Plz Help! ASAP!!!!Weights of eggs laid by two chickens are recorded for a full year. Both data sets follow a normal distribution.
Chicken A: Standard deviation of A is 4.6 grams; 68% of the eggs fall between 50.9 grams and 60.1 grams.
Chicken B: Standard deviation of B is 4.9 grams; 68% of the eggs fall between 51.9 grams and 61.7 grams.
The difference between the mean weight of Chicken B’s eggs and the mean weight of Chicken A’s eggs to the nearest tenth is...?
Answers
The difference between the meanweight of Chicken B's eggs and the mean weight of Chicken A's eggs to the nearest tenth is 1.8 grams.
What is a normal distribution?
A normaldistribution is a probability distribution that is symmetric around the mean, with most of the data points falling close to the mean and fewer data points falling farther away from it.
The shape of a normal distribution is often referred to as a bellcurve because when the distribution is graphed, the resulting curve resembles a bell
We have,
Since both datasets follow a normaldistribution, we can use the empirical rule (also known as the 68-95-99.7 rule) to find the mean weight of each chicken's eggs.
For Chicken A, we know that 68% of the eggs fall between 50.9 grams and 60.1 grams. This means that the mean weight of Chicken A's eggs is the average of these two values:
Mean of A = (50.9 + 60.1) / 2 = 55.0 grams
For Chicken B, we know that 68% of the eggs fall between 51.9 grams and 61.7 grams. This means that the mean weight of Chicken B's eggs is the average of these two values:
Mean of B = (51.9 + 61.7) / 2 = 56.8 grams
The difference between the meanweight of Chicken B's eggs and the mean weight of Chicken A's eggs is:
Difference = Mean of B - Mean of A
= 56.8 - 55.0
= 1.8 grams
Therefore,
The difference between the meanweight of Chicken B's eggs and the mean weight of Chicken A's eggs to the nearest tenth is 1.8 grams.
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Answer:
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Answer:
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