How does the mean absolute deviation (MAD) of the data in set 1 compare to the mean absolute deviation of the data in set 2?Set 1: 5, 10.7, 2
Set 2: 5, 10, 7, 42
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A)The MAD of set 1 is 10.5 more than the MAD of set 2.
B)The MAD of set 1 is 2.5 more than the MAD of set 2.
C)The MAD of set 1 is 10.5 less than the MAD of set 2.
D)The MAD of set 1 is 2.5 less than the MAD of set 2.
(Please sombody awnser this quickly
Answers
The MAD of set 1 is 10.5 less than the MAD of set 2.
What is MAD?
MAD is mean absolute deviation which is calculated by
MAD = ∑₁ⁿ(|x - μ|)/n
Given data of set 1 : 5,10,7,2
and set 2: 5,10,7,42
MAD of set 1 = MAD(1) = ∑₁ⁿ(|x - μ|)/n
where μ is mean of set 1 and x are the entries of set and n is no. of entries,
μ =( 5+10+7+2)/4 =24/4 =6
now reduce the values of set 1 from mean
|x - μ| of set = 1,4,1,4
MAD(1) = ∑₁ⁿ(|x - μ|)/n = (1+4+1+4)/4 =10/4
MAD(1) = 2.5
MAD of set 2 = MAD(2) = ∑₁ⁿ(|x - μ|)/n
calculate mean for set 2
μ =( 5+10+7+42)/4 =64/4 = 16
now reduce the values of set 2 from mean
|x - μ| of set = 11,6,9,26
MAD(2) = ∑₁ⁿ(|x - μ|)/n =(11+6+9+26 )/4 =52/4
MAD(2) = 13
MAD(2) - MAD(1) = 13-2.5 = 10.5
Hence the set 1 is 10.5 less then set 2
Learn more about mean absolute deviation
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Answer:
the answer is C
Step-by-step explanation:
if you do 5+10+7+2 you get 24 divide by 4 you get 6 mean is 6 for set 1
Set 2 if you do 5+10+7+42 you get 64 divide by 4 and you get 16 16-10.5 you get so 5.5 set is less than set 2 there ya go dude
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Answers
8×1000=
5.6×10=
5.6×100=
5.6×1000=
2.12×100=
Answers
When you multiply by 10, 100, or 1000, you must move the decimal place over by how many zeroes there are. Once there is no more decimals, you add 0's to the end of the number until you are done.
For example, 5.6 x 1000
1000 has 3 zeroes.
That means we need to move the decimal spot 3 times.
5.6 x 1000 = 56 x 100
We got rid of the decimal but we still have 2 zeroes left. So now we just add 2 zeroes at the end of the number.
5.6 x 1000 = 56 x 100 = 5600
I hope that helps! :)
Answers
even intergers are represetned as 2n where n is a whole number
odd=2n+1
consecutive odd integers are 2 apart from each other so therefor the numbers are 2n+1,2n+1+2, 2n+1+2+2 or 2n+1, 2n+3, 2n+5
so they add up to 111
2n+1+2n+3+2n+5=111
add like terms
6n+9=111
subtract 9 from both sides
6n=102
divide both sides by 6
n=17
numbers are
2n+1,2n+3,2n+5
subsitute
2(17)+1=34+1=35
therefor since the other sare 2 more
35,37,39 are the numbers
are there 3 that equal 1111? solve and see if it is true
2n+1+2n+3+2n+5=1111
add like terms
6n+9=1111
subtract 9 from both sides
6n=1102
divide both sides by 6
n=183.666666666666
n is not whole so the answer is NO
answer are 35,37,39 and NO
x
x+2
x+4
======(+)
3x+6=111
3x=105
x=35
the numbers are 35 37 39
the second problem has the same logic
x
x+2
x+4
=====(+)
3x+6=1111
3x=1105
x=368, (3) it's not an integer number
AND IT"S CORRECT EXCELLENCY!
TAKE A PIECE OF PAPER, A PEN AND DO IT FOR YOURSELF!
you don't need to write an essay for a simple math exercise
Answers
Answer:
1.7
Step-by-step explanation:
divide both numerator and denominator
Answer:
1 7/10
Step-by-step explanation:
4 1/4 ÷ 2 1/2
17/4 ÷2 1/2
17/4÷5/2
flip flop
17/4×2/5
17/2×1/5
17/2×5
17/10
1 7/10
Answers
B 170
C 200
D 250