All realvalues of x where 1 < x < 4.
The graph of a function f is the set of all points inside the aircraft of the shape (x, f(x)). We can also define the graph of f to be the graph of the equation y = f(x). So, the graph of a character is a unique case of the graph of an equation.
For graphing functions, we need to plot its asymptotes, its x and y-intercepts, holes, and some factors on it by means of building a desk of values. Then simply join the factor by not touching the asymptotes and maintaining a observation of the area and range of the characteristic.
Learn more about Graphfunction here brainly.com/question/24992590
#SPJ2
Answer:
C
Step-by-step explanation:
all real values of x where 1 < x < 4
The pitcher was twice as old as the vase 14 years ago.
To find the number of years, x, ago when the pitcher was twice as old as the vase, we can set up an equation using their ages.
Let's say x years ago, the pitcher was twice as old as the vase.
So, the equation would be:
$(30 - x) = 2(22 - x)$
Simplifying the equation, we get:
$30 - x = 44 - 2x$
Combining like terms, we have:
$2x - x = 44 - 30$
$x = 14$
Therefore, the pitcher was twice as old as the vase 14 years ago.
#SPJ12
{(−1, 1), (−2, 2), (4, −4), (7, −7)}
The domain and range of the relation {(-1, 1), (-2, 2), (4, -4), (7, -7)} are {-1, -2, 4, 7} and {1, 2, -4, -7} respectively.
Not every relation is a function, but every function is a relation.
A function is a relation with clear boundaries.
When we say that something is well-defined, we mean that each element has been assigned a specific image.
The given set is,
{(-1, 1), (-2, 2), (4, -4), (7, -7)}
The domain of a set is the values of x,
Domain = {-1, -2, 4, 7}
The range of a set is the values of y,
Range = {1, 2, -4, -7}
The relation makes the function because for every value of x the sign of function y is negative,
The required function is,
y = -x.
To know more about Relation in function on:
#SPJ2
Answer:
(1, 3)
Step-by-step explanation:
Origin is the point (0,0) on the graph.
Distance between 2 points=
Hence using the formula above,
1) subst. x₂=0, y₂=0 and distance = √10
2) simplify expression and square both sides
So the answer could be any point in which the sum of the square of the x coordinate and the square of the y coordinate equals to 10.
When x₁= 1,
1² + (y₁)²= 10
1+ (y₁)² = 10
(y₁)²= 10 -1
(y₁)²= 9
y₁= ± √9
y₁= 3 or y₁= -3
Thus, the other point could be (1 ,3).