Sarah, who lives in Australia notices that the length of the shadow of the flagpole is getting shorter every day when measured at noon. Paul, who lives in Canada, notices that the length of the shadow of the flagpole is getting longer everyday when measured at noon.Explain how both students can be observing this at the same time. Include these in your explanation: Sun; earth; tilted axis; rotation and revolution.

Answers

Answer 1

Answer:

In Canada winter season is started whereas in Australia summer season is started which is responsible for change in shadow's length.

Both students can be observing this at the same time because o difference in location on the earth surface. The rotation of the earth is responsible for the change occurs in the shadows throughout the day. The rotation of the Earth causes day and night. That portion of the earth which is in front of the sun experience day whereas that part which is at the back of the sun experience night.

The tilting of earth is responsible for the formation of seasons. In winter season, the shadows of objects are longer while on the other hand, the shadows of object in summer season is shorter due to tilting of the earth so we can conclude that in Canada winter season is started whereas in Australia summer season is started.

Learn more about tilting of earth here: brainly.com/question/8678564

Learn more: brainly.com/question/15620767

Answer 2

Answer:

Answer: Sarah lives closer to the sun and to tilted axis makes the shadow seem shorter. Also Paul is facing farther away from the sun and the tilted axis makes the shadow very long

Explanation:

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Four small spheres, each of which you can regard as a point of mass 0.200 kg, are arranged in a square 0.400 m on a side and connected by light rods. Find the moment of inertia of the system about an axis through the center of the square, perpendicular to its plane.

Answers

The moment of inertia of the system about an axis through the center of the square, perpendicular to its plane is $0.0636 \;\rm kg-m^(2)$ .

Given data:

The mass of each sphere is, $m = 0.200 \;\rm kg$ .

Length of side of square is, $L = 0.400 \;\rm m$ .

The expression for the moment of inertia of the system about an axis through the center of the square, perpendicular to its plane is,

$I = 4 mR^(2)$

Here,

R is the distance between center of the square and the sphere. And its value is,

$R =(1)/(2)\sqrt{L^(2)+L^(2)}\nR =(1)/(2)\sqrt{0.400^(2)+0.400^(2)}\nR = 0.282 \;\rm m$

Then, moment of inertia is,

$I = 4 mR^(2)\nI = 4 * 0.200 * 0.282^(2)\nI = 0.0636 \;\rm kg-m^(2)$

Thus, the moment of inertia of the system about an axis through the center of the square, perpendicular to its plane is $0.0636 \;\rm kg-m^(2)$ .

Learn more about moment of inertia here:

brainly.com/question/2176093?referrer=searchResults

The moment of inertia of the system about an axis through the center of the square, perpendicular to the plane is 0.064 kg.m²

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Further explanation

Let's recall Moment of Inertia formula as follows:

$\boxed{ I = m R^2 }$

where:

I = moment of inertia

m = mass of object

R = distance between the object and the axis of rotation.

Given:

mass of sphere = m = 0.200 kg

length of side = x = 0.400 m

Asked:

net moment of inertia = ΣI = ?

Solution:

Let's ilustrate this question as shown in the attachment.

Firstly , let's find distance between center of the square and the sphere:

$R = (1)/(2) √(x^2+x^2)$

$R = (1)/(2) √(2x^2)$

$R = (1)/(2)√(2) x$

$R = (1)/(2) √(2) (0.400)$

$\boxed{R = 0.200√(2) \texttt{ m}}$

$\texttt{ }$

Next , we could find total moment of inertia as follows:

$\Sigma I = mR^2 + mR^2 + mR^2 + mR^2$

$\Sigma I = 4mR^2$

$\Sigma I = 4(0.200)(0.200√(2))^2$

$\boxed{\Sigma I = 0.064 \texttt{ kgm}^2}$

$\texttt{ }$

Learn more

Ratio of Moment of Inertia : brainly.com/question/2176655
Net Torque on the objects : brainly.com/question/9612563
Impacts of Gravity : brainly.com/question/5330244
Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
The Acceleration Due To Gravity : brainly.com/question/4189441

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Answer details

Grade: High School

Subject: Physics

Chapter: Rotational Dynamics

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