The required gradient of the line between the points (-8,6) and (-10,14) is -4.
The slope of the line is a tangent angle made by line with horizontal. i.e. m =tanx where x in degrees.
Here,
The gradient of the line segment between points (-8,6) and (-10,14) is given as,
The gradient of the line = slope of the line,
m = (y₂ - y₁) / (x₂ - x₁)
Substitute the value in the above equation,
m = 14- 6 / -10 + 8
m = 8 / -2
m = -4
Thus, the required gradient of the line between the points (-8,6) and (-10,14) is -4.
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Answer:
-4
Step-by-step explanation:
14 - 6 = 8
-10 - - 8 = - 2
8 / - 2 = - 4
far as Lia. Which equation can be used to
find m, the number of miles Lia walked?
Am= 4 x 20
B20 = 4 x m
C20 = m = 4
Dm = 20 + 4
Answer:
The relation for the distance cover by Tina and Lia is 20 = 4 × m
Option B
Step-by-step explanation
Given as :
The distance cover by Tina = = 20 miles
The distance cover by Lia = = m miles
According to question
Tina walked 4 times as far as Lia
So, The distance cover by Tina = 4 × The distance cover by Lia
Or, = 4 ×
I.e 20 miles = 4 × m miles
or. 20 = 4 × m
So, relation is 20 = 4 × m
Hence, The relation for the distance cover by Tina and Lia is 20 = 4 × m
I.e option B Answer
Answer:
4x² + 20x - 2
Step-by-step explanation:
To evaluate (c ○ d)(x), substitute x = d(x) into c(x)
c(x² + 5x)
= 4(x² + 5x) - 2
= 4x² + 20x - 2
we are given
firstly, we will simplify left side
and then we can compare it with right side
so, we can distribute
we have i on both sides
so,i will get cancelled
we can also write as
now, we can compare
and we get
now, we can solve for p and q
we get
.............Answer
Answer:
For short the answer is A. p = 3 , q = 7