Seems like I've done a few of these already today.
1.
a[1] = 4, d=6
Formula: a[n] = 4 + 6(n-1)
a[40]=4 + 6(39) = 238
Table: 4 10 16 22 28 34 ... a[40]=238
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2.
a[23]=25, d=3
a[n] = a[1] + d(n-1)
25=a[23]=a[1] + 3(22)
a[1] = 25 - 66 = -41
Table: -41 -38 -35 -32 -29 -26
Let's check a[23]= -41 + 3(22)= 25, good
Formula: a[n] = -41 + 3(n-1)
What is the sum of the infinite geometric series?. 1/2+1/4+1/8+1/16+...
Answer:
The sum of the given geometric series is, 1
Step-by-step explanation:
Geometric sequence states that a sequence of numbers that follows a pattern were the next term is found by multiplying by a constant called the common ratio (r).
The sum of the infinite terms of a geometric series is given by:
......[1] ;where
Given the series:
Since, this series is geometric series with constant term(r) =
Since,
,
and so on....
Here, first term(a) =
Substitute the values of a and r in [1] we get;
where r =
or
Simplify:
Therefore, the sum of the infinite geometric series is, 1
Answer:
Undefined.
Step-by-step explanation:
When using the formula y2-y1/x2-x1, the result comes out as -4/0. Any number over a 0 is undefined.
B: (m, n)
C: (m – n, 0)
D: (m, 2n)
Answer:
(m,n)
Step-by-step explanation:
Since O is at the origin, we can take the coordinates of point A and divide them by 2 to find the midpoint
( 2m/2,2n/2)
The midpoint is at (m,n)
A.
5
B.
20
C.
25
D.
30