Answer:
Explanation:
mole fraction of propane after passing through the separator is
mole fractions of ethane and methane
after passing through separator are:
Change in partial pressures then can be written as:
where
and
are mole fractions after and before passing through the separator
Hence,
Answer:
Isobaric process
Explanation:
The process in which the system pressure remain constant is called is called isobaric process. The word "iso"means same and baric means pressure.
At constant pressure, the work done is given by :
Where
W is the work done by the system
p is the constant pressure
is the change in volume
So, the correct option is (c) " isobaric process ".
Answer:
Too many question marks
Explanation:
Answer:
a)Q=131.1 MJ
b)Q=54 MJ
Explanation:
Given that
Mass ,m=200 kg
Specific heat Cp=0.46 J/g°C
Cp=0.46 KJ/kg°C
Heat of fusion = 270 J/g
Heat of fusion = 270 KJ/kg
Melting point temperature = 1450°C
a)
Initial temperature = 25°C
Final temperature=1450°C
Heat required to rise temperature from 25°C to 1450°C.
Q= m CpΔT
Q=200 x 0.46 x (1450-25) KJ
Q=131,100 KJ
Q=131.1 MJ
b)
Heat required to transform from solid phase to liquid phase
Q= Mass x heat of fusion
Q=200 x 27 KJ
Q=54,000 KJ
Q=54 MJ
True
False
Answer: true
Explanation:
Answer:
V₂=1.76 m³
P=222.03 KPa
Explanation:
Given that
For tank 1
V₁=1 m³
T₁= 10°C = 283 K
P₁=350 KPa
For tank 2
m₂=3 kg
T₂=35°C = 308 K
P₂=150 KPa
We know that for air
P V = m R T
P=pressure ,V= Volume,R= gas constant ,T= temperature ,m =mass
for tank 2
P₂ V₂ = m₂ R T₂
By putting the values
150 x V₂ = 3 x 0.287 x 308
V₂=1.76 m³
Final mass = m₁+m₂
m =m₁+m₂
The final volume V= V₂+V₁
V= 1.76 + 1 m³
V= 2.76 m³
The final temperature T= 19.5°C
T= 292.5 K
m =m₁+m₂
m =4.3 + 3 = 7.3 kg
Now at final state
P V = m R T
P x 2.76 = 7.3 x 0.287 x 292.5
P=222.03 KPa
Answer:
891.027 lbm/ft³
Explanation:
See it in the pic