Answer:x equals 4
Step-by-step explanation:
Using continuity concepts, it is found that the function is left-continuous at x = 1.
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A function f(x) is said to be continuous at x = a if:
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The piece-wise definition of the function is:
We have to check the continuity at the points in which the definitions change, that is, x = 0 and x = 1.
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At x = 0:
Since the limits are equal, and also equal to the definition at the point, the function is continuous at x = 0.
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At x = 1:
To the right, the limit is different, thus, the function is only left continuous at x = 1.
A similar problem is given at brainly.com/question/21447009
Answer:
the function is continuous from the left at x=1 and continuous from the right at x=0
Step-by-step explanation:
a function is continuous from the right , when
when x→a⁺ lim f(x)=f(a)
and from the left when
when x→a⁻ lim f(x)=f(a)
then since the functions presented are continuous , we have to look for discontinuities only when the functions change
for x=0
when x→0⁺ lim f(x)=lim e^x = e^0 = 1
when x→0⁻ lim f(x)=lim (x+4) = (0+4) = 4
then since f(0) = e^0=1 , the function is continuous from the right at x=0
for x=1
when x→1⁺ lim f(x)=lim (8-x) = (8-0) = 8
when x→1⁻ lim f(x)=lim e^x = e^1 = e
then since f(1) = e^1=e , the function is continuous from the left at x=1
b. How long does it take the rock to reach its highest point?
c. How high does the rock go?
d. How long does it take the rock to reach half its maximum height?
e. How long is the rock a loft?
Answer:
a. The rock's velocity is and the acceleration is
b. It takes 22.5 seconds to reach the highest point.
c. The rock goes up to 405 m.
d. It reach half its maximum height when time is 6.59 s or 38.41 s.
e. The rock is aloft for 45 seconds.
Step-by-step explanation:
a.
The rock's velocity is the derivative of the height function
The rock's acceleration is the derivative of the velocity function
b. The rock will reach its highest point when the velocity becomes zero.
It takes 22.5 seconds to reach the highest point.
c. The rock reach its highest point when t = 22.5 s
Thus
So the rock goes up to 405 m.
d. The maximum height is 405 m. So the half of its maximum height =
To find the time it reach half its maximum height, we need to solve
For a quadratic equation of the form the solutions are
It reach half its maximum height when time is 6.59 s or 38.41 s.
e. It is aloft until s(t) = 0 again
The rock is aloft for 45 seconds.
The question is incomplete. Here is the complete question.
On the package for a certain brand of spinach seeds there is a guarantee that, if the printed instructions are followed, 63% of planted seeds will germinate. A random sample of 9 seeds is chosen. If these seeds are planted according to the instructions, find the probability that 4 or 5 of them germinate. Do not round your intermiediate computations, and round your answer to three decimal places.
Answer: P(4<X<5) = 0.624
Step-by-step explanation: The probability of a seed germinate is a BinomialDistribution, i.e., a discrete probability distribution of the number of successes in a sequence of n independents experiments.
This distribution can be approximated to normal distribution by determining the values of mean and standard deviation population:
where
n is the sample quantity
p is proportion of successes
For the spinach seeds:
Mean is
5.85
Standard deviation is
1.431
Now, use
to convert into a standard normal distribution.
The probability we want is between 2 values: P(4<X<5).
Therefore, we have to convert those two values:
For X = 4:
z = -1.29
For X = 5:
z = -0.59
Using z-table:
P(X>4) = 1 - P(z< -1.29) = 0.9015
P(X<5) = P(z< -0.59) = 0.2776
The probability will be
P(4<X<5) = P(X>4) - P(X<5)
P(4<X<5) = 0.9015 - 0.2776
P(4<X<5) = 0.624
The probability of 4 or 5 seeds germinate is0.624.
For ten weeks, City A received less rainfall, on average, than City B.
The range between the maximum and minimum values for City B is greater than the range between maximum and minimum values for City A.
During the 10 wk period, the rainfall amount recorded most often for City B was 1 in.
The median for City A is less than the median for City B.
Answer:
During the 10 wk period, the rainfall amount recorded most often for City B was 1 in.
Step-by-step explanation:
Given the data :
City A :
Reordered data:
0, 0.2, 0.2, 0.3, 0.4, 1, 1.3, 1.5, 2.5, 3
City B :
Reordered data:
0, 0, 0.1, 0.1, 0.2, 0.3, 0.4, 1, 1, 1
Using a calculator :
Mean Rainfall for City A = 1.04
Mean rainfall for city B = 0.41
Range : maximum - minimum
City A = 3 - 0 = 3
City B = 1 - 0 = 1
Mode (most occurring) :
City A = 0.2
City B = 1
Median :
City A = 0.7
City B = 0.25
The only true conclusion in the options given that can be drawn from the data is that ;During the 10 wk period, the rainfall amount recorded most often for City B was 1 in.
Answer:
the Answer is C.
Step-by-step explanation:
I just took the test
Answer:
6 and 7
Step-by-step explanation:
I think you mean 'the sq rt of 48 lies between what 2 integers.'
The answer is 6 and 7.