13x = 15x - 8

What is the value of X?

Answers

Answer 1
Answer:

Answer:x equals 4

Step-by-step explanation:


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Find each x-value at which f is discontinuous and for each x-value, determine whether f is continuous from the right, or from the left, or neither. f(x) = x + 4 if x < 0 ex if 0 ≤ x ≤ 1 8 − x if x > 1 x = (smaller value) continuous from the right continuous from the left neither

Answers

Using continuity concepts, it is found that the function is left-continuous at x = 1.

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A function f(x) is said to be continuous at x = a if:

\lim_(x \rightarrow a^(-)) f(x) = \lim_(x \rightarrow a^(+)) f(x) = f(a)

  • If only \lim_(x \rightarrow a^(-)) f(x) = f(a), the function is left-continuous.
  • If only \lim_(x \rightarrow a^(+)) f(x) = f(a), the function is right-continuous.

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The piece-wise definition of the function f(x) is:

x + 4, x < 0

x, 0 \leq x \leq 1

8 - x, x > 1

We have to check the continuity at the points in which the definitions change, that is, x = 0 and x = 1.

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At x = 0:

  • The definition at 0 is f(0) = 0
  • Approaching x = 0 from the left, we have values less than 0, thus:

\lim_(x \rightarrow 0^(-)) f(x) = \lim_(x \rightarrow 0) x + 4 = 0 + 4 = 0

  • Approaching x = 0 from the right, we have values greater than 0, thus:

\lim_(x \rightarrow 0^(+)) f(x) = \lim_(x \rightarrow 0) x = 0

Since the limits are equal, and also equal to the definition at the point, the function is continuous at x = 0.

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At x = 1:

  • The definition at 1 is f(1) = 1
  • Approaching x = 1 from the left, we have values less than 1, thus:

\lim_(x \rightarrow 1^(-)) f(x) = \lim_(x \rightarrow 1) x = 1

  • Approaching x = 1 from the right, we have values greater than 1, thus:

\lim_(x \rightarrow 1^(+)) f(x) = \lim_(x \rightarrow 1) 8 - x = 8 - 1 = 7

To the right, the limit is different, thus, the function is only left continuous at x = 1.

A similar problem is given at brainly.com/question/21447009

Answer:

the function is continuous from the left at x=1 and continuous from the right at x=0

Step-by-step explanation:

a function is continuous from the right , when

when x→a⁺ lim f(x)=f(a)

and from the left when

when x→a⁻ lim f(x)=f(a)

then since the functions presented are continuous , we have to look for discontinuities only when the functions change

for x=0

when x→0⁺ lim f(x)=lim  e^x = e^0 = 1

when x→0⁻ lim f(x)=lim  (x+4) = (0+4) = 4

then since f(0) = e^0=1 , the function is continuous from the right at x=0

for x=1

when x→1⁺ lim f(x)=lim  (8-x) = (8-0) = 8

when x→1⁻ lim f(x)=lim e^x = e^1 = e

then since f(1) = e^1=e , the function is continuous from the left at x=1

A rock thrown vertically upward from the surface of the moon at a velocity of 36​m/sec reaches a height of s = 36t - 0.8 t^2 meters in t sec.a. Find the​ rock's velocity and acceleration at time t.
b. How long does it take the rock to reach its highest​ point?
c. How high does the rock​ go?
d. How long does it take the rock to reach half its maximum​ height?
e. How long is the rock​ a loft?

Answers

Answer:

a. The rock's velocity is v(t)=36-1.6t \:{(m/s)}  and the acceleration is a(t)=-1.6  \:{(m/s^2)}

b. It takes 22.5 seconds to reach the highest point.

c. The rock goes up to 405 m.

d. It reach half its maximum height when time is 6.59 s or 38.41 s.

e. The rock is aloft for 45 seconds.

Step-by-step explanation:

  • Velocity is defined as the rate of change of position or the rate of displacement. v(t)=(ds)/(dt)
  • Acceleration is defined as the rate of change of velocity. a(t)=(dv)/(dt)

a.

The rock's velocity is the derivative of the height function s(t) = 36t - 0.8 t^2

v(t)=(d)/(dt)(36t - 0.8 t^2) \n\n\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\n\nv(t)=(d)/(dt)\left(36t\right)-(d)/(dt)\left(0.8t^2\right)\n\nv(t)=36-1.6t

The rock's acceleration is the derivative of the velocity function v(t)=36-1.6t

a(t)=(d)/(dt)(36-1.6t)\n\na(t)=-1.6

b. The rock will reach its highest point when the velocity becomes zero.

v(t)=36-1.6t=0\n36\cdot \:10-1.6t\cdot \:10=0\cdot \:10\n360-16t=0\n360-16t-360=0-360\n-16t=-360\nt=(45)/(2)=22.5

It takes 22.5 seconds to reach the highest point.

c. The rock reach its highest point when t = 22.5 s

Thus

s(22.5) = 36(22.5) - 0.8 (22.5)^2\ns(22.5) =405

So the rock goes up to 405 m.

d. The maximum height is 405 m. So the half of its maximum height = (405)/(2) =202.5 \:m

To find the time it reach half its maximum height, we need to solve

36t - 0.8 t^2=202.5\n36t\cdot \:10-0.8t^2\cdot \:10=202.5\cdot \:10\n360t-8t^2=2025\n360t-8t^2-2025=2025-2025\n-8t^2+360t-2025=0

For a quadratic equation of the form ax^2+bx+c=0 the solutions are

x_(1,\:2)=(-b\pm √(b^2-4ac))/(2a)

\mathrm{For\:}\quad a=-8,\:b=360,\:c=-2025:\n\nt=(-360+√(360^2-4\left(-8\right)\left(-2025\right)))/(2\left(-8\right))=(45\left(2-√(2)\right))/(4)\approx 6.59\n\nt=(-360-√(360^2-4\left(-8\right)\left(-2025\right)))/(2\left(-8\right))=(45\left(2+√(2)\right))/(4)\approx 38.41

It reach half its maximum height when time is 6.59 s or 38.41 s.

e. It is aloft until s(t) = 0 again

36t - 0.8 t^2=0\n\n\mathrm{Factor\:}36t-0.8t^2\rightarrow -t\left(0.8t-36\right)\n\n\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}\n\nt=0,\:t=45

The rock is aloft for 45 seconds.

On the package for a certain brand of spinach seeds there is a guarantee that, if the printed instructions are followed, of planted seeds will germinate. A random sample of seeds is chosen. If these seeds are planted according to the instructions, find the probability that of them germinate.

Answers

The question is incomplete. Here is the complete question.

On the package for a certain brand of spinach seeds there is a guarantee that, if the printed instructions are followed, 63% of planted seeds will germinate. A random sample of 9 seeds is chosen. If these seeds are planted according to the instructions, find the probability that 4 or 5 of them germinate. Do not round your intermiediate computations, and round your answer to three decimal places.

Answer: P(4<X<5) = 0.624

Step-by-step explanation: The probability of a seed germinate is a BinomialDistribution, i.e., a discrete probability distribution of the number of successes in a sequence of n independents experiments.

This distribution can be approximated to normal distribution by determining the values of mean and standard deviation population:

\mu=np

\sigma=√(np(1-p))

where

n is the sample quantity

p is proportion of successes

For the spinach seeds:

Mean is

\mu=9(0.65)

\mu= 5.85

Standard deviation is

\sigma=√(9.0.65(1-0.65))

\sigma= 1.431

Now, use

z=(x-\mu)/(\sigma)

to convert into a standard normal distribution.

The probability we want is between 2 values: P(4<X<5).

Therefore, we have to convert those two values:

For X = 4:

z=(4-5.85)/(1.431)

z = -1.29

For X = 5:

z=(5-5.85)/(1.431)

z = -0.59

Using z-table:

P(X>4) = 1 - P(z< -1.29) = 0.9015

P(X<5) = P(z< -0.59) = 0.2776

The probability will be

P(4<X<5) = P(X>4) - P(X<5)

P(4<X<5) = 0.9015 - 0.2776

P(4<X<5) = 0.624

The probability of 4 or 5 seeds germinate is0.624.

Find the value of x. Round to the nearest tenth.

Answers

36
i think. hope it helped sorrh if it’s wrong i’m not good at math

Which conclusion can be drawn from the data?Question 9 options:

For ten weeks, City A received less rainfall, on average, than City B.


The range between the maximum and minimum values for City B is greater than the range between maximum and minimum values for City A.


During the 10 wk period, the rainfall amount recorded most often for City B was 1 in.


The median for City A is less than the median for City B.

Answers

Answer:

During the 10 wk period, the rainfall amount recorded most often for City B was 1 in.

Step-by-step explanation:

Given the data :

City A :

Reordered data:

0, 0.2, 0.2, 0.3, 0.4, 1, 1.3, 1.5, 2.5, 3

City B :

Reordered data:

0, 0, 0.1, 0.1, 0.2, 0.3, 0.4, 1, 1, 1

Using a calculator :

Mean Rainfall for City A = 1.04

Mean rainfall for city B = 0.41

Range : maximum - minimum

City A = 3 - 0 = 3

City B = 1 - 0 = 1

Mode (most occurring) :

City A = 0.2

City B = 1

Median :

City A = 0.7

City B = 0.25

The only true conclusion in the options given that can be drawn from the data is that ;During the 10 wk period, the rainfall amount recorded most often for City B was 1 in.

Answer:

the Answer is C.

Step-by-step explanation:

I just took the test

1) Between which two integers does the square root of 48 lie? *

Answers

Answer:

6 and 7

Step-by-step explanation:

I think you mean 'the sq rt of 48 lies between what 2 integers.'

The answer is 6 and 7.