Let the random variable X represent the winnings at one play of game A. The mean, H. Of X is known to be -$0.42 and its standard deviation, o, is $0.26. Let the random variable Y represent the winnings at one play of game B. The mean, , of Y is known to be -$0.42 and its standard deviation, o, is $0.21. You have decided to play one of these two games just once. At which game are you more likely to make a profit (i.E., to not lose money)? Explain your thinking.

Answers

Answer 1
Answer:

Answer:

345

Step-by-step explanation:

i know it not

Answer 2
Answer:

Answer:

565$

Step-by-step explanation:

Y because he got more money


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What is the difference 4y/xy - 2x/xy^3

How would you describe this pattern's rule?
16, 11, 6, 1

Answers

Answer:

Subtracting the number 5 every time.

Each time you are subtracting 5

16-5=11
11-5=6
6-5=1

Hope this helps :)

Instructions:Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).James bought two T-shirts and one pair of jeans at an online store and paid $40, not including taxes, for his purchase. A month later, the same store sold the T-shirts and jeans at a 50% discount from their original prices. James bought two T-shirts and five pairs of jeans for $60, not including taxes.
Assuming the base prices of the T-shirts and the jeans are the same on both occasions, and ignoring the taxes, the price of a T-shirt is $ and the price of a pair of jeans is $.

Answers

Call T the price of the T-shirts and P de price of the jeans

Initially (without discount)
2T + P = 40

One month later (half prices)
2 (T/2) + 5(P/2) = 60
T +5P/2 = 60

To solve the system of equations multiply the second equation by 2 and substract it from the first equation

   2 T + 5P = 120
- (2 T +   P = 40 )
________________

           4P = 80

P = 80/4
P = 20

From 2T + P = 40

T = (40 - P) / 2 = (40 -20) / 2 = 20/2 = 10.

The price of a T-shirt is $10 and the price of a pair of jeans is $20.

Students in Miss Moseley's fourth grade class are learning multiplication, and they demonstrate mastery by passing assessments. Travis has passed 11 tests, and his classmate, Jenifer, has passed 2 tests. Going forward, Travis plans to pass 2 tests per week. Meanwhile, Jenifer plans to pass 5 tests per week. Eventually Jenifer will catch up to Travis. When the number of tests each student has passed are equal, how many tests will each student have passed and how many weeks will it take?

Answers

Jenifer

2+5 week 1

7+5 week 2

12+5 week 3

17 week4


Travis

11+2 week 1

13+2 week 2

15+2 week 3

17 week 4

Find the value of A in the equation 5/a+3=3/A-2

Answers

If you would like to find the value of a in the equation 5/a + 3 = 3/a - 2, you can do this using the following steps:

5/a + 3 = 3/a - 2     /*a
5 + 3a = 3 - 2a
3a + 2a = 3 - 5
5a = -2
a = -2/5

The correct result would be -2/5.
5+3a = 3-2a
So
5a = -2
a=-2/5=-0.4

YOUR ASSIGNMENT: Factory Lighting ProblemIn this assignment, you may work alone, with a partner, or in a small group. Discuss the results of your work and/or any lingering questions with your teacher.

You are deciding whether to light a new factory using bulb A, bulb B, or bulb C.

Which bulb would be better to use on the factory floor?
Which bulb would be better to use in the break room?
To answer these questions, you will compare the energy usage of the three bulbs. The amount of energy the lights use is measured in units of kilowatt-hours. A kilowatt-hour is the amount of energy needed to provide 1000 watts of power for 1 hour.

1. Circle the two bulbs you picked.
incandescent
Halogen
Fluorescent

2.



3. Practice: Summarizing (3 points)
Fill in the blanks.

The energy usage of a light bulb is a function. The input for the function is _________, measured in hours.

The output of the function is energy usage, measured in ____________.

Identify the functional relationship between the variables. _________________ is a function of _________________.

The graph of the function will show energy usage on the _____________ axis and time on the _______________ axis.
4. Practice: Organizing Information (2 points)
Use the data given to complete the table for your first bulb.
DATA TABLE A
Time (hours) x Energy (kWh) y Point (time, energy) (x, y)
3
10
5. Practice: Organizing Information (2 points)
Use the data given to complete the table for your second bulb.
DATA TABLE B
Time (hours)x Energy (kWh)y Point (time, energy)(x, y)
3
10
6. Practice: Organizing Information (5 points: 1 point for labels, 2 points for each graph)

Label the axes of the graph with "Time (hours)" and "Energy (kWh)." Plot the points from Table A on the graph. Connect the points with a line. On the same graph, plot the points from Table B and connect them with a line.


7. Practice: Summarizing (1 point)
Classify each of your graphs as increasing, decreasing, or constant.

First bulb: ___________________


Second bulb:___________________

8. Practice: Summarizing (2 points)
Fill in the blanks.

First bulb: When 3 is the input, the output is _____. When 10 is the input, the output is _______.


Second bulb: When 3 is the input, the output is _____. When 10 is the input, the output is _______.

9. Practice: Summarizing (1 point)
The workers leave the lights on in the break room for stretches of about 3 hours. Which light bulb would light this room using the least amount of energy?








10. Practice: Summarizing (1 point)
The lights in the main room of the factory stay on for stretches of 9 hours. Which kind of light bulb would light this room with the least amount of energy?

Answers

Answer:

To determine which bulb would be better to use on the factory floor and in the break room, we need to compare the energy usage of the three bulbs: incandescent, halogen, and fluorescent.

1. Based on energy efficiency, we would circle the two bulbs that are more energy-efficient: halogen and fluorescent.

3. Summarizing:

- The energy usage of a light bulb is a function. The input for the function is time, measured in hours.

- The output of the function is energy usage, measured in kilowatt-hours (kWh).

- Time is a function of energy usage.

4. Organizing Information: DATA TABLE A

Time (hours) x Energy (kWh) y Point (time, energy) (x, y)

3 -

10 -

5. Organizing Information: DATA TABLE B

Time (hours) x Energy (kWh) y Point (time, energy) (x, y)

3 -

10 -

6. Organizing Information:

- Graph 1: Label the axes with "Time (hours)" and "Energy (kWh)". Plot the points from Table A and connect them with a line.

- Graph 2: Label the axes with "Time (hours)" and "Energy (kWh)". Plot the points from Table B and connect them with a line.

7. Summarizing:

- Graph 1 (First bulb) classification: Unknown, as the points are not provided.

- Graph 2 (Second bulb) classification: Unknown, as the points are not provided.

8. Summarizing:

- First bulb: When 3 hours is the input, the output (energy usage) is unknown. When 10 hours is the input, the output (energy usage) is unknown.

- Second bulb: When 3 hours is the input, the output (energy usage) is unknown. When 10 hours is the input, the output (energy usage) is unknown.

9. Summarizing:

- To determine which light bulb would consume the least amount of energy in the break room for stretches of about 3 hours, we need the data or information on energy usage for each bulb. Without that information, it's not possible to make a definitive conclusion.

10. Summarizing:

- Similarly, to determine which light bulb would consume the least amount of energy in the main room of the factory for stretches of 9 hours, we need the data or information on energy usage for each bulb. Without that information, it's not possible to make a definitive conclusion.

In summary, without the energy usage data for each bulb, we cannot determine which bulb would be better to use on the factory floor or in the break room, or which bulb would consume the least amount of energy for specific time durations.

Step-by-step explanation:

Civil engineer wants to estimate the maximum number of cars that can safely travel on a particular road at a given speed. He assumes that each car is 14 feet long, travels at speed S, and follows the car in front of it at a safe distance for that speed. He finds that the number N of cars that can pass a given spot per minute is modeled by the function N=(89s)/(14+14(s/17)^2))

At what speed can the greatest number of cars travel safely on that road? Assume that the maximum possible speed of a car is less than 300.

Answers

N(s)= (89s)/(14+14( (s)/(17))^2 )\n\nN'(s)= ((89s)/(14+14( (s)/(17))^2 ) )'= (89* 14(1+( (s)/(17))^2)-89s*  (28)/(17) )/(14^2(1+( (s)/(17))^2)) \n\nN'(s)=0\n\n89* 14(1+( (s)/(17))^2)-89s*  (28)/(17)=0\n\n1+( (s)/(17))^2- (2s)/(17) =0\n\n289+s^2-34s=0\n\ns^2-34s+289=0\n\n(s-17)^2=0\n\ns=17