Answer:
40.6 units
Step-by-step explanation:
Arc length is given by the formula ...
s = rθ
where θ is the measure of the central angle in radians.
There are 2π radians in a circle (360°), so π radians in 180°. That can be used to convert the central angle ADB to radians for use in the formula.
∠ADB = 360° -194° = 166°
∠ADB = 166° = (166/180)π radians = 83π/90 radians
Then the arc length AB is ...
length AB = (14)(83π/90) ≈ 40.561 units
The length of arc AB is about 40.6 units.
The solution is, 14 tiles does Joe need.
Area is the measure of a region's size on a surface. The area of a plane region or plane area refers to the area of a shape or planar lamina, while surface area refers to the area of an open surface or the boundary of a three-dimensional object.
here, we have,
given that,
Joe's bathroom floor is 5 feet wide and 8 feet long. He will cover the floor with 3" square tiles.
so first find area
area=legnth times width
5=width
8=legnth
5 times 8=40
so, we have,
area=40
3 area times x number of tiles=40
divide both sides by 3
x=40/3
x=13 and 1/3
since you can't buy 1/3 tiile
round up
x=14
answer is 14 tiles does Joe need.
To learn more on Area click:
#SPJ3
A.
x = 12 + 3
B.
x = 12 ÷ 3
C.
x = 12 − 3
D.
x = 12 • 3
The answer is:
Work/explanation:
To solve, subtract 3 on each side:
The equation that is related to the equation shown is x = 12 - 3.
The longest flagpole that could be shipped in a box that measures 2 ft by 2 ft by 12 ft is 2 feet long.
To find the minimum of a continuous and twice differentiable function f(x), we can firstly differentiate it with respect to x and equating it to 0 will give us critical points.
Putting those values of x in the second rate of function, if results in negative output, then at that point, there is maxima. If the output is positive then its minima and if its 0, then we will have to find the third derivative (if it exists) and so on.
We are given that;
The measurement of box= 2*2*12ft
Now,
To determine the longest flagpole that could be shipped in a box that measures 2 ft by 2 ft by 12 ft, we need to find the maximum length of a flagpole that can fit inside the box without exceeding any of the box's dimensions.
The longest flagpole that could fit inside the box would be equal to the shortest dimension of the box, which is 2 feet. This is because the flagpole would need to fit inside the box in a diagonal orientation in order to maximize its length.
Therefore, by the maxima and minima answer will be 2 feet long.
Learn more about maxima and minima of a function here:
#SPJ3
The expression for the perimeter of the fabric is P = 16x+20. When x=2, the perimeter is 52.
To find the expression for the perimeter of the piece of fabric, we need to determine the length of each side of the fabric. The given expression for the area of the fabric is 16x^2+40x+25. We can factor this expression as (4x+5)^2. Since a square has all its sides equal, the length of each side of the fabric is 4x+5.
The perimeter of a square is given by the formula P = 4s, where s is the length of a side. Therefore, the expression for the perimeter of the fabric is P = 4(4x+5) = 16x+20.
To find the perimeter when x=2, we substitute x=2 into the expression for the perimeter: P = 16(2)+20 = 32+20 = 52.
#SPJ11