The growth of the bacteria is represented by the exponential growth equation. Given the initial population, the four-fold increase, and the time interval for the increase, we can find the population after any given time by using the equation P = 200 * 4^(t/2.5).
The problem given is an example of an exponential growth problem. For these types of problems, we use the formula P = P0 * e^(kt), where P is the final population, P0 is the initial population, k is the growth rate, and t is time. However, in this case, we were given that the bacteria quadruples, meaning 'quadrupling' is not a continuous rate, so we use a slightly different form of the equation: P = P0 * (b)^(t/t0), where b is the times increase and t0 is the time interval for the b-fold increase.
Given that the initial population P0 is 200 bacteria, b is 4 because the population quadruples every 150 minutes, and time t0 is 150 minutes or 2.5 hours. We need to find the population P after t hours. Substituting these values into our equation gives us: P = 200 * 4^(t/2.5).
So, after t hours, the population of the bacteria will be given by the equation P = 200 * 4^(t/2.5).
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5/12 x 4/5
Answer:
68
Step-by-step explanation:
you have to add to 180 and 68+112=180
To find the value of x in the polygon, you need more information such as one of the interior angles or the total sum of the interior angles.
To find the value of x in this polygon, you need to use the fact that the sum of all interior angles in a polygon is given by the formula (n-2) * 180 degrees, where n is the number of sides. In this case, since it is not mentioned what polygon it is, we will assume it is a regular polygon. If the polygon is regular and has x sides, then the sum of all interior angles is also (x-2) * 180 degrees. To find the value of x, you would need more information, such as one of the interior angles or the total sum of the interior angles.
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Answer:
equation
Step-by-step explanation:
Answer:
24 and 48
Step-by-step explanation:
Let's let the two numbers be a and b.
Their sum is 72. So:
One number (let's use a) is two times another (b). In other words:
We have a system of equations. We can solve by substituting the second equation into the first. So:
Combine like terms:
Divide both sides by 3:
So, one of the numbers is 24.
Since their sum is 72, this means that the other number is 72-24 or 48.
So, our two numbers is 24 and 48.
And we're done!
B. 44
C. 50
D. 24