At a certain location, the earth's magnetic field has a magnitude of 5.7×10−5 t and points in a direction that is 73 ∘ below the horizontal. part a find the magnitude of the magnetic flux through the top of a desk at this location that measures 81 cm by 85 cm

Answers

Answer 1
Answer:

Answer:

1.15 * 10^(-5) Tm²

Explanation:

Parameters given:

Magnitude of magnetic field, B = 5.7 * 10^(-5) T

Angle of magnetic field to the horizontal plane = 73°

Dimension of the desk = 81 cm × 85 cm

Area of desk, A = 6885 cm² = 0.6885 m²

The magnitude of the Magnetic Flux, |Φ|, is given as:

|Φ| = |B * A * cosθ|

Where θ = angle of the Magnetic field to the normal of the desk = 90 - 73 = 17°

Therefore, the magnitude of the Magnetic Flux will be:

|Φ| = |5.7 * 10^(-5) * 0.6885 * cos17|

|Φ| = 3.75 * 10^(-5) Tm²

Answer 2
Answer:

When the magnitude of the magnetic flux through the top of a desk at this location is = 1.15 * 10\wedge (-5) Tm2

Calculate of Parameters

Parameters as per the question given:

Then The Magnitude of the magnetic field, B = 5.7 * 10\wedge (-5) T

Then, The Angle of the magnetic field to the horizontalplane = 73°

After that, The Dimension of the desk = is 81 cm × 85 cm

Now, The Area of desk, A = 6885 cm² = 0.6885 m²

When The magnitude of the Magnetic Flux, |Φ|, is given as:

Then, |Φ| = |B * A * cosθ|

Where θ is = angle of the Magnetic field to the normal of the desk = 90 - 73 = 17°

Thus, the magnitude of the Magnetic Flux will be:

|Φ| =|5.7 * 10\wedge (-5) * 0.6885 * cos17|

|Φ| =3.75 * 10\wedge (-5) Tm²

Find more information about Parameters here:

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A beta particle is identical to : an electron

Both of beta particle and electron are high in energy and move in high speed.
hope this helps

A beta particle is identical to an electron  so A I think

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The metric system is based upon powers of ten (10), which is convenient because: A measurement in the metric system that is represented by a rational number remains a rational number after metric unit conversion.

Answer:

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Explanation:

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Which change decreases the resistance of a pieceof copper wire?
(1) increasing the wire’s length
(2) increasing the wire’s resistivity
(3) decreasing the wire’s temperature
(4) decreasing the wire’s diameter

Answers

Explanation :

We know that the resistance of the wire is given by :

R=\rho (l)/(A)

Where

\rho is the resistivity

l is the length of the wire

A is the area of the wire.

Another factor on which the resistance of wire depends is temperature. It is given by :

R=R_(ref)[1+\alpha (T-T_(ref))]

So, it is clear that the resistance of the wire is directly proportional to the temperature. It we want to decrease the resistance of the piece, its temperature should be decreased.

So, the correct option is (3) " decreasing the wire’s temperature ".

Decreasing the wire’s temperature decreases the resistance of a piece of copper wire.

What is resistance?

Resistance is a type of opposition force due to which the flow of current is reduced in the material or wire. Resistance is the enemy of the flow of current.

The relation of resistance with length and thickness is given by ;

\rm R= (\rho L)/(A)

The value of resistance is directly propotional to length and inversly propotional to the area or thickness of the wire.

As the value of temperature increases, the value of resistance in the material is increasing. Length, temperature, and thickness are the factors that affect the resistance of a material.

Resistance of the wire is directly propotional to the temperature. On decreasing the temperature the resistance of the wire is also decreasing.

Hence decreasing the wire’s temperature decreases the resistance of a piece of copper wire.

To learn more about the resistance refer to the link;

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