Answer:
Absolute maxima an minma both occured at .
Step-by-step explanation:
Given function is,
subject to,
Let
To find absolute maxima and absolute minima using Lagranges multipliers method consider as the multipliers such that,
on compairing both side we get,
From (2),
Absolute maxima, at x=3, y=0, is,
Absolute minima, at x=3, y=0, is,
Hence the result.
y= 1/5 x + 4
Answer:
The slope is and the y-intercept is .
Step-by-step explanation:
We are given an equation in slope-intercept form (y = mx + b).
In this equation, we can define the following variables:
The slope in an equation and of a line is the rise over run of a line. The numerator of the fraction will be how many y-coordinates the line will ascend or descend (depending on the sign). The denominator will signify how many x-coordinates the line will move to the left or the right.
The y-intercept is the coordinate at which the line crosses the y-axis. The value of x is 0 and the coordinate can be positive or negative.
Therefore, by looking at our equation, we can see that is the slope, and 4 is the y-intercept.
(17x - 8)
For given question, x = 4
"It is a triangle with all three sides of equal length and each angle measures 60°."
"It is a statement which consists of equal symbol between two mathematical expressions."
From given figure,
we can observe that the all sides of the triangle are equal.
This means, the given triangle is an equilateral triangle.
So, each angle of triangle measures 60°.
So, we get an equation,
⇒ 17x - 8 = 60°
⇒ 17x = 60 + 8
⇒ 17x = 68
⇒ x = 68/17
⇒ x = 4
Learn more about an equilateral triangle here:
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Answer:x=4
Step-by-step explanation:
This triangle is an equilateral triangle with all angles equal.
Sum of angles in a triangle=180
17x-8+17x-8+17x-8=180
Collect like terms
17x+17x+17x-8-8-8=180
51x-24=180
51x=180+24
51x=204
Divide both sides by 51
51x/51=204/51
x=4
Give the z test statistic and its P-value. What do you conclude about the authorship of the new poems? (Let a = .05.)
Use 2 decimal places for the z-score and 4 for the p-value.
a. What is z?
b.The p-value is greater than?
c.What is the conclusion? A)The sonnets were written by another poet or b) There is not enough evidence to reject the null.
Answer:
We conclude that the sonnets were written by by a certain Elizabethan poet.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 8.9
Sample mean, =10.2
Sample size, n = 6
Alpha, α = 0.05
Population standard deviation, σ = 2.5
First, we design the null and the alternate hypothesis
We use One-tailed z test to perform this hypothesis.
a) Formula:
Putting all the values, we have
Now,
b) We calculate the p value with the help of z-table.
P-value = 0.1003
The p-value is greater than the significance level which is 0.05
c) Since the p-value is greater than the significance level, there is not enough evidence to reject the null hypothesis and accept the null hypothesis.
Thus, we conclude that the sonnets were written by by a certain Elizabethan poet.
The z-score is 1.86 and the p-value is 0.0314. As the p-value is less than the level of significance α (0.05), we reject the null hypothesis and conclude that the new sonnets were likely written by another author.
In this statistical testing scenario for authorship of literary works, we need to find out the z-score or z test statistic and then determine the p-value to check if the new sonnets could be the works of the known Elizabethan poet or not.
For calculating the z score, you use the formula z = (x~ - μ) / (σ / √n) = (10.2 - 8.9) / (2.5/ √6) = 1.86 to two decimal places. The p-value is determined from the standard normal distribution table which for a z-score of 1.86 is 0.0314.
Given that α = 0.05, since the p-value is less than α, we reject the null hypothesis H0 (that the works were by the Elizabethan poet). Therefore, we accept the alternative hypothesis Ha (the sonnets were written by another author).
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Answer:
Step-by-step explanation:
From the information given:
a human brain weighs = 1 kg ; = 1000 grams
Number of cells = 10¹¹ cells
The density of water filled in each cell = 1 g/mL
From above;
the weight of each of the brain cell = total weight of the human brain/the number of cells
the weight of each of the brain cell = 1000/10¹¹
the weight of each of the brain cell = 1 × 10⁻⁸ grams
Now, to calculate the quantity of water in each cell; we have:
= the weight of each brain × density
=
For cube; we know that
1 mL = 1 cm³
Thus:
Recall that; the volume of a cube as well =
where;
x = length of each sides
∴
=
x = 0.0022 cm
Thus, the length of each side of the cell = 0.0022 cm
The surface area of a single cell = x²
The surface area of a single cell = (0.0022 cm)²
The surface area of a single cell = 4.84 × 10⁻⁶ cm²
Therefore, the total surface area of is:
=
=
= 50 m²
If the human brain's cells were cube-shaped and filled with water, each cell would be roughly 21.5 micrometers on a side. If these cells were spread out into a single-cell-thick layer, the total surface area for one side of the layer would be approximately 4.63 square meters.
To answer your question, the human brain has about 1011 cells, each filled with water. Given the total mass of the brain (about 1 kg) and the number of cells, we can calculate the volume of a single cell. The density of water is 1 g/mL or 1,000 kg/m³, so the volume of all the cells (entire brain) is 1 m³. Therefore, the volume of a single cell must be 1 m³/1011 cells, which is approximately 10-14 m³. For a cubical cell, the side length of the cube (a) would be the cube root of this volume, which is approximately 2.15 x 10-5 m or 21.5 micrometers.
To calculate the total surface area for one side of the cell layer, we multiply the area of a single cell by the total number of cells: (2.15 x 10-5)² m²/cell x 1011 cells = approximately 4.63 m².
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Answer:
$183.7125
Step-by-step explanation:
Given,
Original investment, A = $ 5,175.00
In first year,
Thetotal investment = $ 5,175.00
The amount is increased by 9 %,
Thus, the final amount at the end of first year,
In Second year,
The total investment = $ 5640.75,
The amount is decreased by 5 %,
Thus, the final amount at the end of second year,
Hence,