Answer:
The correct answers are
1) There must be at least 10 observed successes and 10 observed failures in the sample from population 1.
3) There must be at least 10 observed successes and 10 observed failures in the sample from population 2.
Step-by-step explanation:
Hello!
You have two variables of interest:
X₁: Number of that had to put off medical treatment due to cost during 2016.
n₁= 967 people surveyed
x₁= 184 answered "yes"
sample proportion p'₁= 184/967= 0.19
X₂: Number of that had to put off medical treatment due to cost during 2019.
n₂= 1015 people surveyed
x₂= 253 answered "yes"
p'₂= 253/1015= 0.25
The pooled sample proportion is
To study the population proportion you have to apply the Central Limit Theorem to approximate the distribution of the sample proportion to normal, the conditions for a valid approximation are:
Sample size n ≥ 30
n₁= 967
n₂= 1015
n*p'≥10 (each sample contains at least 10 successes)
n₁*p'₁= 967*0.19= 183.73
n₂*p'₂= 1015*0.25= 253.75
n*(1-p')≥10 (each sample contains at least 10 failures)
n₁*(1-p'₁)= 967*0.81= 783.27
n₂*(1-p'₂)= 1015*0.75= 761.25
The correct answers are
1) There must be at least 10 observed successes and 10 observed failures in the sample from population 1.
3) There must be at least 10 observed successes and 10 observed failures in the sample from population 2.
I hope it helps!
Answer:
-4(2t+1)(2t-7)
Step-by-step explanation:
First factor out the common term -4
Then factor out -4^2
Answer:
the answer is( -42t+1)(2t-7)
Answer:8%
Step-by-step explanation:
8% of her income because I did
280
-----
3500
=
X
------
100 ( Sorry if I'm wrong <3 )
longer side yd
What is this area?
yd2
Answer:
Shorter side = 755 yd
longer side = 1510 yd
A(max) = 1140050 yd²
Step-by-step explanation:
The owner has 3020 yd of fencing
Lets assume:
x the shorter side of the rectangle ( we will use fencing in two sides of length x )
y the longer one
A area of the rectangle and P the perimeter of the rectangle ( we have only three sides covered by fencing material)
We have: A = x * y P = 2 * x + y ⇒ y = P - 2*x ⇒ y = 3020 - 2* x
A (x) = x * ( 3020 - 2*x) ⇒ A(x) = 3020 * x - 2* x²
Taken derivative
A´(x) = 3020 - 4 * x
If A´(x) = 0 3020 -4*x = 0 ⇒4*x = 3020 x = 755 yd
If we take second derivative A´´(x) = -4
so A´´(x) < 0 so there is a maximun in point x = 755
Then
Rectangle dimensions :
x = 755 yd ⇒ y = 3020 - 2 * x ⇒ y = 3020 - 2 * (755) y = 1510 yd
Maximum area is : A(max) = 1510 * 755 ⇒ A(max) = 1140050 yd²
To get the largest area, 3020 yards of fencing is divided equally to form a rectangular grazing piece. Each side is 1510 yards, leading to a total area of 2,280,100 square yards.
We are given a total of 3020 yards of fencing which is used to fence two sides of a rectangle, with a river enclosing the third side. The largest area of a rectangle is obtained when the rectangle is a square. However, since one of the sides is the river, and hence not fenced, the rectangle is not square but should be as close to a square as possible to give the maximum area.
The optimum distribution is dividing the fence into two equal parts for both sides of the rectangle, so each side will be 3020 / 2 = 1510 yds. The dimensions of the largest area he can enclose are: shorter side = yd, longer side = 1510 yds.
The area of this rectangular grazing land would then be 1510 yd * 1510 yd = 2,280,100 yd2.
#SPJ3
Answer:
f(x)=4(x-(-3))+7
Step-by-step explanation:
vertex form= f(x)=a(x-h)^2 +k
vertex= (h,k)
x=-2
f(x)=11
plug in all the variables
11=a(-2-(-3))^2 +7
simplify the right side
11=a(1)^2+7
11=a+7
subtract 7
4=a
equation= f(x)=4(x-(-3))+7
ways
Answer:
17160
Step-by-step explanation:
first there are 13 options
then there are 13 - 1 that was chosen
then there are 13 - 2 that were chosen
then there are 13 - 3 that were chosen
so that's 13 options, then 12 options, then 11 options, and then 10 options
and in order to figure out all of the possibilties we mutiply the options so
13*12*11*10 = 17160
little further explaining of why this works:
we have a set of letters (3 in a set)
A B C
what are the possible combinations?
AB
AC
BC
BA
CA
CB
the answer is 6 which is also 3 * 2 * 1 = 6
HOPE THAT HELPS!1! ^_^