Why do you think there might not be enough fresh water in the future?

Answers

Answer 1
Answer:

Answer:

hmhmhmhm

Explanation:


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When salt dissolves in water, which is the solvent

Answers

a solvent is what is doing the dissolving. so in this case the water would be your solvent because it is dissolving the salt. does that make sense?

What causes some materials to have magnetic fields?

Answers

Magnetic fields in certain materials (most commonly metals) are created due to moving electrons within these materials, which create an electric current.The distribution of electrons in these metals is uneven, resulting in an irregular rotation and lots of movement that then creates two magnetic poles (a north and south pole). When these poles align and face the same direction, they create a magnetic field.

Final answer:

Magnetic fields in materials are due to the alignment of magnetic dipoles within their atoms. Ferromagnetic materials, like iron, have magnetic domains where magnetic dipoles are rigidly aligned, allowing these materials to become magnets. Diamagnetic materials, on the other hand, only display magnetic fields when an external magnetic field is applied.

Explanation:

Magnetic fields in materials are caused by the alignment of magnetic dipoles within the atoms of the materials. In the case of ferromagnetic materials like iron, cobalt, nickel, and gadolinium, tiny regions called magnetic domains contain magnetic dipoles rigidly aligned in the same direction. The coupling among these atoms is so strong that even thermal agitation cannot break it, creating a net dipole moment for the entire domain. For this reason, ferromagnetic materials can be induced to become magnetic or made into permanent magnets.

On the other hand, diamagnetic materials have no permanent magnetic dipole moments. When a magnetic field is applied to these materials, it induces a magnetic dipole in an atom which points opposite to the applied field. This induced dipole thus produces a magnetic field that is also directed opposite to the applied field.

Lastly, all matter has a property called a magnetic dipole moment. A magnetic field can be caused by a magnet, a moving electrically charged object or by magnetic dipoles or combinations of dipoles. However, magnetic fields observed in nature are not produced by single poles.

Learn more about Magnetic Fields here:

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What volume is equivalent to 12.0 m3?

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i think 12000 is the answer

According to ale Chateliers principle what a change is introduced into a system in chemical equilibrium the equilibrium shifts

Answers

Your answer is C in the direction that relieves the change

That is the definition of Le chatelierts principle.


HOPE THIS HELPS

What is responsible for the changes that we see in the Moons shape

Answers

As the moon like orbits earth,it changes phases in an orderly way.

3. For the following reaction, calculate how many grams of each product are formed when 4.05 gof water is used.
2 H2O → 2 H2 + O2

Answers

Answer:

\large \boxed{\text{0.453 g of H$_(2)$; 3.60 g of O$_(2)$}}

Explanation:

We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

MM:                    2.016    32.00

            2H₂O ⟶ 2H₂   +   O₂

m/g:      4.05

1. Mass of hydrogen

(a) Moles of H₂O

\text{Moles of H$_(2)$O} = \text{4.05 g H$_(2)$O}* \frac{\text{1 mol H$_(2)$O}}{\text{18.02 g H$_(2)$O }}= \text{0.2248 mol H$_(2)$O}

(b) Moles of H₂

\text{Moles of H$_(2)$} = \text{0.2248 mol H$_(2)$O } * \frac{\text{2 mol H$_(2)$}}{\text{2 mol H$_(2)$O }} = \text{0.2248 mol H$_(2)$}

(c) Mass of H₂

\text{Mass of H$_(2)$} =\text{0.2248 mol H$_(2)$} * \frac{\text{2.016 g H$_(2)$}}{\text{1 mol H$_(2)$}} = \textbf{0.453 g H$_(2)$}\n\n\text{The reaction produces $\large \boxed{\textbf{0.453 g}}$ of H$_(2)$}

2. Mass of oxygen

(a) Moles of O₂

\text{Moles of O$_(2)$} = \text{0.2248 mol H$_(2)$O } * \frac{\text{1 mol O$_(2)$}}{\text{2 mol H$_(2)$O}} = \text{0.1124 mol O$_(2)$}

(b) Mass of O₂

\text{Mass of O$_(2)$} =\text{0.1124 mol O$_(2)$} * \frac{\text{32.00 g O$_(2)$}}{\text{1 mol O$_(2)$}} = \textbf{3.60 g O$_(2)$}\n\n\text{The reaction produces $\large \boxed{\textbf{0.453 g of H$_(2)$ and 3.60 g of O$_(2)$}}$}