MATHEMATICS MIDDLE SCHOOL

Which is the simplified form of n Superscript negative 6 p cubed?StartFraction n Superscript 6 Over p cubed EndFraction
StartFraction 1 Over n Superscript 6 Baseline p cubed EndFraction
StartFraction p cubed Over n Superscript 6 EndFraction
n Superscript 6 Baseline p cubed

Answers

Answer 1
Answer:

Answer:

Third option. (p^3)/(n^(6))

Step-by-step explanation:

For this exercise you need to remember one of the properties for exponents.

There is a property called the "Negative property of exponents" which states the following:

b^(-n)=(1)/(b^n)

Where b \neq0

As you can observe,  b^n is the reciprocal of b^(-n)

In this case you have the following expression given in the exercise:

n^(-6)p^3

Observe the expression. As you can notice, the base "n" has a negative exponent, which is -6.

Therefore, applying the Negative property of exponents explained at the beginning of this explanation, you can simplify the expression.

Then, the simplified form of  n^(-6p^3) is the one shown below:

n^(-6)p^3=(p^3)/(n^(6))
Answer 2
Answer:

Answer:

C!

Step-by-step explanation:

it is

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5 times 7/8 then converted to simplest form?

Answers

5*7/8 = 4 3/8
5/1 * 7/8 = 35/8
convert into mixed number because numerator is bigger than the denominator so it it
4 3/8

What is the equation of the line that passes through the point 4,4 and has a slope of 0?

Answers

The equation of a line that passes through a point is an algebraic equation. It can also be referred to as the Slope-Intercept Equation.

The equation of the line that passes through the point (4, 4) and has a slope of 0 is written as: y = 4

The equation of the line through a point (x1, y1) can be represented by the algebraic equation:

y = mx + c

where:

m = slope

c = y - intercept

From the question,

(x1, y1) = (4, 4)

m = slope = 0

Substituting these values into the algebraic equation,

4 = (0 x 4) + c

 

Hence, y = 4

The equation of the line that passes through the point (4, 4) and has a slope of zero is y = 4

To learn more, visit the link below:

brainly.com/question/14045393

Answer:

y = 0x + 4 or y = 4.

Step-by-step explanation:

The slope is zero, and in other words, m = 0.

The slope intercept form is y = mx + b.

Replace m with 0.

y = 0m + b.

The y intercept is the y point on the line. Since this slope is a straight horizontal line, the y point given is the y intercept. b is the y intercept.

y = 0m + 4

Since any number times 0 is 0 you can right it as

y = 4.

This is the 2nd problem

Answers

x=4y+6\nx-3y=4\n\n4y+6-3y=4\ny=-2\n\nx=4\cdot(-2)+6\nx=-8+6\nx=-2\n\n\boxed{(x,y)=(-2,-2)}

What is 4 times 210 using distributive property

Answers

Answer:

I believe the answer would be 840

Step-by-step explanation:

Verify 2+2cot^2x=2cotxsecxcscx

Answers

2+2\cot^2x=2\cot x\sec x\csc x\n\nL=2(1+\cot^2x)=2\left(1+(\cos^2x)/(\sin^2x)\right)=2\left((\sin^2x)/(\sin^2x)+(\cos^2x)/(\sin^2x)\right)\n\n=2\left((\sin^2x+\cos^2x)/(\sin^2x)\right)=2\left((1)/(\sin^2x)\right)=(2)/(\sin^2x)\n\nR=2\left((\cos x)/(\sin x)\right)\left((1)/(\cos x)\right)\left((1)/(\sin x)\right)=2\left((1)/(\sin x)\right)\left((1)/(1)\right)\left((1)/(\sin x)\right)\n\n=2\left((1)/(\sin^2x)\right)=(2)/(\sin^2x)

\boxed{L=R}

Used:\n\n\cot x=(\cos x)/(\sin x)\n\n\sin^2x+\cos^2x=1\n\n\sec x=(1)/(\cos x)\n\n\csc x=(1)/(\sin x)

Please Solve:Adding and Subtracting PolymonialsAdd:  (–6 – n + 2n2) + (8 – 3n – 10n2)   
A.–2 – 4n – 8n2  
B.2 – 2n – 8n2  
C.2 – 4n – 8n2  
D.–2 – 2n – 8n2

Add:  (8x + 2y – 3z – 4) + (–4x – 5y + 4z + 6)  
A.–4x + 3y – z + 2  
B.4x – 3y – z + 2  
C.–4x + 3y –z – 2  
D.4x – 3y + z + 2

Subtract and simplify: (2p^2q – 3pq^2 + q^3) – (p^2q + q^3)  
A.p^2q – 3pq^2  
B.2p^2q – 3pq^2  
C.p^2q – 3pq^2+2q^3  
D.p^2q – 2pq^2

Subtract and simplify: (–y^2 – 3y – 5) – (–3y^2 – 7y + 4)  
A.2y^2 – 10y + 4  
B.2y^2 + 4y – 9  
C.–2y^2 – 10y – 1  
D.2y^2 – 7y – 9

Subtract and simplify: (10x^4 – 2x + 7) – (6x^4 + 2x^3 – 4x^2 – 1) 
A.4x^4 – 2x^3 + 4x^2 – 2x + 6  
B.4x^4 + 2x^3 – 4x^2 – 2x + 8  
C.4x^4 – 2x^3 + 4x^2 – 2x + 8  
D.16x^4 + 2x^3 + 4x^2 – 2x + 8

Answers

Add:\n \n (-6-n + 2n^2) + (8 - 3n - 10n^2) =\n \n= -6-n + 2n^2 + 8 - 3n - 10n^2 =\n \n=2 - 4n -8n^2 \n \n Answer : \ C. \ \ \2 - 4n - 8n2


Add: \n \n (8x + 2y - 3z -4) + (-4x - 5y + 4z + 6) = \n \n =8x + 2y - 3z -4 -4x - 5y + 4z + 6=\n \n=4 x - 3 y + z + 2 \n \n Answer : \ D. \ \ \ 4x - 3y + z + 2


Subtract \ and \ simplify: \n\n (2p^2q - 3pq^2 + q^3) -(p^2q + q^3)=\n \n= 2p^2q - 3pq^2 + q^3 - p^2q -q^3 = \n \n= p^2q - 3pq^2 \n \n Answer : \ A. \ \ \ \ p^2q - 3pq^2


Subtract \ and \ simplify: \n\n (-y^2 - 3y-5) - (-3y^2 - 7y + 4)= \n \n= -y^2 - 3y-5+3y^2 +7y- 4 =\n \n=2y^2+4y-9 \n \nAnswer : \ B.\ \ \ \ 2y^2 + 4y - 9


Subtract \ and \ simplify: \n\n (10x^4 -2x + 7)-(6x^4 + 2x^3 -4x^2 - 1) = \n \n = 10x^4 -2x + 7 - 6x^4 - 2x^3 +4x^2 + 1=\n \n=4x^4 -2x^3 +4x^2-2x + 8 \n \nAnswer : \ C. \ \ \ \4x^4 -2x^3 + 4x^2- 2x + 8
 
1)\n(-6-n + 2n^2) + (8-3n-10n^2) =2-4n-8n^2\ \ \ \Rightarrow\ \ \ Ans.\ C\n\n2)\n(8x+2y-3z-4)+(-4x-5y+4z+6)=4x-3y+z+2\ \Rightarrow\ Ans.D\n\n3)\n(2p^2q-3pq^2+q^3)-(p^2q + q^3) =p^2q-3pq^2\ \ \ \Rightarrow\ \ \ Ans.\ A\n\n4)\n (-y^2-3y-5)-(-3y^2-7y + 4) =-y^2-3y-5+3y^2+7y - 4=\n.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =2y^2+4y-9\ \ \ \Rightarrow\ \ \ Ans.\ B\n

5)\n(10x^4-2x + 7)-(6x^4 + 2x^3-4x^2-1) =\n=10x^4-2x + 7-6x^4 - 2x^3+4x^2+1=\n=4x^4-2x^3+4x^2-2x+8\ \ \ \Rightarrow\ \ \ Ans.\ C
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