Mean:
50
Median:
44
Mode:
35, 44, 77, 68, 43, 55, 2
Answer:
There's no mode. The median is 44. The mean is 50.
Step-by-step explanation: Mean is 35+44+77+68+43+55+28=350/7=50 You divide by 7 because there are 7 numbers. Median is the middle number. There are no repeated numbers so there's no mode.
-3 ( - 3 v + 4 y - 2 )
4x + 3y + z= -6
x-3y + 2z=0
11x-2y + 3z = - 26
Answer:
y= - 271/71
x=755/71
z =4866/71
Step-by-step explanation:
For resolve a system you multiply an equation of the system or add two of the equation and replace the result in the system
Add the 1st and 2nd, and replace the 2nd
4x + 3y + z= -6 4x + 3y + z= -6 4x + 3y + z= -6
(-4) (x-3y + 2z=0) → -4x +12y -8z =0 → +15y -7z = -6
11x-2y + 3z = - 26 11x-2y + 3z = - 26 11x-2y + 3z = - 26
Add the 2nd and 1st, and replace the 1st
4x + 3y + z= -6 4x + 3y + z= -6 4x + z= -6
(-1/5)( 15y -7z = -6) → -3y -7/5z =6/5 → -3y -7/5z =6/5
11x-2y + 3z = - 26 11x-2y + 3z = - 26 11x-2y + 3z = - 26
Add the1st and 3rd, and replace the 3erd
(-3)( 4x + z= -6) -12x - 3z= 18 -12x - 3z= 18
-3y -7/5z =6/5 → -3y -7/5z =6/5 → -3y -7/5z =6/5
11x-2y + 3z = - 26 11x-2y + 3z = - 26 -x-2y = - 8
Add the1st and 3rd, and replace the 1st
(1/3)(-12x - 3z= 18 ) -4x - z= 6 -4x - z= 6
(5)(-3y -7/5z =6/5) → -15y - 7z = 6 → -15y - 7z = 6
-x-2y = - 8 (-4)(-x-2y = - 8) 4x + 8y= 32
Add the 1st and 2nd, and replace the 2nd
(-7)(8y - z =38) -56y +7z= 266 -56y +7z= 266
-15y - 7z = 6 → -15y - 7z = 6 → -71y=271 → y= - 271/71
(1/4)(4x + 8y= 12) x+2y=3 x+2y=3
-56y +7z= 266 → -8y + z =38 → z =4866/71
x+2y=3 → x=755/71
Disjunction is OR, written like a right side up ∨. The upside down V is conjunction, AND, written ∧.
Let's make the disjunction truth table.
A B A ∨ B
F F F
F T T
T F T
T T T
A or B is true when either A is true or B is true or both. It's false when they're both false. That's called inclusive OR.
Answer: C
Interestingly, in the original algebra created by Boole, he preferred exclusive OR, written A^B. A^B is false when both A and B are true, but otherwise like inclusive OR. When we do it this way, exclusive OR is like addition mod 2 and AND is multiplication mod 2, so the algebra of Boole was more like regular algebra than what we call Boolean algebra today.
A: 9
B: 8
C: 11
D: 6
As the
To find the value of g(3) we have to put the value of equal to 3 everywhere in g()
Therefore
on solving the equation
Hence g(3) =11 is the answer
Hope this will help