Answer:
4. 2.0 M CaC12(aq)
Explanation:
According to the van't Hoff factor, (the measurement of the solute's colligative properties effect (boiling point,freezing point depression)) a solution that has the highest point at standard pressure, id the one with the most particles or ions.
van't Hoff factor can also be described as the ratio between the original concentration of the solutions's atoms when the solution is dissolved and the concentration of the solutions taken from its mass.
Answer:
The possible options are :
(1) 1.0 M KC1(aq) (3) 2.0 M KCl(aq) (2) 1.0 M CaC12(aq) (4) 2.0 M CaC12(aq)
Answer is (4) 2.0 M CaC12(aq)
Explanation:
vant Hoff factor highest BP has the most particles...ions CaCl2 forms 3 ==> Ca2+ and 2Cl-.
The van 't Hoff factor i (named after Dutch chemist Jacobus Henricus van 't Hoff) is a measure of the effect of a solute upon colligative properties such as osmotic pressure, relative lowering in vapor pressure, boiling-point elevation and freezing-point depression.
(2) number of protons, only
(3) ratio of neutrons to protons
(4) ratio of electrons to protons
Pollution
Particulate matter
Ozone
Answer:
the answer is Particulate matter
Explanation:
Answer:
The reagents needed are Br₂ and FeBr₃
Explanation:
In order to make 3-bromo-5-isopropyltoluene starting with m-isopropyltoluene we need to add Bromine (Br₂) and Iron(III) bromide (FeBr₃).
Please see attached picture for the resulting product, 3-bromo-5-isopropyltoluene.
B) H2 + O 2 --> 2H2O
C) 2H2 + O2 --> 2H2O
D) 2H2 + 2O2 --> 2H2O
Answer: The equation showing conservation of atoms is
Explanation:
Every balanced chemical equation follows law of conservation of mass.
This law states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form. This also means that total number of individual atoms on reactant side must be equal to the total number of individual atoms on the product side.
For the given chemical equations:
The given chemical equation follows:
There are 2 hydrogen atoms and 2 oxygen atoms on the reactant side and 2 hydrogen and 1 oxygen atom on product side.
So, this equation does not show conservation of atoms.
The given chemical equation follows:
There are 2 hydrogen atoms and 2 oxygen atoms on the reactant side and 4 hydrogen atoms and 2 oxygen atoms on product side.
So, this equation does not show conservation of atoms.
The given chemical equation follows:
There are 4 hydrogen atoms and 2 oxygen atoms on the reactant side and 4 hydrogen atoms and 2 oxygen atoms on product side.
So, this equation shows conservation of atoms.
The given chemical equation follows:
There are 4 hydrogen atoms and 4 oxygen atoms on the reactant side and 4 hydrogen atoms and 2 oxygen atoms on product side.
So, this equation does not show conservation of atoms.
Hence, the equation showing conservation of atoms is