The surfacearea of the triangular pyramid is 242.039 square feet.
a three dimensional shape can be defined as a solid figure or an object or shape that has three dimensions—length, width, and height.
Area of equilateraltriangle = √(3)/4) x (side)²
= √(3)/4) x 13²
= 84.303 square feet
Now find the area of one of the triangular faces
Height² = (slant height)² - (base/2²
= 11² - (13/2)²
= 121 - 84.25
Height²= 36.75
Height = 6.063 feet
Area of triangular face = (1/2) x (base) x (height)
= (1/2) x 13 x 6.063
= 39.434 square feet
the total area of the triangular faces is:
4 x 39.434 = 157.736 square feet
Surface area = area of base + area of triangular faces
= 84.303 + 157.736
= 242.039 square feet
Hence, the surface area of the triangular pyramid is 242.039 square feet.
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Answer multiply the width and the height
Step-by-step explanation:
Answer:
49
Step-by-step explanation:
Edge
Gọi số tấm thảm xưởng dệt dệt theo dự định là x ( tấm, x >0 )
⇒ số tấm thảm xưởng dệt dệt trong 1 ngày theo dự định x/30 (tấm)
xưởng dệt dệt đc số tấm thảm trong thực tế là x/20 (tấm)
⇒số tấm thảm xưởng dệt dệt trong 1 ngày thực tế là x+20/25 (tấm)
Vì năng suất tăng 25% nên số tấm thảm dệt được trong 1 ngày thực tế sẽ bằng 125% số tấm thảm dệt đc trong 1 ngày theo dự định nên ta có PT : x+20/25=125% * x/30
me lười làm khúc dưới quá nên tự xử nha.
The solution to the equation 3x + 1 = 10 is x = 3.
To solve the equation 3x + 1 = 10, follow these steps:
Step 1: Get the variable term (3x) by itself by subtracting 1 from both sides of the equation.
3x + 1 - 1 = 10 - 1
3x = 9
Step 2: Isolate the variable by dividing both sides of the equation by the coefficient of x, which is 3.
3x/3 = 9/3
x = 3
So, the solution to the equation is x = 3.
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Answer:
y=-1/13x-36/13
Step-by-step explanation:
Answer:
a) the probability of waiting more than 10 min is 2/3 ≈ 66,67%
b) the probability of waiting more than 10 min, knowing that you already waited 15 min is 5/15 ≈ 33,33%
Step-by-step explanation:
to calculate, we will use the uniform distribution function:
p(c≤X≤d)= (d-c)/(B-A) , for A≤x≤B
where p(c≤X≤d) is the probability that the variable is between the values c and d. B is the maximum value possible and A is the minimum value possible.
In our case the random variable X= waiting time for the bus, and therefore
B= 30 min (maximum waiting time, it arrives 10:30 a.m)
A= 0 (minimum waiting time, it arrives 10:00 a.m )
a) the probability that the waiting time is longer than 10 minutes:
c=10 min , d=B=30 min --> waiting time X between 10 and 30 minutes
p(10 min≤X≤30 min) = (30 min - 10 min) / (30 min - 0 min) = 20/30=2/3 ≈ 66,67%
a) the probability that 10 minutes or more are needed to wait starting from 10:15 , is the same that saying that the waiting time is greater than 25 min (X≥25 min) knowing that you have waited 15 min (X≥15 min). This is written as P(X≥25 | X≥15 ). To calculate it the theorem of Bayes is used
P(A | B )= P(A ∩ B ) / P(A) . where P(A | B ) is the probability that A happen , knowing that B already happened. And P(A ∩ B ) is the probability that both A and B happen.
In our case:
P(X≥25 | X≥15 )= P(X≥25 ∩ X≥15 ) / P(X≥15 ) = P(X≥25) / P(X≥15) ,
Note: P(X≥25 ∩ X≥15 )= P(X≥25) because if you wait more than 25 minutes, you are already waiting more than 15 minutes
- P(X≥25) is the probability that waiting time is greater than 25 min
c=25 min , d=B=30 min --> waiting time X between 25 and 30 minutes
p(25 min≤X≤30 min) = (30 min - 25 min) / (30 min - 0 min) = 5/30 ≈ 16,67%
- P(X≥15) is the probability that waiting time is greater than 15 min --> p(15 min≤X≤30 min) = (30 min - 15 min) / (30 min - 0 min) = 15/30
therefore
P(X≥25 | X≥15 )= P(X≥25) / P(X≥15) = (5/30) / (15/30) =5/15=1/3 ≈ 33,33%
Note:
P(X≥25 | X≥15 )≈ 33,33% ≥ P(X≥25) ≈ 16,67% since we know that the bus did not arrive the first 15 minutes and therefore is more likely that the actual waiting time could be in the 25 min - 30 min range (10:25-10:30).