Answer:6
Step-by-step explanation:
y = 4x - 1
b) 2x + y = 8
4x + 3y = 16
c) -3x + 2y = 19
4x + 5y = 13
d) -3x + 7y = 9
4x - 3y = 7
e) -4x + 5y = -7
x = 23 - 3y
f) y = -x
y = -2/5x - 1/5
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Look at the photo below for the answer.
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Answer:
a) x = 1 , y = 3
Step-by-step explanation:
a) 7x + 3y = 16
y = 4x - 1
or
3y + 7x = 16 ... (i)
y - 4x = -1 ... (ii)
Solving the simultaneous equation by substitution;
Equation (ii) tells us that y = 4x - 1
Substituting that in (i) gives;
3(4x - 1) + 7x = 16
12x - 3 + 7x = 16
19x = 16 + 3 = 19
x = = 1
y = 4(1) - 1 = 3
Help me with math please! 5 questions, 5 points each, 25 points overall! :D Please answer EACH AND EVERY question!! ↓ ↓ ↓ ↓ ↓
Let x be the rate of speed of slower cyclist
and x+10 = rate of speed of faster cyclist
Distance = Speed * Time
5x + 5(x+10) = 200
5x + 5x + 50 = 200
10x = 200-50
10x = 150
x = 15
Rate of speed of slower cyclist: 15 mph
Rate of speed of faster cyclist = 15+10 => 25 mph
In this problem, the speed of the faster cyclist is 25 mi/h and the speed of the slower cyclist is 15 mi/h. We determine this by setting up and solving an algebraic equation considering the total distance and time they traveled.
This problem is a typical example of relativerate and distance problems in algebra. First, define the speed of the faster cyclist as x m/h. Then, the speed of the slower cyclist is x-10 m/h. They travel towards each other, so their rates add up. That's why the equation becomes x+(x-10) = 200/5. We get this equation because the total distance they traveled is 200 miles (meeting in the middle), and they traveled for 5 hours.
Solving the equation x+(x-10) = 40 gives 2x-10 = 40, then 2x = 50, and finally x = 25. So, the faster cyclist is moving at 25 mi/h, and the slower cyclist is moving at 15 mi/h (25-10).
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