Answer:
B
Step-by-step explanation:
x-intercepts:
factor the function
f(x)=(x+3)(x+1)
zeros at x=-3,-1
x-intercepts --> (-3,0),(-1,0)
y-intercepts:
set x=0 in f(x)
f(0)=(0)^2+4(0)+3=3
y-intercept --> (0,3)
find minimums and maximums
The max or min of a quadratic function occurs at x=-b/(2a). If a is negative, the max value of the function is f(-b/(2a)). if a is positive, the minimum value of the function is f(-b/(2a)).
f(x)=ax^2+bx+c
f(x)=x^2+4x+3
here a is positive so you are looking for a minimum,
x=-b/(2a)
x=-4/(2*1)
x=-2 ----> plug into f(x), f(-2)=(-2)^2+4(-2)+3=-1
Answer:B
Step-by-step explanation:
Answer:
Your value of x will be 28°
Step-by-step explanation:
First, we'll need to find the length of the two obtuse angles. To do this, you add them together. 124 + 124 = 248°.
Since we know that the entire interior measure of the figure is 360°, you have to subtract 248 from 360 to find out the measure of the two unknown angles together.
The sum of the two unknown angles is 112°.
Now, you have to divide 112 by 4, since both of the angles multiply x by two.
112 divided by 4 is equal to 28.
This means the value of x is equal to 28°
I'll check this just to be sure. First I'll start with the top two angles:
2 x 28 = 56
56 + 56 = 112
Then I'll add it to the bottom two angles:
248 + 112 = 360°