MATHEMATICS COLLEGE

I am not understanding this question.

Answers

Answer 1

Answer:

Answer:

boardgamegeek.com/boardgame/245655/kings-dilemma

Step-by-step explanation:

Related Questions

Frans Summer job pays $200 per week. The circle graph shows how she spends the $200.50%savings10%movies15%other10%books15%clothingHow many dollars of Fran's weekly pay is spent on books and clothing?OA. $25OC. $50O D. $100OB. $30
Abigail invested $29,000 in an account paying an interest rate of 2.1% compoundedcontinuously. Assuming no deposits or withdrawals are made, how much money, tothe nearest dollar, would be in the account after 8 years?
What is the equation for this graph? Use y=mx+b
Four friends want to share two largepizzas equally. Each pizza is cut into ten slices. How many slices will each person get?
-3 < 5 true or false

The zeroes of the function are:
A) -2 and 0
B) 0 and 4
C) -2, 0, and 4

Answers

It would be C because they are the ones that función in , I think not sure

Which is bigger 0.159 or 1.590

Answers

Answer:

1.590

Step-by-step explanation:

Answer:

0.159

Step-by-step explanation:its obvious hope this helped tho

Evaluate the expression when a=-5 and y=7.

Answers

Step by step explanation:

_______________________________

Step 1:

$- 4a + y$

Write the equation

_______________________________

Step 2:

$= - 4 * ( - 5) + 7$

Insert the values of a ie -5 and y ie 7

_______________________________

Step 3:

$= + 20 + 7$

Multiply- 4 with -5 to get 20

_______________________________

Step 4:

$= 27$

add 20 with 7 to get 27

_______________________________

⚡Final answer: 27

hope it helped you:)

Answer:

27

Step-by-step explanation:

We are given that a = -5 and y = 7 and we are asked to evaluate the expression -4a + y.

To evaluate the expression, we would plug -5 for a and 7 for y into the expression.

-4a + y = -4(-5) + 7 = 20 + 7 = 27

So -4a + y = 27.

I hope you find my answer and explanation to be helpful. Happy studying. :)

Which of the following is a RATE?12 to 3

12 stickers to 3 students

Answers

Answer:

gfgfcvfvghcghccghcgcvchdcfgcfcfrtyc

Step-by-step explanation:

PLEASE HELP!!!!!
will mark brainliest!!!!!

Answers

Answer:

fx =1; then fx =2; then fx =4

Step-by-step explanation:

then plug the coordinates in as x is horizontal bar in top right then the fx

Pleeease open the image and hellllp me

Answers

1. Rewrite the expression in terms of logarithms:

$y=x^x=e^(\ln x^x)=e^(x\ln x)$

Then differentiate with the chain rule (I'll use prime notation to save space; that is, the derivative of y is denoted y' )

$y'=e^(x\ln x)(x\ln x)'=x^x(x\ln x)'$

$y'=x^x(x'\ln x+x(\ln x)')$

$y'=x^x\left(\ln x+\frac xx\right)$

$y'=x^x(\ln x+1)$

2. Chain rule:

$y=\ln(\csc(3x))$

$y'=\frac1{\csc(3x)}(\csc(3x))'$

$y'=\sin(3x)\left(-\cot^2(3x)(3x)'\right)$

$y'=-3\sin(3x)\cot^2(3x)$

Since $\cot x=(\cos x)/(\sin x)$ , we can cancel one factor of sine:

$y'=-3(\cos^2(3x))/(\sin(3x))=-3\cos(3x)\cot(3x)$

3. Chain rule:

$y=e^{e^(\sin x)}$

$y'=e^{e^(\sin x)}\left(e^(\sin x)\right)'$

$y'=e^{e^(\sin x)}e^(\sin x)(\sin x)'$

$y'=e^{e^(\sin x)+\sin x}\cos x$

4. If you're like me and don't remember the rule for differentiating logarithms of bases not equal to e, you can use the change-of-base formula first:

$\log_2x=(\ln x)/(\ln2)$

Then

$(\log_2x)'=\left((\ln x)/(\ln 2)\right)'=\frac1{\ln 2}$

So we have

$y=\cos^2(\log_2x)$

$y'=2\cos(\log_2x)\left(\cos(\log_2x)\right)'$

$y'=2\cos(\log_2x)(-\sin(\log_2x))(\log_2x)'$

$y'=-\frac2{\ln2}\cos(\log_2x)\sin(\log_2x)$

and we can use the double angle identity and logarithm properties to condense this result:

$y'=-\frac1{\ln2}\sin(2\log_2x)=-\frac1{\ln2}\sin(\log_2x^2)$

5. Differentiate both sides:

$\left(x^2-y^2+\sin x\,e^y+\ln y\,x\right)'=0'$

$2x-2yy'+\cos x\,e^y+\sin x\,e^yy'+\frac{xy'}y+\ln y=0$

$-\left(2y-\sin x\,e^y-\frac xy\right)y'=-\left(2x+\cos x\,e^y+\ln y\right)$

$y'=(2x+\cos x\,e^y\ln y)/(2y-\sin x\,e^y-\frac xy)$

$y'=(2xy+\cos x\,ye^y\ln y)/(2y^2-\sin x\,ye^y-x)$

6. Same as with (5):

$\left(\sin(x^2+\tan y)+e^(x^3\sec y)+2x-y+2\right)'=0'$

$\cos(x^2+\tan y)(x^2+\tan y)'+e^(x^3\sec y)(x^3\sec y)'+2-y'=0$

$\cos(x^2+\tan y)(2x+\sec^2y y')+e^(x^3\sec y)(3x^2\sec y+x^3\sec y\tan y\,y')+2-y'=0$

$\cos(x^2+\tan y)(2x+\sec^2y y')+e^(x^3\sec y)(3x^2\sec y+x^3\sec y\tan y\,y')+2-y'=0$

$\left(\cos(x^2+\tan y)\sec^2y+x^3\sec y\tan y\,e^(x^3\sec y)-1\right)y'=-\left(2x\cos(x^2+\tan y)+3x^2\sec y\,e^(x^3\sec y)+2\right)$

$y'=-(2x\cos(x^2+\tan y)+3x^2\sec y\,e^(x^3\sec y)+2)/(\cos(x^2+\tan y)\sec^2y+x^3\sec y\tan y\,e^(x^3\sec y)-1)$

7. Looks like

$y=x^2-e^(2x)$

Compute the second derivative:

$y'=2x-2e^(2x)$

$y''=2-4e^(2x)$

Set this equal to 0 and solve for x :

$2-4e^(2x)=0$

$4e^(2x)=2$

$e^(2x)=\frac12$

$2x=\ln\frac12=-\ln2$

$x=-\frac{\ln2}2$

Other Questions

Answer these 3 questions and ill give u brainliest and 5 stars and 15 points and a thank you

Automobile fuel efficiency is often measured in miles that the car can be driven per gallon of fuel (mpg). Heavier cars tend to have lower fuel efficiencies (lower mpg ratings). Which variable (weight or fuel efficiency) is most naturally considered the explanatory (predictor) variable in this context? A. Weight B. Fuel efficiency

Greg used 1 inch tiles to help make a ruler what mistake did he make

Which pair of variables would most likely have a negative correlation?A. the time spent driving in a car and the number of miles drivenB. the height of a dog in inches and the number of ounces of food the dog eats per dayC. the number of sit-ups completed and the number of calories burned during a workoutD. the time spent reading a book and the number of pages remaining to be read in the book