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Answer 1
Answer:

Answer:

  (4, 5)

Step-by-step explanation:

Dilation by factor d about point (a, b) effects the transformation ...

  (x, y) ⇒ d((x, y) -(a, b)) +(a, b)

  ⇒ (d(x-a) +a, d(y-b) +b)

  (x, y) ⇒ (dx +a(1-d), dy +b(1-d))

We have (x, y) = (3, 4) and (a, b) = (1, 2) and d=3/2. Filling in these numbers, we get ...

  (3, 4) ⇒ ((3/2)(3)+1(1-3/2), (3/2)(4)+2(1-3/2)) = (9/2 -1/2, 6 -1) = (4, 5)

Point E' is (4, 5).

_____

If you look at the graph, you realize that E is (2, 2) from (1, 2). Dilation by a factor of 3/2 moves it to (3/2)(2, 2) = (3, 3) from (1, 2). So ...

  E' = (3+1, 3+2)

  E' = (4, 5)


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Albert says that the two systems of equations show below have the same solutions determine in-state whether you agree with Albert. Justify your answer

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Which of the following is the best definition of the range of a relation? A. The set of all possible input values, or x-values
B. The set of all possible output values, or y-values
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Answers

the answer is either a or c

2+3=8,

3+7=27,

4+5=32,

5+8=60,

6+7=72,

7+8=????????

SOLVE IT IF YOU CAN

 

Answers

here 2+3=2(3+1)=2(4)=8
3+7=3(7+2)=3*9=27
and so on
7+8=7(8+6)=98

Determine the type and number of solutions of 7x^2+3x+8=0

Answers

7x^2+3x+8=0 \n \na =7, \ b=3 ,\ c=8 \n \n\Delta =b^2 - 4ac = 3^2 -4\cdot 7\cdot 8=9-224=-215\n \n Answer : \ \Delta \ is \ negative,\ this \ gives \ two \ imaginary \ solutions


7x^2+3x+8=0\n\n \Delta=3^2-4\cdot7\cdot8=9-224=-115\ \ \Rightarrow\ \ \ no\ real\ solution\n\n\ two\ complex\ solutions\n\n\Delta=-115=115\cdot i^2\ \ \ \Rightarrow\ \ \ √(\Delta) = √(115)\ i\n\nx_1= (-b- √(\Delta) )/(2a) = (-3- √(115)\ i)/(2\cdot 7) = (-3- √(115i))/(14)\n\nx_2= (-b+ √(\Delta) )/(2a) = (-3+ √(115)\ i)/(2\cdot 7) = (-3+ √(115)\ i)/(14)

If a baseball player hits a baseball from 4 feet off the ground with an initial velocity of 64 feet per second, how long will it take the baseball to hit the ground? Use the equation h = −16t2 + 64t + 4.

Answers

you need to find the roots of the function, h(t)

then h(t) = 0 = -16t^2 + 64t + 4

divide both sides by -4

4t^2 - 16 t - 1 = 0

use the quadratic function

(-b+/- √(b^2-4ac) )/(2a)

substitue a = 4, b = -16, c = -1

you will get t1 ≈ 0 and t2 ≈ 4

Answer: approx. 4 seconds.

Answer: 2 plus or minus the square root of 17 end root over 2

Solve each equation for the given variable -2x+5y=12 for y
'

Answers

so basically get 1 of y on one side so
-2x+5y=12
add 2x to both sides
5y=12+2x
divide both sides by 5
y=(12+2x)/5
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