defective. The quality control manager tests a random sample of
30 batteries in each shipment. Simulate the test by generating random
numbers between 1 and 600. How well does your sample represent the
shipment? Explain. (Explore Activities 1 and 2)
Answer:
18.33
Step-by-step explanation:
600 -50 ÷ 30
550 ÷30 = 18.333
Answer:
Volume = lwh
V = 1.6 x 2.8 x 3.2
V = 14.336
V = 14.3 cubed
Yellow is the right answer.
If it is exact find a function F(x,y) whose differential, dF(xy) is the left hand side of the differential equation. That is, level curves F(xy)=C are solutions to the differential equation.
Answer:
The equation is exact
F(x,y) = 3x4/4 - 3xy -y2
Step-by-step explanation:
The step by step explanation and to ascertain the exactness of the differential equation is as shown in the attached file.
Answer:
the 2nd one
Step-by-step explanation:
Answer:
Step-by-step explanation:
Using normal distribution,
z = (x - μ)/σ
μ= mean = 44 and
σ = standard deviation= 5.0
a) The probability that yield strength is at most 40=
P( x lesser than or equal to 40)
z = (40-44)/5= -0.8
Looking at the normal distribution table,
P( x lesser than or equal to 40) =0.2119
b) P(x greater than 62) = 1 - P(x lesser than or equal to 62)
z = (62-44)/5= 3.6
Looking at the normal distribution table,
P(x greater than 62) = 1 -0.99984
= 0.00016
c)P( 42 lesser than or equal to x lesser than or equal to 62)
= P(x lesser than or equal to 62) - P( x lesser than or equal to 40)
= 0.99987-0.2119= 0.78797
d) What yield strength value separates the strongest 75% from the others.
To get x for strongest 75, we get the z value corresponding to 0.75 from the table
z = 0.675= (x-44)/5
x = 3.375+44 = 47.375
The rest is 25% = 0.25
we get the z value corresponding to 0.25 from the table)
z = -0.67 = (x-44)/5
-3.35= x -44
x = -44+3.35= 40.65
yield strength value that separates the strongest 75% from the others
=47.375-40.65= 6.725
The probability that the yield strength is at most 40 is approximately 0.2119 and the probability that it is greater than 62 is approximately 0.0001. The yield strength value that separates the strongest 75% from the others is approximately 40.628 ksi.
This question is about calculating probabilities and percentiles using the properties of the normal distribution. The yield strength for the A36 grade steel is normally distributed with a mean (μ) of 44 and a standard deviation (σ) of 5.0.
(a) To find the probability that the yield strength is at most 40, we will need to calculate the Z-score value for the yield strength of 40. The Z-score can be calculated using the following formula: Z = (X - μ) / σ , where X is the observed value, μ is the mean, and σ is the standard deviation. For X = 40, μ = 44, and σ = 5.0, the Z-score is -0.8. Looking up the Z-score in the standard normal distribution table, the probability that the yield strength is at most 40 is approximately 0.2119. Using a similar process, we find that the probability that the yield strength is greater than 62 is less than 0.0001, very close to zero.
(b) To determine the yield strength value that separates the strongest 75% from the others, we find the Z-score that corresponds to a cumulative probability of 0.25 in the standard normal distribution table (because the strongest 75% corresponds to the weakest 25%). That Z-score is approximately -0.6745. Using the formula Z = (X - μ) / σ to solve for X gives us X = σZ + μ = 5.0 * -0.6745 + 44 = 40.6275, which rounded to three decimal places is 40.628.
#SPJ3
Answer:
8 inches
Step-by-step explanation:
90 miles -------------> represented by 3 inches
1 mile -------------> represented by 3/90 inches
240 miles ----------> represented by 3/90 x 240 = 8 inches