Answer:
5.5,5(1/4),5(1/5),5.1
Step-by-step explanation:
Answer:
brett,amir,suki,marilyn
Step-by-step explanation:
brett = 5.5, greatest
amir = 5.25
suki = 5.2
marilyn 5.1 ,least
equation:
n =
The greatest number that can be added to 4315 without having to regroup is 5644. When added together, the sum doesn't result in a carryover to the next place value.
In Mathematics, particularly arithmetic, regrouping is the process of making groups of tens when adding or subtracting two numbers. When the question asks for the greatest number that can be added to 4315 without having to regroup, we are essentially looking for a number that when added to 4315 doesn't result in a carryover to the next place value.
Considering the number 4315, you would notice that the units digit is 5, the tens digit is 1, the hundreds digit is 3, and the thousands digit is 4. This means for each position we can add a number up to 9 without needing to regroup. Hence, the greatest number you can add to 4315 without needing to regroup would be 5644 (which gives 9 in the units place, 1+5=6 in the tens place, 3+4=7 in the hundreds place, and 4+4=8 in the thousands place).
#SPJ2
7x + 3 = 2x + 13
Answer:
Step-by-step explanation:
7x + 3 = 2x + 13
5x + 3 = 13
5x = 10
x = 2
Answer:
x = 2
Step-by-step explanation:
given
7x + 3 = 2x + 13 ( subtract 2x from both sides )
7x - 2x + 3 = 2x - 2x + 13 ( simplify both sides )
5x + 3 = 13 ( subtract 3 from both sides )
5x + 3 - 3 = 13 - 3 ( simplify both sides )
5x = 10 ( divide both sides by 5 )
x = , that is
x = 2
(See picture attached below)
Answer Choices:
A. x2 + 15x − 2 = 0
B. x2 + 15x + 58 = 0
C. 4x2 + 30x − 2 = 0
D. 4x2 + 30x + 58 = 0
Answer:
C
Step-by-step explanation:
took the test