MATHEMATICS HIGH SCHOOL

What is P(tails ) P(tails)start text, P, left parenthesis, t, a, i, l, s, end text, right parenthesis? If necessary, round your answer to 2 22 decimal places.

Answers

Answer 1

Answer:

Question is not clear enough

I'll assume the question is this:

A fair coin has 2 sides (heads and tails) that are equally likely to show when the coin is flipped. What is P(tails)?

Answer:

P(tails) = 0.5

Step-by-step explanation:

Given:

Number of sides = 2

Number of head = 1

Number of tails = 1

Let P(Tail) = Probability of obtaining a tail when the coin is flipped.

P(Tails) is calculated as follows;

P(Tails) = Number of Tails/Total Number of Sides

Substitute in the values of Number of Tails and Total Number of Sides

P(Tails) = 1/2

P(Tails) = ½

P(Tails) = 0.5

Hence, the probability of obtaining a tail provided that the two sides of the coin are equally likely to show when the coin is flipped is 0.5

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If grade point average rises as number of hours watching tv falls, the correlation between GPA and TV is

Answers

If the grade point average (GPA) rises as the number of hours spent watching TV falls, the correlation between GPA and TV is likely negative or inversely correlated. This means that as one variable (TV watching) decreases, the other variable (GPA) tends to increase. Negative correlation is represented by a negative correlation coefficient, typically ranging from -1 (perfect negative correlation) to 0 (no correlation). In this case, the correlation coefficient would be less than 0 but greater than -1.

PLSSSSSSSSSSS HEEEEEELP????The mean of a set of normally distributed data is 600 with a standard deviation of 20. What percent of the data is between 580 and 620?

Answers

Answer:

The percentage of the data between 580 and 620 is 68.26 %

Step-by-step explanation:

Given,

Mean, $\mu$ = 600,

Standard deviation, $\sigma$ = 20,

Using the equation,

$z-score=(x-\mu)/(\sigma)$

Z-score for the data 580 = $(580-600)/(20)$

$=(-20)/(20)$

$=-1$

While, the z-score for the data 620 = $(620-600)/(20)$

$=(20)/(20)$

$=1$

Using normal distribution table,

P(580 < z) = 0.1587

Also, P(620 > z) = 0.8413

Hence, the percent of the data is between 580 and 620 = P(620 > z) - P(580 < z)

= 0.8413 - 0.1587

= 0.6826

= 68.26 %

z = (X-Mean)/SD
z1 = (580-600)/20 = - 1
z2 = (620-600)/20 = + 1
According to the Empirical Rule 68-95-99.7
Mean +/- 1*SD covers 68% of the values
Therefore, required percent is 68%
hopes this help :) :D :)

1 7/3 in simplest form

Answers

It is already in simplest form, since 17 is a prime number.

Ramona is counting the posts between mile markers on the highway. In 1 mile, she counts 33 posts if the posts are evenly spaced, how many feet apart are they?(1 mile = 5,280 feet)
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