An icicle is in the shape of an inverted cone with a diameter of 14 mm and a height of 60 mm. How much-frozen water is in the icicle? Use 3.14 for Pi. Round the answer to the nearest tenth.

Answers

Answer 1
Answer:

Answer:

Amount of water =  3077.2 mm^3.

Step-by-step explanation:

The radius = 1/2 diameter = 1/2 * 14 = 7.

The amount of ice in the cone = it's volume.

The volume of the cone = 1/3 3.14 r^2 h

= 1/3 * 3.14 * 7^2 * 60

= 3077.2 mm^3.


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Which of the following is a polynomial function in standard form with zeros at –8, –1, and 3?A) f(x) = (x + 8)(x + 1)(x – 3)B) f(x) = x^3 – 6x^2 – 19x + 24C) f(x) = x^3 + 6x^2 – 19x – 24D) f(x) = (x – 8)(x – 1)(x + 3)
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What is the slope of the line?

Answers

Answer:

12

Step-by-step explanation:

72/6=12

48/4=12

What is the Remainder of 70!/5183

Answers

Hello,

Answer 1277

11978571669969891796072783721689098736458938142546425857555362864628009582789845319680000000000000000=
2311127082764787149541343569687265818340524434216944985057951546329926602892117561196218406328381 * 5183+ 1277




The set of ordered pairs represent a function. Write a rule that represent the function. (0,0), (1,6),(2,24), (3,54),(4,96)

Answers

The required function would be f(x) = 6x² which represents the set of ordered pairs.

What is a function?

The function is defined as a mathematical expression that defines a relationship between one variable and another variable.

We have been given that function as sets of ordered pairs :

(0,0), (1,6), (2,24), (3,54), (4,96)

First, we must identify a pattern. It appears that all yₓ values are multiples of 6.

We can divide yₓ by 6x since it is a multiple of 6 and a multiple of x:

y₁/ 6×1 = 1

y₂/ 6 ×2 = 2

y₃/ 6 ×3= 3

y₄/6×4 = 4

We can clearly see a pattern here ;

y/ 6×x = x

y = x × x × 6

y = 6x² = f(x)

Therefore, the required function would be f(x) = 6x² which represents the set of ordered pairs.

Learn more about the functions here:

brainly.com/question/12431044

#SPJ5

All y coordinates are divisable by 6. What you then get is the square of x, so the function is:

f(x) = 6x²

Calculate one tenth of an income of $12,347 by dividing by 10. 12.35 123.47 1,234.70 123,470

Answers

Answer: 1,234.70

Step-by-step explanation:

The given amount of income = $12,347

To find :  One tenth of an income of $12,347  

To calculate one tenth of an income of $12,347, we need to divide $12,347 by 10 ,we get

12,347/10\n\n=(12,347 )/(10)\n\n=1,234.7

On dividing a number by ten , we put decimal just before the first digit from the right.

Hence, One tenth of an income of $12,347 = 1,234.70

1,234.70. Hope this helps

How are expressions and equations different

Answers

 An "equation" has a left side, a right side and an equals sign separating the sides. An "expression," by contrast, doesn't have any "sides" and is simply what the name suggests: An algebraic "expression."
Expressions have no equal sign, while equations have equal signs. 

The function f(x) = –x2 − 2x + 15 is shown on the graph. What are the domain and range of the function?The domain is all real numbers. The range is {y|y < 16}.
The domain is all real numbers. The range is {y|y ≤ 16}.
The domain is {x|–5 < x < 3}. The range is {y|y < 16}.
The domain is {x|–5 ≤ x ≤ 3}. The range is {y|y ≤ 16}.

Answers

First, you can simplify the function finding the perfect square:

f(x)=-x^2-2x+15=-(x^2+2x)+15=-(x^2+2x+1-1)+15=-((x+1)^2-1)+15=-(x+1)^2+1+15=-(x+1)^2+16.

This form of function gives you the coordinates of parabola vertex - (-1,16).

From the diagram you can see that all values for x are possible, then the domain is x\in (-\infty,\infty) (all real numbers). Also you can see that values of y decrease from y=16 to -\infty, then the range is y\in(-\infty,16] (or {y|y ≤ 16}).

Answer: correct choice is B.

Since the function is a parabola and there are no discontinuities, the domain is all real numbers. To determine the range, the function has to be transformed into the vertex form.
The vertex form of the function is:
f(x) = -(x+1)2 +16
This means that the graph is facing downwards with the vertex at (-1,16).
So, the range is {y|y ≤ 16}