is positive for this period. This means that the right graph definately does not show the slope of the left.

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A 0.09 kg marble sits at rest on the top of a sloping, frictionless track.a. If the slope has a height of 1.5 m, calculate the velocity of the marble at the bottom of
the slope.

Answers

Answer:

Explanation:

Notice that nothing but the mass and height are given, and the mass is not really necessary. It will cancel when we do the problem.

So the potential energy at the top equals the Kinetic energy at the bottom.

PE_top = Ke_bottom

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Three friends tie three ropes in a knot and pull on the ropes in different directions. Adrienne (rope 1) exerts a 20-N force in the positive x-direction, and Jim (rope 2) exerts a 40-N force at an angle 53∘ above the negative x-axis. Luis (rope 3) exerts a force that balances the first two so that the knot does not move.a. Use equilibrium conditions to find F LonKx and F LonKy.
b. Use equilibrium conditions to determine the magnitude of F⃗ LonK.
c. Use equilibrium conditions to determine the angle θ that describes the direction of F⃗ LonK. Use positive values if the force is directed above the positive x-axis and negative values if it is directed below the positive x-axis.
d. Construct a force diagram for the knot.

Answers

Answer:

Part a)

F = 4 \hat i - 32\hat j

Part b)

Magnitude of the force is given as

F = 32.2 N

Part c)

As we know that Y component of the force is negative so here the force is directed below the X axis

\theta = -82.9 degree

Explanation:

Part a)

Adrienne apply the force of 20 N along +X direction and Jim apply force of 40 N at 53 degree above negative X axis

so we will have

F_1 = 20 \hat i

F_2 = 40cos53(-\hat i) + 40 sin53(\hat j)

F_2 = -24\hat i + 32\hat j

now let say the force exerted by Luis is F such that sum of all forces must be zero

now we have

F_1 + F_2 + F_3 = 0

so we have

20\hat i -24\hat i + 32\hat j + F = 0

-4\hat i + 32\hat j + F = 0

F = 4 \hat i - 32\hat j

Part b)

Magnitude of the force is given as

F = √(4^2 + 32^2)

F = 32.2 N

Part c)

As we know that Y component of the force is negative so here the force is directed below the X axis

So here we have

tan\theta = -(32)/(4)

\theta = -82.9 degree

Oil flows upward in the wick of a lantern because of liquid property called

Answers

Capillarity "Capillarity causes the part of the surface of a liquid in contact with a solid, to be either elevated above (e.g. water), or depressed below (e.g. mercury), the rest of the surface. This trait is named for the behaviour of liquids in capillary tubes placed perpendicular to the surface. The forces operating within capillarity are cohesion, adhesion, and surface tension."