Suppose you observe a binary system containing a main-sequence star and a brown dwarf. The orbital period of the system is 1 year, and the average separation of the system is 1 AUAU . You then measure the Doppler shifts of the spectral lines from the main-sequence star and the brown dwarf, finding that the orbital speed of the brown dwarf in the system is 22 times greater than that of the main-sequence star.

Answers

Answer 1

Answer:

Final answer:

In a binary system with a main-sequence star and a brown dwarf, we can determine their masses by analyzing their radial velocity curve and measuring the Doppler shifts of their spectral lines. Kepler's law can then be used to calculate the sum of their masses.

Explanation:

The question is about a binary system containing a main-sequence star and a brown dwarf. We can determine the masses of the stars in a spectroscopic binary by analyzing their radial velocity curve. By measuring the Doppler shifts of the spectral lines, we can calculate the orbital speed of each star and use Kepler's law to calculate the sum of their masses.

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Answer 2

Answer:

Final answer:

The orbital speed and separation of a binary system composed of a main-sequence star and a brown dwarf can be utilized to infer their respective masses. This is accomplished by studying the Doppler effect from the spectral lines of the system and applying Kepler's third law. Greater mass is found to exhibit slower orbital speed.

Explanation:

The main-sequence star and the brown dwarf form a binary system with an orbital period of 1 year and an average separation of 1 Astronomical Unit (AU). The Doppler shifts of the spectral lines from the main-sequence star and the brown dwarf indicate that the orbital speed of the brown dwarf in the system is 22 times greater than that of the main-sequence star.

We can estimate the masses of the stars in this binary system using the formula based on Newton's reformulation of Kepler's third law: D³ = (M₁ + M₂)P², where D represents the semimajor axis in AU and P represent the period in years. From this, we can calculate the sum of the masses of the two stars. Given the difference in orbital speeds, the main-sequence star has a higher mass to result in a slower speed, and the brown dwarf has a smaller mass to result in the higher speed.

In conclusion, by analyzing the radial velocity curve and using Kepler's third law, we can estimate the masses of the stars in a binary system.

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Is paper a good water absorbent ?

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paper is not a good water absorbant.

What is the exact meaning of croos section and cross sectional area of a conductor?

Answers

The cross section is the little tiny circle you see when you cut a wire
and look at the flat, cut end.

The cross-sectional area of the wire is the area of that little circle.
It's equal to

Area = (pi) x (1/4) x (Diameter of the wire)²

A boat is headed due east across a river at a velocity of 25 meters/second with respect to the water. The velocity of the river current is 2.7 meters/second due north. What is the angle at which the boat will deviate from its original path?

Answers

V(b-w)= 25i +0j

V(w) = 0i +2.7j

The resultant velocity V(b -w) =Vb -Vw

Therefore Vb = 25i+2.7j

The angle is calculated as follows:

ArcTan 2.7/25 = 6.16 degrees

The angle at which the boat will deviate from its original path would be 6.2 degrees. Hope this answers the question. Have a nice day.

Answer:

6.2

Explanation:

plato user

When a squid pushes against the water, the squid moves forward because the ______________ pushes against the _______________.

Answers

Answer:

water pushes against the squid

4. Which problem is most likely to result from the use of nuclear power?O A. storage of radioactive wastes
B. miners getting trapped underground
C. oil spills that pollute oceans and beaches
O D. pollutants in the groundwater after drilling

Answers

Answer:

i think it is A

Explanation

If anyone knows how to do any of these PLEASE help me....im am so confused rn and our teacher sucks at explaining this stuff......

Answers

take 68.2/60 = 1.137 hr
take 56.9/1.137 = 50.043 mi/hr

take 189/211 = 0.896

24.8/2 = 12.4 m
12.4/82.3 = 0.15s

Well, five answers for only five points is pretty slim. But I've already got
a lot of points, and your plea for help sounds so desperate, that I think
I ought to jump in here and relieve some of your pain.

These aren't difficult problems. The bummer is that whoever wrote them
got so interested in his dinosaur stories that he kind of hid the actual Math
and Physics under all kinds of stuff that doesn't matter.

1).   Speed = (distance covered) / (time to cover the distance)

   =    (56.9 miles) / (68.2 minutes)

   = (56.9 / 68.2) miles/minute

   = 0.834 mile per minute.

BUT ... the question wants to know the speed in 'mph' ... miles per hour.

Well ... there are 60 minutes in an hour. If 0.834 mile in covered in 1 minute,
then 60 times as much would be covered in 1 hour.

(0.834 mile/minute) x (60 minute/hour) = 50.06 mile/hour

Rounded to no decimal places = 50 mph

2). Use the same formula:

   Speed = (distance covered) / (time to cover the distance)

   = (189 meters) / (211 seconds)

   = (189 / 211) meters/seconds

   = 0.8957 meters/second

   Round to 3 decimal places: 0.896 m/s

3). The attacker jumped from 24.8 meters away.
   He already covered half of the distance.
   How far away is he now ? 1/2 of 24.8 m = 12.4 m .
   He still has 12.4 meters left to go.

   He's moving at 82.3 meters per second.
   When will he arrive here ?

   Time = (distance) / (speed)

=    (12.4 meters) / (82.3 m/s)

=    (12.4 / 82.3) seconds

=    0.1506 second

   Two decimal places:    0.15 second

4).    Distance = (speed) x (time)

= ( 237 km/hr) x (16.8 seconds) .

Do you see the problem here ? We have the distance covered in an hour,
but we need to know how much distance is covered in only 16.8 seconds.
We really need to work out the speed in (meters per second).

OK. 237 km = 237,000 meters, so the speed is 237,000 meters/hour.

1 hour is 3,600 seconds.
So the speed is only one 3600th of 237,000 meters in 1 second.

   (237,000 meters/hour) x (1 hour / 3600 seconds) = 65.8333 m/s

   Distance = (speed) x (time)

      = (65.8333 meter/second) x (16.8 seconds)

    = (65.8333 x 16.8) meters

= 1106 meters.

5). This is a nasty trick question. The whole story is irrelevant,
and we don't even care how far Vinny dropped.

Anything that drops on Earth falls with the acceleration of gravity.
It doesn't matter how big or heavy or small or light it is.
Everything falls with the acceleration of gravity on Earth ... about 9.8 m/s² .

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