Answer:
1.552 moles
Explanation:
First, we'll begin by writing a balanced equation for the reaction showing how C8H18 is burn in air to produce CO2.
This is illustrated below:
2C8H18 + 25O2 -> 16CO2 + 18H2O
Next, let us calculate the number of mole of C8H18 present in 22.1g of C8H18. This is illustrated below:
Molar Mass of C8H18 = (12x8) + (18x1) = 96 + 18 = 114g/mol
Mass of C8H18 = 22.1g
Mole of C8H18 =..?
Number of mole = Mass /Molar Mass
Mole of C8H18 = 22.1/144
Mole of C8H18 = 0.194 mole
From the balanced equation above,
2 moles of C8H18 produced 16 moles of CO2.
Therefore, 0.194 mole of C8H18 will produce = (0.194x16)/2 = 1.552 moles of CO2.
Therefore, 1.552 moles of CO2 are emitted into the atmosphere when 22.1 g C8H18 is burned
To calculate the number of moles of CO2 emitted into the atmosphere when 22.1 g of C8H18 is burned, we need to convert the mass of C8H18 to moles using its molar mass. The mole ratio between C8H18 and CO2 is 1:8 based on the balanced chemical equation. Thus the number of moles of CO2 produced can be calculated by multiplying the number of moles of C8H18 by the mole ratio.
To calculate the number of moles of CO2 emitted into the atmosphere when 22.1 g of C8H18 is burned, we need to convert the mass of C8H18 to moles using its molar mass. The molar mass of C8H18 is calculated by summing the atomic masses of its constituent elements: (12 g/mol for carbon)(8 carbon atoms) + (1 g/mol for hydrogen)(18 hydrogen atoms) = 114.22 g/mol for C8H18.
Next we need to use the balanced chemical equation for the combustion of C8H18 to determine the mole ratio between C8H18 and CO2. The balanced equation is: C8H18 + 12.5 O2 → 8 CO2 + 9 H2O.
From the balanced equation, we can see that 1 mole of C8H18 produces 8 moles of CO2. Thus we can calculate the number of moles of CO2 produced by dividing the mass of C8H18 by its molar mass and multiplying by the mole ratio:
number of moles of CO2 = (mass of C8H18 / molar mass of C8H18) * 8
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If an average cell phone is dropped from a typical cruising altitude of an airplane, neglecting air resistance, it would take about 107 seconds to reach the ground.
The subject this question falls under is physics because it involves the physical principles of gravity and free fall. If we ignore air resistance (a common simplification in basic physics problems), we can solve this problem by employing the equation for the time (t) of a free-falling object:
t = √(2h/g),
where h is the height the object falls from and g is acceleration due to gravity (about 9.8 m/).
Notice that we would need to first convert 37,000 feet to meters (about 11,277.6).
By substituting these values into our formula, we get a value that indicates that a phone falling from the typical cruising altitude of an airplane would take about 107 seconds to hit the ground.
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Blue
Red
Concentration of products
Concentration of reactants
Answer:
Option C:- concentration of products
Explanation:
According to Le Chateleir's principle,
if the forward reaction is favored in the equilibrium then concentration of products will increase and concentration of reactants will decrease.
If the reverse reaction is favored in the equilibrium then concentration of products will decrease and concentration of reactants will increase.
Biotic components are the living components of an ecosystem. The biotic factor that limits the carrying capacity of any habitat is activity of decomposers, i.e., option B.
The organisms that usually feed on dead and decaying organisms and whose digestion is external one are called as decomposers.
The bioticfactor that limits the carryingcapacity of any habitat is activity of decomposers.
Thus, the correct option is B.
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