In the clip from the Simpsons, Ralph charges Bart twice the fair from Tucson to Flagstaff, minus 2/3 the fair from Albuquerque to El Paso. It costs $40 to travel from Tucson to Flagstaff, and $90 to travel from Albuquerque to El Paso. So, how much does Bart need to pay?

Answers

Answer 1
Answer:

Answer:

$20.

Step-by-step explanation:

Given:

In the clip from the Simpsons, Ralph charges Bart twice the fair from Tucson to Flagstaff, minus 2/3 the fair from Albuquerque to El Paso.

It costs $40 to travel from Tucson to Flagstaff,

And $90 to travel from Albuquerque to El Paso.

Question asked:

How much does Bart need to pay ?

Solution:

Fair to travel from Tucson to Flagstaff = $40

Fair to travel from Albuquerque to El Paso = $90

As Ralph charges Bart twice the fair from Tucson to Flagstaff, minus 2/3 the fair from Albuquerque to El Paso.

Bart\ need\ to\ pay=2 *\$40 - (2)/(3) *\$90\n \n

                            =80-(180)/(3) \n \n =80-60\n \n =20

Thus, Bart need to pay $20.


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Expand the logarithmic expression.
log(b)squrt(13/73)

Answers

Answer:

\frac{log_b{13}-log_b{73}}{2}

Step-by-step explanation:

log_b{\sqrt{(13)/(73)}}

First we remove the square root

log_b({(13)/(73))^(1)/(2)}

As per log property we can move the exponent 1/2 before log

(1)/(2)log_b{(13)/(73)}

Now we apply log property to expand log (13/73)

log(a/b)= log(a) - log(b)

(1)/(2)log_b{13}-log_b{73}}

\frac{log_b{13}-log_b{73}}{2}


\log_b\sqrt{(13)/(73)}=\frac12\log_b(13)/(73)=\frac{\log_b13-\log_b73}2

9p=81
helppppppppppppppppp

Answers

p = 9 becsude 9 x 9 = 81 so yeah

Gavin and Ethan are training for a race. Last week, Gavin ran 7 kilometers, and Ethan ran twice as far as Gavin. What is the total distance that Gavin and Ethan ran last week? Express your answer in meters.

Answers

The total distance that Gavin and Ethan ran last week is: 21000 meters

How to find the total distance?

Gavin ran 7 kilometers last week, and Ethan ran twice as far as Gavin. To find the total distance that Gavin and Ethan ran last week, we need to add the distance that Gavin ran to the distance that Ethan ran.

Since Gavin ran 7 kilometers, we can convert this to meters by multiplying by 1000:

7 kilometers * 1000 meters/kilometer = 7000 meters

Since Ethan ran twice as far as Gavin, we can find the distance that Ethan ran by multiplying Gavin's distance by 2:

2 * 7000 meters = 14000 meters

Therefore, the total distance that Gavin and Ethan ran last week is:

7000 meters + 14000 meters = 21000 meters

In summary, Gavin ran 7000 meters and Ethan ran 14000 meters last week, for a total distance of 21000 meters that they both ran.

Read more about Total Distance at: brainly.com/question/4931057

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If Ethan ran twice as far as Gavin then he ran 14 kilometers. 7*2=14. And then you add 7 to 14 which gives you 21. so they ran a total of 21 kilometers

A class of 24 students is planning a field trip to a science museum. A nonrefundable deposit of $50 is required for the day-long program, plus a charge of $4.50 per student.Determine a linear function that models the cost, c, and the number of students, s.

Which statements about the linear function and its graph are correct? Check all that apply.

Answers

Answer:

A,C, and D

Step-by-step explanation:

Did it on Edgenuity

Answer:

A, C, D

Step-by-step explanation:

An astronaut who weighs 126lb on Earth weighs only21lb on the moon. How much would a person who weights 31lb on the moon weigh on Earth?

Answers

If his weight on Earth is 126lb and only 21lb on moon, you can divide 126/21 to see what is the ratio of those weights.
126/21=6

It means that your weight on moon will be 6 times less than on Earth.

Now we have to multiply 31lb which is weight of the person on moon by 6 to get his weight on Earth 6*31=186
On moon our mass becomes 1/6 of actual mass so if you weigh 60 kg then your mass on moon will be 10 kg..
Similarly if your mass on moon is 31 lbs then your mass on earth will be 31*6=186 lbs.
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Factorise 80 x + 30 need explaining clearly please

Answers

remember distributive
a(b+c)=ab+ac
reverse
ab+ac=a(b+c)
find a which is GCF

factor them and group

80x=2*2*2*2*5*x
30=2*3*5
GCF=2*5=10
a=10
80x+30=10(8x)+10(3)=10(8x+3)
80 (x) + 30 

80+30=110*

110(x)

30-110-80(x)

80-30=50-110=(x)+110+30+50/(x)

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