MATHEMATICS HIGH SCHOOL

It is given that y is directly proportional to x raise to power n and write down the value of n when y metre square is area of a square of length x metre

Answers

Answer 1
Answer:

Answer:

The correct answer is 2.

Step-by-step explanation:

Given y is directly proportional to x raised to the power n.

⇒ y \alphax^(n)

⇒ y = p × x^(n) with p being the constant of proportion.

Let y be the area of a square of side x meters.

Therefore y = x^(2) square meters.

Now according to the given problem, comparing both the above mentioned equation we get the value of n equal to 2.

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I need some help in this problem...
-2/3x=-468/17

Answers

do you need to factor? solve for x?
Multiply both sides by 3/(-2).
x=702/17

PLEASE HELP ITS DUE TMR

Answers

Answer:

3 pigs

Step-by-step explanation:

First split the shape into two rectangles to find the area. On the left you can make the rectangle 10*7 and on the right subtract 7 from 16 to get 9 so the one on the right is 9*6. Find the area of both rectangles by multiplying, which will get you 70 and 54 respectively. Add these to get 124 square meters of space in the field. Now you will have to divide it by 36 to see how many pigs can fit, which results in the answer 3.4444... Round down to get 3 pigs as you can not fit another pig in the .4444... of space.

Each hour, the number of bacteria in Dr. Nall’s petri dish tripled. What percent is the population compared to the population the hour before?A. 3%
B. 30%
C. 130%
D. 300%

Answers

Answer:

Option D. 300%

Step-by-step explanation:

Let the number of bacteria in Dr Nall's petri dish = x

After one hour number of bacteria in the petri dish = 3x

So the percentage of the population compared to the population the hour before will be

= \frac{\text{Population after 1 hour}}{\text{Population before 1 hour}}* 100

= (3x)/(x)* 100

= 300%

Therefore, Option D. will be the answer.
THE ANSWER IS THE D!!!!!!!!!!!!

A coin is tossed and a six​-sided die numbered 1 through
6 is rolled. Find the probability of tossing a
head and then rolling a number greater than 4.

Answers

The probability of tossing a head and then rolling a number greater than 4 is 1/6. The probability says the number of possible outcomes from the total outcomes of an event.

What is probability?

The probability is defined as the ratio of the count of the favorable outcomes to the total count of the outcomes of the sample.

P(A) = n(A)/n(S)  where A is n event, n(S) is the total count of the sample, and n(A) is the count of favorable outcomes.

Calculating the probability:

The given events are tossing a coin and rolling a dice.

The favorable outcomes for these events are given as tossing a head and rolling a number greater than 4.

Calculating the probability of tossing a coin:

The total outcomes of the event are 2 (head and tail)

The favorable outcome = 1 (only head)

So, the probability of tossing a head = 1/2

Calculating the probability of rolling a dice:

The total outcomes of the event are 6 ( a dice has 6 faces with a number on each face (1 to 6))

So, there are only two numbers that are greater than 4 (5, 6)

The favorable outcomes = 2

So, the probability of rolling a numbergreater than 4 = 2/6 =1/3

Calculating the probability of two events at the same time:

To get this probability- multiply both the probabilities.

⇒ 1/2 × 1/3 =1/6

Therefore, the required probability is 1/6.

Learn more about probabilities here:

brainly.com/question/10837034

#SPJ2
tossing a head = 1/2
rolling a number greater then 4 = 2/6 = 1/3

1/2 * 1/3 = 1/6 <==

What is the common ratio of the geometric sequence whose second and fourth terms are 6 and 54, respectively?

Answers

Hi there! T4=T2×r²,6r²=54. Therefore, the answer would be 3.
a₂ = 6      a₄ = 54

a_(n) = q^(n-1) * a_(1) 

\left \{ {{ a_(2) = q^(2-1) * a_(1) } \atop { a_(4) = q^(4-1)* a_(1) }} \right. \n \n \left \{ {{6 = q * a_(1) } \atop {54 = q^(3) * a_(1) }} \right. \n \n \left \{ {{ a_(1) = (6)/(q) } \atop {54 = q^(3) * (6)/(q) }} \right. \n \n \left \{ {{ a_(1) = (6)/(q) } \atop {54 = q^(2) * 6 }} \right. 

\left \{ {{ a_(1) = (6)/(q) } \atop { q^(2) =9}} \right. \n \n \left \{ {{ a_(1) = (6)/(q) } \atop {q= √(9) }} \right. 
q = 3     q = -3

a₁ = 6/3 = 2   a₁ = 6/-3 = -2

What is the square root of -1?

Answers

Answer:

The square root of -1 is i

Your question is "what is the square root of i", the answer is just i

i represents an imaginary number, in other words a term for non real numbers

Answer:

i
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