MATHEMATICS COLLEGE

Find the perimeter and area of the regular polygon. Round answers to the nearest tenth.

Answers

Answer 1

Answer:

Answer: perimeter = 26.5

Area = 106

Step-by-step explanation:

The given polygon is an octagon. The apotherm which is the perpendicular line from the midpoint of the octagon is 8,

The formula for determining the area of a polygon is expressed as

Area = a² × n × tan 180/n

Where n represents the number of sides of the polygon.

n = 8

Therefore,

Area = 8² × 4 × tan(180/8)

Area = 256 × tan 22.5

Area = 106

The formula for determining the perimeter of a regular polygon is

P = 2 × area/apotherm

Perimeter = 2 × 106/8

Perimeter = 26.5

Related Questions

Whoever answers correctly gets brainlist
Graph a line with a slope of 2/5 that contains the point (-2,4)
1. In order to get more female customers, a new clothing store offers free gourmet coffee and pastry to its customers. The average daily revenue over the past five-week period has been $1,080 with a standard deviation of $260. Use this sample information to construct a 95% confidence interval for the average daily revenue. The store manager believes that the coffee and pastry strategy would lead to an average daily revenue of $1,200. Is the manager correct based on the 95% confidence interval?
Please help! Thank you!
7) In 2014, the attendance at Jefferson School's School Festival was 650. In 2015, the attendance was 575. What was the percent change in attendance from 214 to 2015? Round to the nearest tenth. * A 11% B 12% decrease C 13% D 14%

Does Anyone Know This?

Answers

Answer:

Pretty sure its B

Step-by-step explanation:

Determine the value of x

1)70
2)140
3)40
4)280

Answers

180-140= 40

Im not so sure of my answer so I might be wrong so enjoy!!

The slope of a line is 2. The y-intercept of the line is –6. Which statements accurately describe how to graph the function? A. Locate the ordered pair (0, –6). From that point on the graph, move up 2, right 1 to locate the next ordered pair on the line. Draw a line through the two points.
B. Locate the ordered pair (0, –6). From that point on the graph, move up 2, left 1 to locate the next ordered pair on the line. Draw a line through the two points.
C. Locate the ordered pair (–6, 0). From that point on the graph, move up 2, right 1 to locate the next ordered pair on the line. Draw a line through the two points.
D. Locate the ordered pair (–6, 0). From that point on the graph, move up 2, left 1 to locate the next ordered pair on the line. Draw a line through the two points.

Answers

Answer:

Step-by-step explanation:

Slope is positive 2 so we have to move 1 point right and 2 points up.

Secondly y-intercept is -6 so ,point is (0,-6)

8. A carpenter balances his daily projects between small jobs (x) and building cabinets (y). He allots 2hours per small job and 4 hours per cabinet job. He works at most 12 hours per day (2x + 4y <_12).
He cannot do more than 3 small jobs per day
and get all of his cabinets done (Y >_0) & (0The carpenter earns $125 per small job and $500 per cabinet job. Find a combination of small jobs and
completed cabinet jobs per week that will maximize income.

Answers

Answer:

$\$1125$

Step-by-step explanation:

The equations of the system are

$2x+4y\leq 12$

$y\geq 0$

$0<x\leq 3$

From the graph it can be seen that points $(3,1.5)$ and $(3,0)$ falls in the bounded region.

The income will be

$125x+500y=125* 3+500* 1.5\n =\$1125$

$125* 3+500* 0=\$375$

So, the person can do 3 small jobs and build 1 and a half cabinets per day.

The maximum income will be $\$1125$ .

What is the approximate circumference pf the circle shown below?

Answers

Answer:

A: 20pi

Step-by-step explanation:

c=2(pi)r

c=2(pi)(10)

c=20(pi)

c=62.8

Given the following function , find f(-2) ,f (0) and f(2) F(X)=-3x-3 F(-2) = help me please i don't understand

Answers

Answer:

$\large{f(-2)=3\n\nf(0)=-3\n\nf(2)=-9}$

Step-by-step explanation:

$f(x)=-3x-3\n\nf(-2)\to\text{put x = -2 to the equation of the function}\ f(x):\n\nf(-2)=-3(-2)-3=6-3=3\n-------------------------\nf(0)\to\text{put x = 0 to the equation of the function}\ f(x):\n\nf(0)=-3(0)-3=0-3=-3\n------------------------\nf(2)\to\text{put x = 2 to the equation of the function}\ f(x):\n\nf(2)=-3(2)-3=-6-3=-9$

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