Answer:
For each of them, you would need to isolate the variable.
Step-by-step explanation:
Okay so for the first one, you would need to isolate the x.
x/-2 = 3
Since the "/" represents division, you need to do the inverse of dividing which is multiplication. You would need to multiply on both sides of the equation.
x = 3 x -2
x = -6
And there you have it, the answer for the first problem!
You again, isolate the x for the second equation as well.
-9x = -9
Since the x is directly next to the 9, indicating that it is multiplication. Do the inverse of multiplication which is division. Divide by -9 on both sides.
x=-9
Since -9/-9 cancels each other out, that leaves x by itself.
x = -9/-9
x = 1
You only end up cancelling out the number next to the variable, not the one on the other side. (if you are wondering why I didn't cross it out)
As for the third one, you can carry the -5 over to the -4, but since the inverse of -5 is +5, you add 5 to -4.
x = 1
As easy as that! You don't do the same as the two questions before because the number isn't right next to the variable.
For the fourth one, you isolate the x once more. You do the inverse of multiplication which is again, division. And again, the -5/-5 cancel out!
x = -5/25
x = -0.2
And finally, the last one!
You repeat the same steps as the third one. Add 2 on each side and cancel out 2 + 2 on the x's side.
x = 10 +2
x = 12
And that's all your answers. Hope you understood :)
Answer:
Ratio of PQC to ABC is 2:9.
Step-by-step explanation:
In ΔBRQ and ΔBPC
∠BQR = ∠BCP (given) and ∠B is common for both triangles, so from AAA similarity ΔBRQ and ΔBPC are similar.
⇒ BQ : QC = BR : RP = 2 : 1 →(1)
now draw perpendiculars from points A and P to BC line segment. Call the projected points as A' and P'.
It is clear that lines AA' and PP' are parallel. So in ΔBPP' and ΔBAA' we have AAA similarity with common angle at B.
⇒PP' : AA' = BP : BA = 2 : 3 →(2) (∵ AP : PB = 1 : 2)
area of ΔPQC = 0.5×PP'×QC
area of ΔABC = 0.5×AA'×BC
area of ΔPQC : area of ΔABC = (0.5×PP'×QC)/(0.5×AA'×BC)
=(PP'/AA')×(QC/BC)
=(2/3)×(1/3) (∵ from (1) and (2))
=2/9.
∴ Ratio of PQC to ABC is 2:9
b. 41⁄9
c. 67⁄8
d. 135⁄11
e. 107⁄20
f. 493⁄17
A.) 3 3/4
B.) 4 5/9
C.) 8. 375 - I couldn't solve this one
D.) 12 3/11
E.) 5 7/20
F.) 29
Answer:
Option A
Step-by-step explanation:
The given function is a linear function therefore rate of change of this function will be the slope of the given line.
Since this line passes through two points ( 0,1 ) and ( 0.5 0 )
the slope of the line =
slope =
= ( -2 )
Therfore, Option A will be the answer.
The rate of change of function is,
m = - 2
We have to given that,
A function is shown in figure.
Since, The rate of change of linear function is slope of line.
Here, Two points on the line are (1, - 1) and (0, 1)
Since, The equation of line passes through the points (1, - 1) and (0, 1)
So, We need to find the slope of the line.
Hence, Slope of the line is,
m = (y₂ - y₁) / (x₂ - x₁)
m = (1 - (-1)) / (0 - 1)
m = 2 / - 1
m = - 2
So, The rate of change of function is,
m = - 2
Learn more about the equation of line visit:
#SPJ6
(2)Which number is halfway between 1/2 and 5/6?
A.7/10
B.13/20
C.27/40
D.2/3