MATHEMATICS HIGH SCHOOL

Parallel lines s and t are cut by a transversal, r, as shown.Parallel lines s and t are cut by transversal r. Clockwise from top left, the angles formed by lines r and s are blank, (7 x minus 2) degrees, 1, blank; formed by lines r and t are blank, blank, blank, (6 x + 18) degrees.

What is the measure of angle 1?
20°
42°
138°
160°

Answers

Answer 1

Answer:

9514 1404 393

Answer:

42°

Step-by-step explanation:

The angles marked with x-expressions are alternate interior angles, so are congruent.

7x -2 = 6x +18

x = 20 . . . . . . . . add 2-6x

6x+18 = 6(20) +18 = 138

Angle 1 is supplementary to either of the x-expression angles, so is ...

∠1 = 180° -138°

∠1 = 42°

Answer 2

Answer:

Answer:

Step-by-step explanation:

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The answer to the polynomial

Answers

-Polynomials don't have answers.
This question just wants you to add 2 polynomials.
The pencil work under the first one is incorrect.

Here's what you need to do to find the sum of polynomials:

-- Remove parentheses.
(If there's a plus sign before the whole parentheses, then just erase the parentheses. If there's a minus sign before the whole thing, then change the sign of each term inside, and erase the parentheses.)

-- Add up all the x² terms.
Like this ...

x² + x² = 2x²
or
2x² + 7x² = 9x²

-- Add up all the x³ terms the same way.

-- Add up all the 'x' terms the same way.

-- Add up the plain numbers.

-- Write down all the sums as a new polynomial.

What is the value of x?

Answers

Answer:

x=70

Step-by-step explanation:

Since they are supplementary angles (180°)

45° + (2x-5)° = 180°

(2x-5)° = 180° - 45°

(2x-5)° = 135°

2x° = 135° + 5°

2x° = 140°

x° = 140/2°

x° = 70°

Since they are supplementary angles (180°)

45° + (2x-5)° = 180°

(2x-5)° = 180° - 45°

(2x-5)° = 135°

2x° = 135° - 5°

2x° = 130°

x° = 130/2°

x° = 65°

On a separate piece of paper sketch a unit circle with angle 0 in standard position. For what values of θ is the sine increasing? Decreasing? For what values of θ is the cosine increasing? Decreasing? For which angle between 0° and 360° is sine equal to 0? Where is cosine equal to 0? Please help(:

Answers

1) Sine is the y-component in the unit circle. It grows from 0 t o1 in the sector 0° to 90 °, then starts to decrease from 1 to -1 until 270° where it starts to increase again from 270° to 360° (0°=.

2) Cosine is the x - component in the unit circle. It decreases from 1 to - 1 in the sector 0° to 180°, and increases from -1 to +1 in the sector 180° to 360°.

3) Sine is equal to 0 at angles 0° and 180°.

4) Cosine is equal to 0 at angles 90° and 270°

What is the sum?

(9c-8) + (2c-6)

Answers

Answer:

The sum is 11c - 14.

11c−14 this is the answer good luck

Question 2(Multiple Choice Worth 4 points)(02.01 LC)
Figure EFGHK as shown below is to be transformed to figure E'F'G'H'K' using the rule (x, y) (x+8, y + 5):